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2. If the bond length of HF is 0.91 Å, and frequency is 1.241*10¹⁴ s^-1how would I find the total energy for n=0,1,2?

n = 4
n = 3
-n =D1
n = 0
X = 0
FIGURE 11.4 Plots of the first five wave-
unctions of the harmonic oscillator. They
re superimposed against the potential
nergy for the system. The positions where
ne wavefunctions go outside the poten-
energy are called the classical turning
oints. Classically, a harmonic oscillator will
ever go beyond its turning point, because
does not have enough energy. Quantum
nechanically, there is a nonzero prob-
pility that a particle acting as a harmonic
scillator will exist beyond this point.
al

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