A technician compares repair costs for two types of microwave ovens (type I and type II). He believes that the repair cost for type I ovensis greater than the repair cost for type II ovens. A sample of 35 type I ovens has a mean repair cost of $80.39. The population standarddeviation for the repair of type I ovens is known to be $24.63. A sample of 31 type II ovens has a mean repair cost of $73.47. Thepopulation standard deviation for the repair of type II ovens is known to be $10.42. Conduct a hypothesis test of the technician's claim atthe 0.05 level of significance. Let i be the true mean repair cost for type I ovens and µz be the true mean repair cost for type II ovens.Step 1 of 5: State the null and alternative hypotheses for the test.

Name: A technician compares repair costs for two types of microwave ovens (
Uploaded: 2024-03-20T07:07:00.000Z
Channel: Bartleby
Description: A technician compares repair costs for two types of microwave ovens (type I and type II). He believes that the repair cost for type I ovensis greater than the repair cost for type II ovens. A sample of 35 type I ovens has a mean repair cost of $80.3

Solution : Given information: n1= 35 Sample size of type I ovens n2= 31 Sample size of type II ovens…

Math

Statistics

technician compares repair costs for two types of microwave ovens (type I and type II). He believes that the repair cost for type I ovens s greater than the repair cost for type II ovens. A sample of 35 type I ovens has a mean repair cost of $80.39. The population standard deviation for the repair of type I ovens is known to be $24.63. A sample of 31 type Il ovens has a mean repair cost of $73.47. The population standard deviation for the repair of type Il ovens is known to be $10.42. Conduct a hypothesis test of the technician's claim at the 0.05 level of significance. Let u be the true mean repair cost for type I ovens and µ2 be the true mean repair cost for type II ovens. Step 1 of 5: State the null and alternative hypotheses for the test.

