A marketing consultant is hired by a major restaurant chain wishing to investigate the preferences and spending patterns of lunch customers. The CEO of the chain hypothesized that the average customer spends at least $13.50 on lunch. A survey of 25 customers sampled at one of the restaurants found the average lunch bill per customer to be $15.50. Based on previous surveys, the restaurant informs the marketing manager that the standard deviation is o = $3.50. To address the CEO's conjecture, the marketing manager carried out a hypothesis test of : u = 13.50 vs. : u > 13.50 and obtained a P-value = 0.002. At a significance level of a = 0.05, this %3D %3! %3D %3D result:

A marketing consultant is hired by a major restaurant chain wishing to investigate the preferences and spending patterns of lunch customers. The CEO of the chain hypothesized that the average customer spends at least $13.50 on lunch. A survey of 25 customers sampled at one of the restaurants found the average lunch bill per customer to be $15.50. Based on previous surveys, the restaurant informs the marketing manager that the standard deviation is o = $3.50. To address the CEO's conjecture, the marketing manager carried out a hypothesis test of : u = 13.50 vs. : u > 13.50 and obtained a P-value = 0.002. At a significance level of a = 0.05, this %3D %3! %3D %3D result:

Name: A marketing consultant is hired by a major restaurant chain wishing t
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: A marketing consultant is hired by a major restaurant chain wishing to investigate thepreferences and spending patterns of lunch customers. The CEO of the chainhypothesized that the average customer spends at least $13.50 on lunch. A survey of25 cus

