Please correct answer and don't use hand rating A charming GT professor finds a bottle of mineral water. The label is torn off except for theanalysis below in ppm:Na+ 5.50K+ 3.90Ca2+ 29.40Mg2+ 5.10SO4-- 31.40Cl- 2.84HCO3-91.00pH 6.76Use the following molecular weights Ca2+ 40.1 g/mole, Na+ 23 g/mole, Mg2+ 24.3 g/mole,K+39.1 g/mole, SO42-96.1 g/mole, Cl- 35.5 g/mole, HCO3- 61.0 g/mole.a) compute the charge balanceb) calculate the ionic strengthc) calculate the activity coefficients for H+, Ca2+, HCO3- and CO32-

a) Compute the charge balanceWe need to compute the charge balance by ensuring that the sum of…

Answered: A charming GT professor finds a bottle…

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter13: The Chemistry Of Solutes And Solutions

Section: Chapter Questions

Problem 107QRT

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Patients undergoing an upper gastrointestinal tract laboratory test are typically given an X-ray contrast agent that aids with the radiologic imaging of the anatomy. One such contrast agent is sodium diatrizoate, a nonvolatile water-soluble compound. A 0.378-m solution is prepared by dissolving 38.4 g sodium diatrizoate (NaDTZ) in.l.60 102 mL water at 3 1.2C (the density of water at 31.2C is 0.995 g/cm3). What is the molar mass of sodium diatrizoate? What is the vapor pressure of this solution if the vapor pressure of pure water at 31.2C is 34.1 torr?
You need 300. mL of 0.500-M K2Cr2O7. Which method is best to prepare this solution? Explain your choice. (a) Dilute 250. mL of 0.600-M K2Cr2O7 to 300. mL. (b) Add 50.0 mL water to 250. mL of 0.250-M K2Cr2O7. (c) Dilute 125 mL of 1.00-M K2Cr2O7 to 300. mL. (d) Add 30.0 mL of 1.50-M K2Cr2O7 to 270. mL of water.
how do you calculate per serving Zn value for kidney beans compare it with the reported value fine powder beans: 3.3011 g nutrtional value per 100g (3.5 oz): zinc 10%. 1.07 mg y=0.0037x+0.2727 0=0.0037x+0.2727 x=-73.702 = 73.702 Diluted of unknown solution: 73.702 ppb x 400 (dilution factor) = 29,480 ppb 29,480 ug/L x 0.010 = 2948 ug = 2.94 mg in ca 4 g beans
150 140 130 120 110 100 90 80 70 60 50 Ka 40 30 20 KCIO3 10 Bwww -Ce₂(50s)s 0 10 20 30 40 50 60 70 80 90 100 Temperature (°C) Rectangular Snip According to the solubility curve graph above, which of the following ionic compounds would be most soluble at 25°C? a NaNO3 b NaCl Time left for this assessment: с KCI d KCIO3 56:45 Grams of solute per 100 g H₂O 000 3 IN NaNO3 KNO3 KHÁ
100 90 NANO, 80 70 60 CaCl, 50 Pb(NO3)2 40 KCI NaCI 30 20 KCIO, 10 Ce,(SO)3 10 20 30 40 50 60 70 80 90 100 Temperature (°C) How many grams of K2Cr207 will dissolve in 100g of water at 80°C? Solubility (g of salt in 100 g H,O) KNO3
Oral rehydration salts are stated to contain the following components: Sodium Chloride 3.5g Potassium Chloride 1.5g Sodium Citrate 2.9g Anhydrous Glucose 20.0g 8.342 g of oral rehydration salts are dissolved in 500 ml of water. 5 ml of the solution is diluted to 100 ml and then 5 ml is taken from the diluted sample and is diluted to 100 ml. The sodium content of the sample is then determined by flame photometry. The sodium salts used to prepare the mixture were: Trisodium citrate hydrate (C6H5Na3O7, 2H2O) MW 294.1 and sodium chloride (NaCl) NW 58.5. Atomic weight of Na = 23. The content of Na in the diluted sample was determined to be 0.3210 mg/100 ml. Determine the % of stated content of Na in the sample.
