what is the critical value?
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A: It is assumed that the population standard deviations (σ1 and σ2) are not equal.
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Q: Researchers from a certain country were interested in how characteristics of the spleen of residents…
A: Given that n1=93, x¯1=11.1, s1=0.9, n2=107, x¯2=9.9, s2=0.8, α=0.01.
Q: Insurance Company A claims that its customers pay less for car insurance, on average, than customers…
A: Company A Sample size, n1=11 Sample mean, x¯1=150 Sample sd, s1=12 Company B Sample size, n2=13…
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A: Normal random variable x follows the distribution with bell shaped curve. The normal distribution is…
Q: An agricultural company is trying to decide which type of fertilizer to use on its crops. The…
A: Formula : Test statistic
Q: Pilots who cannot maintain regular sleep hours due to their work schedule often suffer from…
A: Answer Sample size [n] =28Standard deviation =1.7Variance [1.7]^2 =2.89
Q: The marketing manager of a firm that produces laundry products decides to test market a new laundry…
A: For region :For region : and Assume that both the populations are normally distributed and has the…
Q: Brew sells a wide variety of outdoor equipment and clothing. The company sells both through mail…
A: Given:n1 = 11 = 67.50s1 = 23.75n2 = 7 = 81.60s2 = 23.25Formula Used:
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A: Given data,n1=40x1=46.6σ1=4.6n2=45x2=48.8σ2=2.4Compute value of test statistic?
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Q: A new small business wants to know if its current radio advertising is effective. The owners decide…
A: The sample size for no advertising group is 13, sample mean is 23.8 and sample standard deviation is…
Q: Suppose that an independent research company was tasked with testing the validity of complaints…
A: Given The total number of bags collected = 16 = nThe mean weight of 16 bags = 19.471 lbsThe mean…
Q: An agricultural company is trying to decide which type of fertilizer to use on its crops. The…
A:
Q: A new small business wants to know if its current radio advertising is effective. The owners decide…
A: From the provided information,
Q: Suppose that an independent research company was tasked with testing the validity of complaints…
A: The sample mean (M) is 19.483 and the population standard deviation is 0.6.
Q: 1. In the past, patrons of a cinema complex have spent an average of $5.25 for popcorn and other…
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Q: A new small business wants to know if its current radio advertising is effective. The owners decide…
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A: Given that Sample size n =24 Sample mean =24970 Sample standard deviation =2300
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Q: K.Brew sells a wide variety of outdoor equipment and clothing. The company sells both through mail…
A: Given:n1 = 18 = 81.30s1 = 16.25n2 = 9 = 67s2 = 15.25Formula Used:
Q: A report states that the mean yearly salary offer for students graduating with mathematics and…
A: According to the given information in this question, we need to answer all the parts
Q: Researchers from a certain country were interested in how characteristics of the spleen of residents…
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Q: Test the claim at the 0.05 level of significance. Let recent graduates with a master's degree be…
A:
Q: A technician compares repair costs for two types of microwave ovens (type I and type II). He…
A:
11) In a sample of 41 business trips taken by employees in the HR department, a company finds that the average amount spent for the trips was $1544 with a standard deviation of $413. In a sample of 101 trips taken by the employees in the sales department is $1725 with a standard deviation of $677. When testing the hypothesis (at the 10% level of significance) that the variance of the amount spent on trips taken by the sales department is higher than those taken by the HR department what is the critical value?
*please round your answer to 2 decimal places*
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- 1) A study compared the weight loss of people on a low-fat diet versus people on a low-carb diet. In a sample of 100 obese people on a low-fat diet the sample mean weight loss as 7.6 pounds with a standard deviation of 3.2 pounds. In another sample of 120 obese people on a low-carb diet the sample mean weight loss was 6.7 pounds with a standard deviation of 3.9 pounds. a) Test the hypothesis, at the 5% level of significance, that there is a difference in the mean weight loss of using the 2 different diets. b) What is the p-value?According to Management Accounting, salary figures for certified management accountants (CMAs) who are in the field less than 1 year are normally distributed with a mean of $31,129. A random sample of 15 firstyear CMAs in Denver produces a mean salary of $32,279, with a standard deviation of $1,797. Test the hypothesis that the mean for all Denver firstyear CMAs is not equal to $31,129. Use the .05 level of significance. 1. State the null hypothesis and alternative hypothesis 2.What is the test statistic used for the test (z or t) and it’s critical value (round to 2 places) 3. Determine the p-value. And do you or do you not reject the null hypothesis?A cell phone company offers contract phones and non-contract phones. In a sample of 40 contract subscribers, the mean yearly income was found to be $57,000 with a standard deviation of $9,200. In a sample of 30 non-contract phones, the mean yearly income was found to be $53,000 with a standard deviation of $7,100. At the 1% significance level, is there evidence that the mean annual income level between the two groups is the same? Include a p-value with your test.
