How many seconds will it take for Ca2+ and BR- to migrate 35.0 cm in a field of 4750 V/m? The mobilities are 6.12 x 10^-8 m^2/Vs for Ca2+ and 8.13 x 10^-8 m^2/Vs for Br-
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- An analyst wants to find out the active surface of his electrode before conducting his analyzes. To do this, he carried out a series of measurements by cyclic voltammetry (CV) using a 1 mM solution of K4Fe(CN)6 dissolved in 0.1M NaCl. He recorded the anodic peak intensity (ip) corresponding to the oxidation of Fe(II) to Fe(III) as a function of the scanning speed (v) of the CV (see table). What is the active surface of the electrode? Data: Fe diffusion coefficient (CN)64-, D = 6.67x10-6 cm2/s Randles-Sevcik equation ip = (2,69x105)n3/2ACD1/2v1/2 rate (v/s) ip (A) 5,00E-02 5,75E-05 1,00E-01 7,68E-05 2,00E-01 9,94E-05 5,00E-01 1,42E-04 1,00E+00 2,07E-04The equation to calculate for molar absorptivity (ε) is ε = A/(bc) where A is absorbance (unitless), b is path length in cm, and c is concentration in M. Suppose you have a solution with concentration of 2.9 ± 0.25 M, a path length of 1 ± 0.1 cm, and an absorbance of 0.4629 ± 0.0006. What is the uncertainty or error for the molar absorptivity?Zinc is to be used as an internal standard for the polarographic analysis of thallium. A standard solution containing twice the concentration of zinc as Thallium has a diffusion current of 1.89 µA for Ti and 3.50 µA for Zn. A 10.0g alloy was dissolved in 500 mL, 25 mL of this solution was mixed with 25 mL of 1.0 x 10-3 M Zn 2+ solution. The diffusion currents of this final solution are 18.2µA for Tl+ and 14.5µA for Zn+. Calculate % Ti in the sample analysed
- . The conductance of 0.00017 M acetic acid solution is 153 µS when applying a probe with 0.87 cm−1cell constant. The same probe measures 5.7 µS for the conductance of water. Calculate the conductivityand molar conductivity of the solution.6Chloroform is an internal standard in the determination of the pesticide DDT in a polarographic analysis in which each compound is reduced at an electrode surface. A mixture containing 0.500 mM chloroform and 0.800 mM DDT gave signals of 15.3 µA for chloroform and 10.1 µA for DDT. An unknown solution (10.00 mL) containing DDT was placed in a 100-ml volumetric flask and 10.2 µl of chloroform (MW = 119.39, density = 1.484 g/mL) were added. After dilution to the mark with solvent, polarographic signals of 29.4 and 8.7 HA were observed for the chloroform and DDT, respectively. Find the concentration of DDT in the unknown. Dichlorodiphenyltrichloroethane (DDT) ÇI CI
- Chloroform is an internal standard in the determination of the pesticide DDT in a polarographic analysis in which each compound is reduced at an electrode surface. A mixture containing 0.500 mM chloroform and 0.800 mM DDT gave signals of 15.3 µA for chloroform and 10.1 µA for DDT. An unknown solution (10.00 mL) containing DDT was placed in a 100-ml volumetric flask and 10.2 ul of chloroform (MW = 119.39, density = 1.484 g/mL) were added. After dilution to the mark with solvent, polarographic signals of 29.4 and 8.7 µA were observed for the chloroform and DDT, respectively. Find the concentration of DDT in the unknown.The answer is 0.372 ug/mL1 mL was taken from the sample filtrate and mixed with 13 mL pure water and 4 mL sulfomolybdic acid and 2 mL dilute SnCI2 solution by adding it, and after waiting for 15 minutes, the absorbance of the resulting solutions against pure water was read at 520 nm. if the function of the calibration graph obtained with standard phosphorus solutions of 0.5-2.5 mg/mL is y= 0.245x + 0.107 and the absorbance of the serum sample is 0.342, how many grams of phosphorus is the amount in the sample?
- TLC was used to compare the solubility of two compounds A and B in a solvent system (acetic acid, methanol, H2O). The distances that solvent has moved in the silica gel TLC was 12 cm. and for the compounds were 2 and 8 cm respectively. (a) Calculate the Rf values and which compound is more soluble and which one is more polar. (b) What are the factors affecting the Rf value[3] The following Figure is the electrocapillary curves (A) and differential capacitance curves (B) for mercury in contact with 0.5 M Na,SO4 in the presence and absence of n-heptanol . 440- (A) (B) 420 Na,So. 400 Na, So, CHOH 360 Na so, 20 340- Na So, CH,OH 10 320 0.4 0.8 12 1.6 20 24 0.4 0.8 1.2 -EV ex NCE) 1.6 2.0 -EV e NCE (a) How do the curves in figure (A) relate to those in figure (B)? (b) What implications can be derived from the flat region in the electrocapillary curves in the presence of n-heptyl alcohol? (c) If we measure the electrocapillary curve of mercury in contact with 0.5 M Na,SO4 at higher temperature, what changes in the curve can be observed? Try to give explanation of these changes.What is the molar absorptivity coefficient? Question 13 options: 7.14 × 10–1 M–1 cm–1 1.40 × 103 M–1 cm–1 2.60 × 102 M–1 cm–1