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

If the weekly grocery expenditure of households in a certain urban market is known to be normally distributed with a mean of $150 and a standard deviation of $30, what proportion of the households spend between $110 and $160 per week on groceries?
A marketing consultant is hired by a major restaurant chain wishing to investigate the preferences and spending patterns of lunch customers. The CEO of the chain hypothesized that the average customer spends at least $13.50 on lunch. A survey of 25 customers sampled at one of the restaurants found the average lunch bill per customer to be = $14.50. Based on previous surveys, the restaurant informs the marketing manager that the standard deviation is o = $3.50. To address the CEO's conjecture, the marketing manager decides to carry out a test of hypothesis. The null hypothesis should be: O a. Ho: µ = 13.50. %3D O b. Ho: µ = 14.50. O c. Ho: µ < 13.50. O d. Ho: µ s 14.50.
The average chef at a restaurant earns $17 an hour with a deviation of $1.75. What are the chances that someone is earning more than $20 an hour?
Is it worth pursuing a doctoral degree in education if you already have an undergraduate degree? One way to help make this decision is to look at the mean incomes of these two groups. Suppose that 1212 people with bachelor’s degrees in education were surveyed. Their mean annual salary was $42,000$⁢42,000 with a standard deviation of $9800$⁢9800. Fifteen people with doctoral degrees in education were found to have a mean annual salary of $50,000$⁢50,000 with a standard deviation of $9200$⁢9200. Assume that the population variances are not the same. Construct a 90%90% confidence interval to estimate the true difference between the mean salaries for people with doctoral degrees and undergraduate degrees in education. Let Population 1 be the salaries for people with doctoral degrees and Population 2 be the salaries for people with undergraduate degrees. Round the endpoints of the interval to the nearest whole number, if necessary.
The Jimmy John’s store manager on Hwy. 46 wanted to know more about their customers. She decides to focus on two variables: the average ticket spent by customers, and whether customers would consider purchasing ice cream if it was available. She interviewed 54 customers over a two-week period. Results of her research showed average ticket was $10.89 with a standard deviation of $2.35. Twenty-two customers said they would purchase ice cream if it was available. INCLUDE EXCEL EQUATIONS. Assume the store manager wants to conduct a similar survey at the National Road store. Answer the following questions: c. What sample size is needed to have 95% confidence of estimating the population average ticket in this store to within plus/minus $1.00 if the standard deviation is assumed to be $2.35? d. How many customers need to be selected to have 90% confidence of estimating the population proportion who would consider purchasing ice cream plus/minus 0.10 (10%)?
Janet is planning to rent a booth at a festival for a day to sell clothes that she has made. She sells jackets for $204 and skirts for $165. Her past experiences suggests that sales of jackets will have a mean of 7.6 with a standard deviation of 1.9, and sales of skirts will have a mean of 11.3 with a standard deviation of 2.7. The cost of renting the booth for the day is $232. What are the mean and standard deviation of her net income? [Hint: you should first define random variables and use them to express her net income] O A. u= $3182.9, o = $3414.9 O B. µ= $3414.9, o = $590.51 O C. u= $3182.9, o = $590.51 Q D. p= $3182.9, o = $44.04 O E. p= $3414.9, o = $44.04
Airline Fares. The mean airfare for flights departing from Buffalo Niagara International Airport during the first three months of 2017 was $320.51. Assume the standard deviation for this population of fares is known to be $80. Suppose a random sample of 60 flights departing from Buffalo Niagara International Airport during the first three months of 2018 is taken. If the mean and standard deviation of the population of airfares for flights departing from Buffalo Niagara International Airport didn’t changed between the first three months of 2017 and the first three months of 2018, what is the probability the sample mean will be within $20 of the population mean cost per flight? What is the probability the sample mean will be within $10 of the population mean cost per flight?
Suppose that the average gregariousness score for the entire U.S. population is 70. The head research psychologist at Somerville University is interested in determining whether or not the university psychology students are statistically significantly more gregarious than the overall population. A random sample of 200 students from Somerville University shows a mean of 75 on the gregarious test with a sample standard deviation of 20. a. State the research hypothesis. b. State the null hypothesis. c. Identify the test statistic and provide the formula.
According to the U.S. Census, the average adult woman is the United States is 65 inches tall and the standard deviation is 3 inches. If Zsike is 67 inches tall, what is her z-score?
According to a health foundation survey from 2018 and 2016, the average annual premiums for employer-sponsored health insurance for family coverage was $16,834 in 2018 and $15,745 in 2016. Suppose the survey for 2018, was based on 250 employees who had employer-sponsored health insurance and the survey for 2016 was based on 200 employees who had employer-sponsored health insurance. Assume the population standard deviation for 2018 and 2016 were $2160 and $1990; respectively. Find a 97% confidence interval for the mean difference. (Round your answer to 1 decimal place.)Lower limit = Upper limit =
The average McDonald's restaurant generates $3.6 million in sales each year with a standard deviation of 0.9. Trent wants to know if the average sales generated by McDonald's restaurants in Kentucky is different than the worldwide average. He surveys 27 restaurants in Kentucky and finds the following data (in millions of dollars): 4.1, 2.8, 4.4, 4.5, 5.3, 5, 3.7, 2.9, 3.8, 4.8, 3.6, 2.3, 3.7, 2.9, 2.9, 4, 1.1, 5.2, 2.9, 5, 4, 4, 5.9, 3.2, 2.2, 4.3, 3.8 Perform a hypothesis test using a 3% level of significance. Step 1: State the null and alternative hypotheses. Ho: [? v] ? v На: ? ? v (So we will be performing a Select an answer test.) Step 2: Assuming the null hypothesis is true, determine the features of the distribution of point estimates using the Central Limit Theorem. By the Central Limit Theorem, we know that the point estimates are Select an answer v with distribution mean and distribution standard deviation Step 3: Find the p-value of the point estimate. P( ? v ? v = P( ? ♥ ?…
The average McDonald's restaurant generates $2.4 million in sales each year with a standard deviation of 0.7. Carissa wants to know if the average sales generated by McDonald's restaurants in New Mexico is different than the worldwide average. She surveys 18 restaurants in New Mexico and finds the following data (in millions of dollars): 2.1, 2, 2.9, 1.7, 1.8, 2.3, 2.1, 2.1, 3.3, 1.4, 1.6, 1.4, 1.4, 2.3, 2.6, 2.7, 2.7, 1.7 Perform a hypothesis test using a 8% level of significance. Step 1: State the null and alternative hypotheses. Ho: pv 2.4 Ha: Ev 2.4 (So we will be performing a two-tailed test.) Step 2: Assuming the null hypothesis is true, determine the features of the distribution of point estimates using the Central Limit Theorem. By the Central Limit Theorem, we know that the point estimates are normally distributed v with and distribution standard deviation distribution mean Step 3: Find the p-value of the point estimate. P(zv [ p-value = Step 4: Make a Conclusion About the…