- An industrial plant wants to determine which of two types of fuel, electric or gas, is more cost efficient (measured in cost per unit of energy). Independent random samples were taken of plants using electricity and plants using gas. These samples consisted of 7 plants using electricity, which had a mean cost per unit of $36.41 and standard deviation of $8.53, and 13 plants using gas, which had a mean of $46.50 and standard deviation of $8.60. Assume that the populations of costs per unit are normally distributed for each type of fuel, and assume that the variances of these populations are equal. Can we conclude, at the 0.10 level of significance, that u, the mean cost per unit for plants using electricity, differs from H,, the mean cost per unit for plants using gas? Perform a two-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places and round your answers as specified in the table. (If necessary, consult a list of formulas.)…Fran is training for her first marathon, and she wants to know if there is a significant difference between the mean number of miles run each week by group runners and individual runners who are training for marathons. She interviews 42 randomly selected people who train in groups and finds that they run a mean of 47.1 miles per week. Assume that the population standard deviation for group runners is known to be 4.4 miles per week. She also interviews a random sample of 47 people who train on their own and finds that they run a mean of 48.5 miles per week. Assume that the population standard deviation for people who run by themselves is 1.8 miles per week. Test the claim at the 0.01 level of significance. Let group runners training for marathons be Population 1 and let individual runners training for marathons be Population 2. Step 2 of 3 : Compute the value of the test statistic. Round your answer to two decimal places.Pilots who cannot maintain regular sleep hours due to their work schedule often suffer from insomnia. A recent study on sleeping patterns of pilots focused on quantifying deviations from regular sleep hours. A random sample of 28 commercial airline pilots was interviewed, and the pilots in the sample reported the time at which they went to sleep on their most recent working day. The study gave the sample mean and standard deviation of the times reported by pilots, with these times measured in hours after midnight. (Thus, if the pilot reported going to sleep at p.m., the measurement was -1.) The sample mean was 0.8 hours, and the standard deviation was 1.6 hours. Assume that the sample is drawn from a normally distributed population. Find a 90% confidence interval for the population standard deviation, that is, the standard deviation of the time (hours after midnight) at which pilots go to sleep on their work days. Then give its lower limit and upper limit.
- The Chartered Financial Analyst (CFA) designation is fast becoming a requirement for serious investment professionals. It is an attractive alternative to getting an MBA for students wanting a career in investment. A student of finance is curious to know if a CFA designation is a more lucrative option than an MBA. He collects data on 38 recent CFAs with a mean salary of $138,000 and a standard deviation of $34,000. A sample of 80 MBAs results in a mean salary of $130,000 with a standard deviation of $46,000.a) Specify the hypotheses to test whether a CFA designation is more lucrative than an MBA.b) Calculate the value of the test statistic and the p-value. Do not assume that the population variances are equal.c) At the 5% significance level, is a CFA designation more lucrative than an MBA?The Chartered Financial Analyst (CFA) designation is fast becoming a requirement for serious investment professionals. It is an attractive alternative to getting an MBA for students wanting a career in investment. A student of finance is curious to know if a CFA designation is a more lucrative option than an MBA. He collects data on 36 recent CFAS with a mean salary of $145,000 and a standard deviation of $36,000. A sample of 47 MBAS results in a mean salary of $135,000 with a standard deviation of $24,000. Assume that H, is the population mean for individuals with a CFA designation and u, is the population mean of individuals with MBAS. (You may find it useful to reference the appropriate table: z table or t table) a. Set up the hypotheses to test if a CFA designation is more lucrative than an MBA at the 10% significance level. O Họ: 41- H2 = 0; HA: H1 - H2# 0 O Ho: 1-4220; HA H1 - 4200 b-1. Calculate the value of the test statistic. Do not assume that the population variances are…10
- A new small business wants to know if its current radio advertising is effective. The owners decide to look at the mean number of customers who make a purchase in the store on days immediately following days when the radio ads are played as compared to the mean for those days following days when no radio advertisements are played. They found that for 13 days following no advertisements, the mean was 23.9 purchasing customers with a standard deviation of 1.9 customers. On 6 days following advertising, the mean was 24.7 purchasing customers with a standard deviation of 1.6 customers. Test the claim, at the 0.01 level, that the mean number of customers who make a purchase in the store is lower for days following no advertising compared to days following advertising. Assume that both populations are approximately normal and that the population variances are equal. Let days following no advertisements be Population 1 and let days following advertising be Population 2. Step 3 of 3: Draw a…A technician compares repair costs for two types of microwave ovens (type I and type II). He believes that the repair cost for type I ovens is greater than the repair cost for type II ovens. A sample of 35 type I ovens has a mean repair cost of $80.39. The population standard deviation for the repair of type I ovens is known to be $24.63. A sample of 31 type II ovens has a mean repair cost of $73.47. The population standard deviation for the repair of type II ovens is known to be $10.42. Conduct a hypothesis test of the technician's claim at the 0.05 level of significance. Let i be the true mean repair cost for type I ovens and µz be the true mean repair cost for type II ovens. Step 1 of 5: State the null and alternative hypotheses for the test.A researcher is interested in examining the effect of emotions on those that are convicted of a crime while under the age of 15. She decides to compare the empathy quotient (EQ) scores of those convicted of violent crimes to those convicted of non-violent crimes. A random sample of 35 violent offenders had a mean score of 33.5 and a standard deviation of 3.2, and another sample of 46 non-violent offenders had a mean of 37 and a standard deviation of 3.8. Also, suppose that equal variance cannot be assumed, but the populations are normal. If a higher EQ score indicated increased empathy, construct a 95% confidence interval for the difference in means. What is the critical value? What is the lower bound of the confidence interval? What can she conclude about the difference in empathy between the two groups?
