A marketing consultant is hired by a major restaurant chain wishing to investigate thepreferences and spending patterns of lunch customers. The CEO of the chainhypothesized that the average customer spends at least $13.50 on lunch. A survey of 25customers sampled at one of the restaurants found the average lunch bill per customerto be $15.50. Based on previous surveys, the restaurant informs the marketingmanager that the standard deviation is a = $3.50. To address the CEO's conjecture, themarketing manager carried out a hypothesis test of: μ = 13.50 vs.: μ> 13.50 andobtained a P-value = 0.002. At a significance level of a = 0.05, this result:a, proves without a doubt that the average lunch bill exceeds $13.50.O b. proves without a doubt that the average lunch bill does not exceed $13.50.O c. provides evidence against the null hypothesis hypothesis in favor of the alternativehypothesis.O d. does not provide evidence against the null hypothesis in favor of the alternative hypothesis.

Given: population mean = 13.50 Sample mean = 15.50 sample size = 25 P-value = 0.002 Significance…

Answered: A marketing consultant is hired by a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The Robotics Manufacturing Company operates an equipment repair business where emergency jobs arrive randomly at the rate of two jobs per 8-hour day. The company's repair facility is a single-server system operated by a repair technician. The service time varies, with a mean repair time of 2.9 hours and a standard deviation of 1.8 hours. The company's cost of the repair operation is $28 per hour. In the economic analysis of the waiting line system, Robotics uses $36 per hour cost for customers waiting during the repair process. (a) What are the arrival rate and service rate in jobs per hour? (Round your answers to four decimal places.) λ = μ = (b) Show the operating characteristics. (Round your answers to four decimal places. Report time in hours.) La L = Wa = = W = Wq Show the total cost per hour. (Express the total cost per hour in dollars. Round your answer to the nearest cent.) TC = $ (c) The company is considering purchasing a computer-based equipment repair system that would…
A marketing consultant is hired by a major restaurant chain wishing to investigate the preferences and spending patterns of lunch customers. The CEO of the chain hypothesized that the average customer spends at least $13.50 on lunch. A survey of 25 customers sampled at one of the restaurants found the average lunch bill per customer to be = $14.50. Based on previous surveys, the restaurant informs the marketing manager that the standard deviation is o = $3.50. To address the CEO's conjecture, the marketing manager decides to carry out a test of hypothesis. The null hypothesis should be: O a. Ho: µ = 13.50. %3D O b. Ho: µ = 14.50. O c. Ho: µ < 13.50. O d. Ho: µ s 14.50.
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A polling organization reported data from a survey of 2000 randomly selected Canadians who carry debit cards. Participants in this survey were asked what they considered the minimum purchase amount for which it would be acceptable to use a debit card. Suppose that the sample mean and standard deviation were $9.14 and $7.70, respectively. (These values are consistent with a histogram of the sample data that appears in the report.)Do these data provide convincing evidence that the mean minimum purchase amount for which Canadians consider the use of a debit card to be appropriate is less than $10? Carry out a hypothesis test with a significance level of 0.01. (Use a statistical computer package to calculate the P-value. Round your test statistic to two decimal places and your P-value to four decimal places.) t = P-value = State your conclusion. Reject H0. We do not have convincing evidence that the mean minimum purchase amount for which Canadians consider it…
Think of your own example of a data set that would follow a normal distribution and explain why.

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