The ionization energy of potassium is 4.34 eV and the electron affinity of chlorine is 3.61 eV. The Madelung constant for the KCl structure is 1.748 and the distance between ions of opposite sign is 0.314 nm, given that e is 1.602 X 10-19 C. Compute the cohesive energy of KCI per ion pair. A. -1.284 eV B. -3.643 eV C. -7.285 eV D. -8.015 eV

icon
Related questions
Question
QUESTION 12
The ionization energy of potassium is 4.34 eV and the electron affinity of chlorine is 3.61 eV.The
Madelung constant for the KCl structure is 1.748 and the distance between ions of opposite sign is
0.314 nm, given that e is 1.602 X 10-19 C. Compute the cohesive energy of KCI per ion pair.
A. -1.284 eV
B. -3.643 eV
C. -7.285 eV
D. -8.015 eV
Transcribed Image Text:QUESTION 12 The ionization energy of potassium is 4.34 eV and the electron affinity of chlorine is 3.61 eV.The Madelung constant for the KCl structure is 1.748 and the distance between ions of opposite sign is 0.314 nm, given that e is 1.602 X 10-19 C. Compute the cohesive energy of KCI per ion pair. A. -1.284 eV B. -3.643 eV C. -7.285 eV D. -8.015 eV
Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

Blurred answer