An article presents a study of health outcomes in women with symptoms of heart disease. In a sample of 110.0 women whose testresults suggested the presence of coronary artery disease, the mean peak systolic blood pressure was 169.9 mmHg, with a standarddeviation of 24.8 mmHg. In a sample of 225.0 women whose test results suggested an absence of coronary artery disease, the meanpeak systolic blood pressure was 163.3 mmHg, with a standard deviation of 25.8 mmHg. Can you conclude that the mean peaksystolic blood pressure differs between these two groups of women? Find the P-value and state a conclusion. (Round the final answerto four decimal places.)The P-value is

Answered: Image /qna-images/answer/39225f15-d801-45b0-aee3-0b3684906d87.jpg

Answered: An article presents a study of health…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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1) A study compared the weight loss of people on a low-fat diet versus people on a low-carb diet. In a sample of 100 obese people on a low-fat diet the sample mean weight loss as 7.6 pounds with a standard deviation of 3.2 pounds. In another sample of 120 obese people on a low-carb diet the sample mean weight loss was 6.7 pounds with a standard deviation of 3.9 pounds. a) Test the hypothesis, at the 5% level of significance, that there is a difference in the mean weight loss of using the 2 different diets. b) What is the p-value?
A student scored 66 on a general science test where the class mean and standard deviation were 82 and 8, respectively; he also scored 53 on a psychology test where the class mean and standard deviation were 58 and 3, respectively. In which class was his relative position higher?
Bone mineral density (BMD) is a measure of bone strength. Studies show that BMD declines after age 45. The impact of exercise may increase BMD. A random sample of 59 women between the ages of 41 and 45 with no major health problems were studied. The women were classified into one of two groups based upon their level of exercise activity: walking women and sedentary women. The 39 women who walked regularly had a mean BMD of 5.96 with a standard deviation of 1.22. The 20 women who are sedentary had a mean BMD of 4.41 with a standard deviation of 1.02. Which of the following inference procedures could be used to estimate the difference in the mean BMD for these two types of women
A report states that the mean yearly salary offer for students graduating with a degree in accounting is $48,722. Suppose that a random sample of 50 accounting graduates at a large university who received job offers resulted in a mean offer of $49,870 and a standard deviation of $3900. Do the sample data provide strong support for the claim that the mean salary offer for accounting graduates of this university is higher than the national average of $48,722? Ho: μ = Ha: (Put in the correct symbol and value) ✓ Select an answer a not = P-value: = ↑ Based on the above we choose to Select an answer Question Help: Post to forum Submit Question
A report about how American college students manage their finances includes data from a survey of college students. Each person in a representative sample of 793 college students was asked if they had one or more credit cards and if so, whether they paid their balance in full each month. There were 500 who paid in full each month. For this sample of 500 students, the sample mean credit card balance was reported to be $825. The sample standard deviation of the credit card balances for these 500 students was not reported, but for purposes of this exercise, suppose that it was $205. Is there convincing evidence that college students who pay their credit card balance in full each month have a mean balance that is lower than $907, the value reported for all college students with credit cards? Carry out a hypothesis test using a significance level of 0.01. State the appropriate null and alternative hypotheses. H0: ? = 907 Ha: ? < 907 H0: ? = 907 Ha: ? > 907 H0: ? < 907…
A newspaper article reports that the mean cost for preventative dental care per year is $175 with a standard deviation of $35 (assume that this is the population standard deviation). You want to test whether the mean cost for preventative dental care in your company is different from what was reported in the article. You take a random sample of 250 employees and find the mean cost is $171. Does this signficantly differ from what was reported in the article? Run the appropriate test at α=0.05. Give each of the following to receive full credit: 1) the appropriate null and alternative hypotheses; 2) the appropriate test; 3) the decision rule; 4) the calculation of the test statistic; and 5) your conclusion including a comparison to alpha or the critical value. You MUST show your work to receive full credit. Partial credit is available.
A pharmaceutical company needs to know if its new cholesterol drug, Praxor, is effective at lowering cholesterol levels. It believes that people who take Praxor will average a greater decrease in cholesterol level than people taking a placebo. After the experiment is complete, the researchers find that the 46 participants in the treatment group lowered their cholesterol levels by a mean of 19.5 points with a standard deviation of 4.9 points. The 37 participants in the control group lowered their cholesterol levels by a mean of 18.4 points with a standard deviation of 4.1 points. Assume that the population variances are not equal and test the company's claim at the 0.02 level. Let the treatment group be Population 1 and let the control group be Population 2. Step 2 of 3: Compute the value of the test statistic. Round your answer to three decimal places.
In a test of the effectiveness of garlic for lowering cholesterol, 36 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of 0.2 and a standard deviation of 1.76. Use a 0.05 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 0. What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and alternative hypotheses?
A college in the northeastern United States used SAT scores to help decide which applicants to admit. To determine whether the SAT was useful in predicting success, the college examined the relationship between the SAT scores and first-year GPAs of admitted students. The average math SAT score of a sample of 200 randomly selected students was 649.5 with a standard deviation of 66.2. The average GPA of the same students was 2.63 with a standard deviation of 0.58. The correlation between GPA and math SAT score was 0.19. (a) What does the correlation of 0.19 tell us about SAT scores and GPA scores? (You need to provide two answers.)(b) Find the equation of the least squares regression line.(c) Using the equation, predict the GPA score of a person with a math SAT score of 650.(d) Using the equation, predict the GPA score for a person with a math score of 800.
In a test of the effectiveness of garlic for lowering cholesterol, 64 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of 0.8 and a standard deviation of 2.14. Use a 0.01 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 0. What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.…
A researcher is interested in examining the effect of emotions on those that are convicted of a crime while under the age of 15. She decides to compare the empathy quotient (EQ) scores of those convicted of violent crimes to those convicted of non-violent crimes. A random sample of 35 violent offenders had a mean score of 33.5 and a standard deviation of 3.2, and another sample of 46 non-violent offenders had a mean of 37 and a standard deviation of 3.8. Also, suppose that equal variance cannot be assumed, but the populations are normal. If a higher EQ score indicated increased empathy, construct a 95% confidence interval for the difference in means. What is the critical value? What is the lower bound of the confidence interval? What can she conclude about the difference in empathy between the two groups?

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