Insurance Company A claims that its customers pay less for car insurance, on average, than customers of its competitor, Company B. You wonder if this is true, so youdecide to compare the average monthly costs of similar insurance policies from the two companies. For a random sample of 13 people who buy insurance from CompanyA, the mean cost is $150 per month with a standard deviation of $19. For 9 randomly selected customers of Company B, you find that they pay a mean of $157 permonth with a standard deviation of $16. Assume that both populations are approximately normal and that the population variances are equal to test Company A's claimat the 0.05 level of significance. Let customers of Company A be Population 1 and let customers of Company B be Population 2.Step 1 of 3: State the null and alternative hypotheses for the test. Fill in the blank below.Ho: M₁ = μ₂Ha:M₁•H₂

The objective of this question is to formulate the null and alternative hypotheses for a statistical…

Answered: Insurance Company A claims that its…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A researcher was interested in comparing the mean grade-point-average (GPA) of students at the University of Toronto Scarborough and Mississauga campuses. Independent random samples of 8 students from the Scarborough campus and 13 students from the Mississauga campus yielded the following GPAs. You can assume the data in each group follow a normal distribution. Do the data provide sufficient evidence to conclude that the mean GPA of students at the Scarborough campus different from the mean GPA of students at the Mississauga campus? A. In Excel, calculate the appropriate test statistic and P-value. Let group 1 be Scarborough and group 2 be Mississauga B.Assuming a 5% significance level, what is the appropriate decision for this test and why? C. Write a one-sentence conclusion statement about the population. What if the data actually weren’t normally distributed and failed the normal population assumption. What statistical test would you conduct instead?
You hypothesize that people in stats classes are happier than people in all other classes. You compare happiness scores in three of your classes: Statistics, Developmental Psychology, and Social Psychology. In Statistics there are 15 students and the mean happiness rating is 23.1 with a standard deviation of 9.78. In Developmental Psychology there are 15 students and the mean happiness rating is 24.4 with a standard deviation of 2.92. In Social Psychology there are 15 students with a mean rating of 17.7 and standard deviation of 8.46. The sum of squares between groups is equal to 384. The sum of squares within groups is equal to 2461. Use the One-Way ANOVA calculation table to help calculate. What is the degrees of freedom within samples?
You are interested in seeing whether emotions impact decision making. You have three groups--a happy group, a sad group, and a neutral group. For the happy group there are 5 participants and the mean risky decision making score 5.0 with a standard deviation of 0.7. For the sad group there are 5 participants and the mean risky decision making score 5.4 with a standard deviation of 1.1. For the neutral group there are 5 participants and the mean risky decision making score 5.8 with a standard deviation of 2.8. The sum of squares between samples is equal to 1.6. The sum of squares within samples is equal to 38.0. What is the degrees of freedom within samples?
You are interested in seeing whether emotions impact decision making. You have three groups--a happy group, a sad group, and a neutral group. For the happy group there are 5 participants and the mean risky decision making score 5.0 with a standard deviation of 0.7. For the sad group there are 5 participants and the mean risky decision making score 5.4 with a standard deviation of 1.1. For the neutral group there are 5 participants and the mean risky decision making score 5.8 with a standard deviation of 2.8. The sum of squares between samples is equal to 1.6. The sum of squares within samples is equal to 38.0. What is the mean square between samples?
Insurance Company A claims that its customers pay less for car insurance, on average, than customers of its competitor, Company B. You wonder if this is true, so you decide to compare the average monthly costs of similar insurance policies from the two companies. For a random sample of 13 people who buy insurance from Company A, the mean cost is $⁢150 per month with a standard deviation of $⁢19. For 9 randomly selected customers of Company B, you find that they pay a mean of $⁢157 per month with a standard deviation of $16. Assume that both populations are approximately normal and that the population variances are equal to test Company A’s claim at the 0.05 level of significance. Let customers of Company A be Population 1 and let customers of Company B be Population 2. Step 2 of 3: Compute the value of the test statistic. Round your answer to three decimal places. Step 3 of 3: Draw a conclusion and interpret the decision.