technician compares repair costs for two types of microwave ovens (type I and type II). He believes that the repair cost for type I ovens s greater than the repair cost for type II ovens. A sample of 35 type I ovens has a mean repair cost of $80.39. The population standard deviation for the repair of type I ovens is known to be $24.63. A sample of 31 type Il ovens has a mean repair cost of $73.47. The population standard deviation for the repair of type Il ovens is known to be $10.42. Conduct a hypothesis test of the technician's claim at the 0.05 level of significance. Let u be the true mean repair cost for type I ovens and µ2 be the true mean repair cost for type II ovens. Step 1 of 5: State the null and alternative hypotheses for the test.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A certain prescription medicine is supposed to contain an average of 250 parts per million (ppm) of a certain chemical. If the concentration is higher than this, the drug may cause harmful side effects; if it is lower, the drug may be ineffective. The manufacturer runs a check to see if the mean concentration in a large shipment conforms to the target level of 250 ppm or not. A simple random sample of 100 portions is tested, and the sample mean concentration is found to be 247 ppm. The sample concentration standard deviation is s = 12 ppm. Suppose that the p-value was 0.0259. What is the appropriate conclusion to make if α = 0.05? Group of answer choices Fail to reject H0. We have insufficient evidence to conclude that the mean concentration is different from 250 ppm. Fail to reject H0. We have sufficient evidence to conclude that the mean concentration is less than 250 ppm. Reject H0. We have insufficient evidence to conclude that the mean concentration is less than 250…
Insurance Company A claims that its customers pay less for car insurance, on average, than customers of its competitor, Company B. You wonder if this is true, so you decide to compare the average monthly costs of similar insurance policies from the two companies. For a random sample of 13 people who buy insurance from Company A, the mean cost is $150 per month with a standard deviation of $19. For 9 randomly selected customers of Company B, you find that they pay a mean of $157 per month with a standard deviation of $16. Assume that both populations are approximately normal and that the population variances are equal to test Company A's claim at the 0.05 level of significance. Let customers of Company A be Population 1 and let customers of Company B be Population 2. Step 2 of 3: Compute the value of the test statistic. Round your answer to three decimal places.
K.Brew sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet. Random samples of sales receipts were studied for mail order sales and internet sales, with the total purchase being recorded for each sale. A random sample of 18 sales receipts for mail order sales results in a mean sale amount of $81.30 with a standard deviation of $16.25 . A random sample of 9 sales receipts for internet sales results in a mean sale amount of $67.00 with a standard deviation of $15.25 . Using this data, find the 98% confidence interval for the true mean difference between the mean amount of mail order purchases and the mean amount of internet purchases. Assume that the population variances are not equal and that the two populations are normally distributed. Step 2 of 3 : Find the standard error of the sampling distribution to be used in constructing the confidence interval. Round your answer to two decimal places.
Carlos and Devon both accepted new jobs at different companies. Carlos's starting salary is $32,000 and Devon's starting salary is $33,000. They are curious to know who has a better starting salary when compared to the salary distributions of their new employers. A website that collects salary information from a sample of employees for a number of major employers reports that Carlos's company offers a mean salary of $54,000 with a standard deviation of $6,000. Devon's company offers a mean salary of $44,000 with a standard deviation of $4,000. Find the z-scores corresponding to each of their starting salaries. Round to two decimal places, if necessary
A bridal gown shop owner owns a store in San Francisco and a store in Redwood city. She is trying to figure out if clients tend to spend the same amount at both stores. She takes a random sample of 25 purchases from each store, and find the San Francisco store has a mean amount spent of $2500 with a standard deviation of $1500. The Redwood City store has a mean amount spent of $2000 with a standard deviation of $1000. Use a significance level of 10% to determine if the clients at the two stores spend the same amounts. State: Plan: Do: Conclude:
Insurance Company A claims that its customers pay less for car insurance, on average, than customers of its competitor, Company B. You wonder if this is true, so you decide to compare the average monthly costs of similar insurance policies from the two companies. For a random sample of 7 people who buy insurance from Company A, the mean cost is $150 per month with a standard deviation of $16. For 12 randomly selected customers of Company B, you find that they pay a mean of $160 per month with a standard deviation of $14. Assume that both populations are approximately normal and that the population variances are equal to test Company A's claim at the 0.10 level of significance. Let customers of Company A be Population 1 and let customers of Company B be Population 2. Step 2 of 3: Compute the value of the test statistic. Round your answer to three decimal places.
An engineer designed a valve that will regulate water pressure on an automobile engine. The engineer designed the valve such that it would produce a mean pressure of 5.5 pounds/square inch. It is believed that the valve performs above the specifications. The valve was tested on 24 engines and the mean pressure was 5.7 pounds/square inch with a variance of 0.49. A level of significance of 0.01 will be used. Assume the population distribution is approximately normal. Make the decision to reject or fail to reject the null hypothesis. Dain
A new drug is being tested to see if it reduces the frequency of migraines. Study participants were divided into two groups. 49 participants in group 1 received the medication; 42 participants in group 2 received a placebo. After a period of six months, group 1 had a mean of 4 migraines. It is known that the population standard deviation for this group is 1.3 migraines. Group 2 had a mean of 5.4 migraines. The population standard deviation for this group is 1.7 migraines. Can we conclude that the medication reduces the population mean number of migraines? Use αα =0.01. Note: If t-test, then unequal variances are assumed. Question a)Let: μ1μ1 = the population mean number of migraines with the medication μ2μ2 = the population mean number of migraines with the placebo (Step 1) State the null and alternative hypotheses by selecting the appropriate symbol, and identify which tailed test: H0:H0: μ1μ1 μ2μ2 H1:H1: μ1μ1 μ2μ2 Which tailed test…
A certain prescription medicine is supposed to contain an average of 250 parts per million (ppm) of a certain chemical. If the concentration is higher than this, the drug may cause harmful side effects; if it is lower, the drug may be ineffective. The manufacturer runs a check to see if the mean concentration in a large shipment conforms to the target level of 250 ppm or not. A simple random sample of 100 portions is tested, and the sample mean concentration is found to be 247 ppm. The sample concentration standard deviation is s = 12 ppm. What are the appropriate null and alternative hypotheses? Group of answer choices H 0: x̄ = 250 vs. H a: x̄ < 250 H 0: x̄ = 250 vs. H a: x̄ ≠ 250 H 0: x̄ = 250 vs. H a: x̄ > 250 H 0: μ = 250 vs. H a:μ < 250 H 0: μ = 250 vs. H a: μ ≠ 250 H 0: μ = 250 vs. H a: μ > 250
Insurance Company A claims that its customers pay less for car insurance, on average, than customers of its competitor, Company B. You wonder if this is true, so you decide to compare the average monthly costs of similar insurance policies from the two companies. For a random sample of 13 people who buy insurance from Company A, the mean cost is $150 per month with a standard deviation of $19. For 9 randomly selected customers of Company B, you find that they pay a mean of $157 per month with a standard deviation of $16. Assume that both populations are approximately normal and that the population variances are equal to test Company A's claim at the 0.05 level of significance. Let customers of Company A be Population 1 and let customers of Company B be Population 2. Step 1 of 3: State the null and alternative hypotheses for the test. Fill in the blank below. Ho: M₁ = μ₂ Ha:M₁ •H₂
According to the Vivino website, suppose the mean price for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is $32.48. A New England-based lifestyle magazine wants to determine if red wines of the same quality are less expensive in Providence, and it has collected prices for 64 randomly selected red wines of similar quality from wine stores throughout Providence. The mean and standard deviation for this sample are $30.15 and $12, respectively. (a) Develop appropriate hypotheses for a test to determine whether the sample data support the conclusion that the mean price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48. (Enter != for # as needed.) Ho: H: (b) Using the sample from the 64 bottles, what is the test statistic? (Round your answer to three decimal places.) Using the sample from the 64 bottles, what is the p-value? (Round your answer to four decimal places.) p-value =…
A sample of 76 female workers and another sample of 48 male workers from a state produced mean weekly earnings of $743.50 for the females and $777.63 for the males. Suppose that the population standard deviations of the weekly earnings are $80.05 for the females and $88.68 for the males. The null hypothesis is that the mean weekly earnings are the same for females and males, while the alternative hypothesis is that the mean weekly earnings for females is less than the mean weekly earnings for males. Directions: • Label your answers with the correct statistical symbols. • If you use the Ti, identify which function and values you used to calculate. If you solve by hand, show all steps 2.5 The significance level for the test is 1%. What is/are the critical value(s)? 2.6. What is the value of the test statistic, rounded to three decimal places? 2.7. What is the p-value for this test, rounded to four decimal places? 2. 8. Using the p-value approach, do you reject or fail to reject the null…