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- Q2. Consider the structure shown H₂N G C !!! H₂C I H₂C. HN CH H₂ H₂C 1 CH₂ HN CH H₂ NH,* C=0 C=0 NH₂ CH H₂C HO + HN 11 H₂C N H CH₂ G=0 NH CH NH C=0 CH H₂N. C CH₂ H₂C NH H₂ NH₂ a. Would you consider this a zwitterion or not? Explain. b. If not, would the pH have to increase or decrease to make it a zwitterion? Explain.Everyone keeps giving me different answers so I’m very confusedcompound CH3 CH₂0 CH3 — OH C- CH3 1 CH3-N - CH3 CH₂ ||| -C-H 01C- | NH₂ CH3 family ester
- 8) Identify enantiomers. C E A CI H ICL F CI H Cle H. CI H. CI H CI CI H. F H. 'F 'F H. F H H. F H H H. A) B and D, A and C B) B and D C) A and B, A and D, B and C, C and D D) B and D, A and B, A and D, B and C, C and D E) A and CTo preview the image click here For the following two structures compared in parts A and B, determine whether they are enantiomers OR diastereomers OR the same structure drawn differently (non-bonding electrons not included for clarity). A. B. HO H Н. H3C CH3 H HO Me CI HO H H3C CH3 "OH H Me CL ape-oroflocktem is4. Using the curved arrow formalism to show all the bond-making and bond- breaking steps of the following reaction, indicating stereochemistry, where appropriate, by using wedges and dashes. CH,CH2OH H3C OCH,CH3 H,C. OCH CH3
- Classify each compound as identical to A or its enantiomer. CHO CHO H OH CHO a. CH,CH-C--OH CumCH,CH3 H OH b. d. HO C. ČH,CH3 н он CH;CH CHO CHO ACH3)3CO- is a base that can be made from (CH3)3COH (pKa = 18). Using curved arrow formalism, draw a reaction of this base reacting with NH3 (pKa = 36). Show the products. Which way will be equilibrium lie?16. The structure that corresponds to the below Newman projection is: CI H₂C A) II B) I C) III D) IV CI H₂C CH3 CI CI H₂C H H || H H CH3 CI CI H₂C CH₂ CI ||| CH3 CI CH3 CH3 IV CI CI
