If a geneticist were to closely examine the make-up of a single aut chromosome from one of your cells, that chromosome would be found to be a mosaic of genes derived from your mother and father. a mosaic of genes derived from just two of your grandparents-either your maternal grandparents or your paternal grandparents. a mosaic of genes derived from all four of your grandparents. a mosaic of genes derived from just two of your grandparents-either your two grandfathers or your two grandmothers. derived entirely from genes from just one of your grandparents.

If a geneticist were to closely examine the make-up of a single aut chromosome from one of your cells, that chromosome would be found to be a mosaic of genes derived from your mother and father. a mosaic of genes derived from just two of your grandparents-either your maternal grandparents or your paternal grandparents. a mosaic of genes derived from all four of your grandparents. a mosaic of genes derived from just two of your grandparents-either your two grandfathers or your two grandmothers. derived entirely from genes from just one of your grandparents.

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Description: If a geneticist were to closely examine the make-up of a single autosomalchromosome from one of your cells, that chromosome would be found to bea mosaic of genes derived from your mother and father.a mosaic of genes derived from just two of your gra

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter15: Genomes And Genomics

Section: Chapter Questions

Problem 2QP: Hemophilia and color blindness are both recessive conditions caused by genes on the X chromosome. To...

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Mitotic recombination can occasionally produce a twin spot.Let’s suppose an animal species is heterozygous for two genesthat govern fur color and length: one gene affects pigmentation,with dark pigmentation (A) dominant to albino (a); the other geneaffects hair length, with long hair (L) dominant to short hair (l).The two genes are linked on the same chromosome. Let’s assume ananimal of this species is AaLl; A is linked to l, and a is linked to L.Draw the chromosomes labeled with these alleles, and explainhow mitotic recombination could produce a twin spot with onespot having albino pigmentation and long fur and the other havingdark pigmentation and short fur.
Examine the two pedigrees shown in Figure Q7–3.One results from deletion of a maternally imprinted auto-somal gene. The other pedigree results from deletion of apaternally imprinted autosomal gene. In both pedigrees,affected individuals (red symbols) are heterozygous forthe deletion. These individuals are affected because onecopy of the chromosome carries an imprinted, inactivegene, while the other carries a deletion of the gene. Dottedyellow symbols indicate individuals that carry the deletedlocus, but do not display the mutant phenotype. Whichpedigree is based on paternal imprinting and which onmaternal imprinting? Explain your answer.
A tomato geneticist attempts to assign five recessivemutations to specific chromosomes by using trisomics.She crosses each homozygous mutant (2n) with each ofthree trisomics, in which chromosomes 1, 7, and 10 takepart. From these crosses, the geneticist selects trisomicprogeny (which are less vigorous) and backcrosses themto the appropriate homozygous recessive. The diploidprogeny from these crosses are examined. Her results, inwhich the ratios are wild type:mutant, are as follows:Which of the mutations can the geneticist assign towhich chromosomes? (Explain your answer fully.)
In Drosophila, a cross (cross 1) was made between twomutant flies, one homozygous for the recessive mutationbent wing (b) and the other homozygous for the recessivemutation eyeless (e). The mutations e and b are alleles oftwo different genes that are known to be very closelylinked on the tiny autosomal chromosome 4. All the progeny had a wild-type phenotype. One of the female progeny was crossed with a male of genotype b e/b e ; we willcall this cross 2. Most of the progeny of cross 2 were of theexpected types, but there was also one rare female ofwild-type phenotype.a. Explain what the common progeny are expected tobe from cross 2.b. Could the rare wild-type female have arisen by (1)crossing over or (2) nondisjunction? Explain.
Familial retinoblastoma, a rare autosomal dominant defect, arose in a large family that had no prior history of the disease. Consider the following pedigree (the darkly colored symbols represent affected individuals): a. Circle the individual(s) in which the mutation most likely occurred. b. Is the person who is the source of the mutation affected by retinoblastoma? Justify your answer. c. Assuming that the mutant allele is fully penetrant, what is the chance that an affected individual will have an affected child?
Hemophilia and color blindness are both recessive conditions caused by genes on the X chromosome. To calculate the recombination frequency between the two genes, you draw a large number of pedigrees that include grandfathers with both hemophilia and color blindness, their daughters (who presumably have one chromosome with two normal alleles and one chromosome with two mutant alleles), and the daughters sons. Analyzing all the pedigrees together shows that 25 grandsons have both color blindness and hemophilia, 24 have neither of the traits, 1 has color blindness only, and 1 has hemophilia only. How many centimorgans (map units) separate the hemophilia locus from the locus for color blindness?
In a cross in Drosophila, a female heterozygous for the autosomallylinked genes a, b, c, d, and e (abcde/ + + + + +) was testcrossedwith a male homozygous for all recessive alleles (abcde/abcde).Even though the distance between each of the loci was at least3 map units, only four phenotypes were recovered, yielding thefollowing data: Phenotype No. of Flies+ + + + + 440a b c d e 460+ + + + e 48a b c d + 52 Total = 1000 Why are many expected crossover phenotypes missing? Can anyof these loci be mapped from the data given here? If so, determinemap distances.
An animal is heterozygous for two autosomal genetic traits found on different chromosomes. Purple fur is inherited dominantly (with pp genotype giving green fur) and the gene is located near the telomere on the short arm of an acrocentric autosome. The gene for claw sharpness is located closer to the centromere on one arm of a metacentric chromosome. The S+ allele is dominant and results in sharp pointy claws, while the SS genotype gives the animal rounded dull claws. Create and label a diagram showing all possible arrangements of the chromosomes involved in these traits’ inheritance during metaphase 1.
Below is a pedigree from one family (two parents and eight children). Four of the children (indicated by shaded shapes) are affected with a serious disease with an unknown genetic cause. a) For the disease, what pattern of inheritance (autosomal/sex-linked, recessive/dominant) is exhibited by this pedigree? b) Linkage analysis of the disease to a series of VNTR polymorphisms on human chromosome 5 is shown above. Is there evidence for linkage between the disorder and the VNTR? Briefly explain your answer.
10 cM separates two hypothetical autosomal human genes. The dominant alleles are have complete penetrance and will result to Crossed eyes (e+) and short thumbs (th+). Four children are born to a normal guy and cross-eyed, small-thumbed woman. Two of the children have short thumbs and the other two have crossed eyes. She is carrying her fifth child. What is the probability that this fifth child will be cross-eyed and have short thumbs?
A woman who sought genetic counseling is found to be heterozygousfor a chromosomal rearrangement between the second andthird chromosomes. Her chromosomes, compared to those in anormal karyotype, are diagrammed on the next page:(a) This woman is phenotypically normal. Does thissurprise you? Why or why not? Under what circumstancesmight you expect a phenotypic effect of such arearrangement?
In an electrophoretic gel across which is applied a powerful electrical alternating pulsed field, the DNA of thehaploid fungus Neurospora crassa (n = 7) moves slowlybut eventually forms seven bands, which represent DNAfractions that are of different sizes and hence havemoved at different speeds. These bands are presumed tobe the seven chromosomes. How would you show whichband corresponds to which chromosome?