Insurance Company A claims that its customers pay less for car insurance, on average than customers of its competitor, Company B. You wonder if this is true, so you decide to compare the average monthly costs of similar insurance policies from the two companies. For a random sample of 11 people who buy insurance from Company A, the mean cost is $⁢150 per month with a standard deviation of $⁢14. For 14 randomly selected customers of Company B, you find that they pay a mean of $⁢158 per month with a standard deviation of $⁢12. Assume that both populations are approximately normal and that the population variances are equal to test Company A’s claim at the 0.10 level of significance. Let customers of Company A be Population 1 and let customers of Company B be Population 2. Step 2 of 3 : Compute the value of the test statistic. Round your answer to three decimal places.
You are interested in seeing whether emotions impact decision making. You have three groups--a happy group, a sad group, and a neutral group. For the happy group there are 5 participants and the mean risky decision making score 5.0 with a standard deviation of 0.7. For the sad group there are 5 participants and the mean risky decision making score 5.4 with a standard deviation of 1.1. For the neutral group there are 5 participants and the mean risky decision making score 5.8 with a standard deviation of 2.8. The sum of squares between samples is equal to 1.6. The sum of squares within samples is equal to 38.0. What is the mean square within samples?
Insurance Company A claims that its customers pay less for car insurance, on average, than customers of its competitor, Company B. You wonder if this is true, so you decide to compare the average monthly costs of similar insurance policies from the two companies. For a random sample of 13 people who buy insurance from Company A, the mean cost is $150 per month with a standard deviation of $19. For 9 randomly selected customers of Company B, you find that they pay a mean of $157 per month with a standard deviation of $16. Assume that both populations are approximately normal and that the population variances are equal to test Company A's claim at the 0.05 level of significance. Let customers of Company A be Population 1 and let customers of Company B be Population 2. Step 2 of 3: Compute the value of the test statistic. Round your answer to three decimal places.
4)Listen Provide an appropriate response. When Scholastic Achievement Scores (SAT's) are sent to test-takers, the percentiles associated with their scores are also given. Suppose a test-taker scored at the 54th percentile for their verbal grade and at the 17th percentile for their quantitative grade. Interpret these results. This student performed better than 54% of the other test-takers in the verbal part and better than 83% in the quantitative part. This student performed better than 46% of the other test-takers in the verbal part and better than 83% in the quantitative part. This student performed better than 46% of the other test-takers in the verbal part and better than 17% in the quantitative part. This student performed better than 54% of the other test-takers in the verbal part and better than 17% in the quantitative part. Question 8 (5 points)
Suppose you've just been hired as a statistics professor, but you've never taught undergrads before. While you're doing your best, you're not sure you're fully up to par with all the other excellent statistics professors out there. You decide to look at your 41 students' grades on their midterm exam. They averaged grades of 81 on this exam, with a standard deviation of 10. You reason that if they're higher than normal, you might be making things too easy for them. Likewise, if they're lower than normal, you might be making things too hard. Seeking a Goldilocks effect, you compare this with the national average of statistics midterm exam scores - this is 79. BEING SPECIFIC, what kind of statistical analysis should you perform, and WHY? Three parts of your answer will factor into the grade on this answer: the type of statistical test, one specific aspect of this test (hint- see the earlier questions), and your explanation as to why.
It is known that average house prices today is $371,040 higher compared to 10 years ago and median in the current time also $382,000 higher than house prices 10 years ago. Provide an interpretation of the change of mean and median based on the information above. Compare and contrast these values and comment on the distribution of the increases in house prices.
A researcher was interested in comparing the mean grade-point-average (GPA) of students at the University of Toronto Scarborough and Mississauga campuses. Independent random samples of 8 students from the Scarborough campus and 13 students from the Mississauga campus yielded the following GPAs. You can assume the data in each group follow a normal distribution. Do the data provide sufficient evidence to conclude that the mean GPA of students at the Scarborough campus different from the mean GPA of students at the Mississauga campus? A. What statistical test is most appropriate to answer this question? B. Identify the relevant assumptions and conditions. State how these have or have not been met. C. Write an appropriate null and alternative hypothesis for this question.

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