A marketing consultant is hired by a major restaurant chain wishing to investigate the preferences and spending pat lunch customers. The CEO of the chain hypothesized that the average customer spends at least $13.50 on lunch. A of 25 customers sampled at one of the restaurants found the average lunch bill per customer to be i = $14.50 . Bas previous surveys, the restaurant informs the marketing manager that the standard deviation is o = $3.50 . Lunch bi Normally distributed. To address the CEO's conjecture, the marketing manager carried out a hypothesis test of Họ : µ = 13.50 vs. H. : µ > 13.50. ,the P-value for the hypothesis test equals: Vn Using the test statistic (x – 13.50)/- 0.077.

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A marketing consultant is hired by a major restaurant chain wishing to investigate the preferences and spending patterns of
lunch customers. The CEO of the chain hypothesized that the average customer spends at least $13.50 on lunch. A survey
of 25 customers sampled at one of the restaurants found the average lunch bill per customer to be i = $14.50 . Based on
previous surveys, the restaurant informs the marketing manager that the standard deviation is o = $3.50 . Lunch bills are
Normally distributed. To address the CEO's conjecture, the marketing manager carried out a hypothesis test of
Họ : µ = 13.50 vs. Ha : µ > 13.50.
Using the test statistic (x – 13.50)/–
the P-value for the hypothesis test equals:
0.077.
0.923.
0.144.
0.025.
Transcribed Image Text:A marketing consultant is hired by a major restaurant chain wishing to investigate the preferences and spending patterns of lunch customers. The CEO of the chain hypothesized that the average customer spends at least $13.50 on lunch. A survey of 25 customers sampled at one of the restaurants found the average lunch bill per customer to be i = $14.50 . Based on previous surveys, the restaurant informs the marketing manager that the standard deviation is o = $3.50 . Lunch bills are Normally distributed. To address the CEO's conjecture, the marketing manager carried out a hypothesis test of Họ : µ = 13.50 vs. Ha : µ > 13.50. Using the test statistic (x – 13.50)/– the P-value for the hypothesis test equals: 0.077. 0.923. 0.144. 0.025.
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