Oral rehydration salts are stated to contain the following components: Sodium Chloride 3.5g Potassium Chloride 1.5g Sodium Citrate 2.9g Anhydrous Glucose 20.0g 8.342 g of oral rehydration salts are dissolved in 500 ml of water. 5 ml of the solution is diluted to 100 ml and then 5 ml is taken from the diluted sample and is diluted to 100 ml. The sodium content of the sample is then determined by flame photometry. The sodium salts used to prepare the mixture were: Trisodium citrate hydrate (C6H5Na3O7, 2H2O) MW 294.1 and sodium chloride (NaCl) NW 58.5. Atomic weight of Na = 23. The content of Na in the diluted sample was determined to be 0.3210 mg/100 ml. Determine the % of stated content of Na in the sample. The stated should be 104.5, how??
Grams of solute/100g H 20 150 140 130 120 110 100 90 80 70 60 50 40 30 20 10 0 KI Na2SO47 0 10 Solubility Curve NaNO3 HCI NH3 KNO3 NaCl gases solids NH4CI KCI KCIO3 SO2 20 30 40 50 60 70 80 90 100 Temperature (°C) 1) Find the solubility of potassium nitrate at i) 20 °C, ii) 80 °C 2) Calculate the maximum amount of potassium nitrate that could be dissolved in 20 cm³ of water at 40°C. 3) Find the minimum temperature needed to make a solution of potassium nitrate with a concentration of 2.0 mol dm-³. 4) Compare and contrast the solubility curves of sodium chloride and sodium nitrate 5) Summarise the trends in the solubility curves for solid salts and gases.
C. Electrolytes in Body Fluids 1. Type of IV Solution 5% Isolute P (mEa/L) Plasnalyte (mEg/L) Lactated Ringer's (mEg/L) Nal+ = 130 Klt = 4 Ca2+ = 3 Nal+ = 25 K+ = 20 Nal+ = 140 Kl+ = 5 2. Cations %3D %3D Mg+ = 3 Mg2+ = 3 CI- = 22 HPO- =3 Acl- = 23 CI- = 98 Glu'-= 23 Acl- = 27 3. Anions CI'- = 109 %3D HPO = 28 %3D %3D 4. Total Charge of Cations (+) 137 137 5. Total Charge of Anions (-) 6. Sum of the Charges Copyright 2014 Pearson Education, Inc.
2. How many mL of a 0.250 M KCI solution must be diluted to 1.000 L so that the diluted solution (density = 1.00 g/mL ) is 400 ppm K* by weight ? (MW KCI = 74.55; AW K = 39.10)
Given the following: Solutions Flask 1 Flask 2 Flask 3 0.04 M KI 25.0 mL 25.0 mL 12.5 mL 1% starch 5.00mL 5.00mL 5.00mL 0.03 M Na2S2O3 5.50 mL 5.50 mL 5.50 mL 0.05 M H2SO4 5.00 mL 5.00mL 5.00mL 0.08 M NaCl 0 0 10.0 mL and Solutions Beaker 1 Beaker 2 Beaker 3 0.04 M H2O2 25.0 mL 12.5 mL 25.0 mL deioinized water 0 12.5 mL 0 Following the procedure Run 1 is when Beaker 1 is added to Flask 1 and the timer is started giving the time recorded for the run in the table below. This is repeated with Beaker 2 and Flask 2 for Run 2 and finally Beaker 3 and Flask 3 for Run 3: The results for these runs are given below: Run Time (seconds) 1 35 2 66 3 72 Calculate the following for each run: the initial molarities of I- and H2O2 (from the solutions tables) the rates of reaction [I2]/time (calculate the [I2] from [S2O32-] and the reaction: I2(aq) + 2 S2O32-(aq) → 2I-(aq) + S4O62-(aq) Choose the correct rate law for this reaction from your calculations.…
How many grams of Ba(103)2 (487 g/mol) can be dissolved in 400 mL of water at 25°C. (Ksp of Ba(1O3)2 = 1.57 x 10-9) Ba(103)2 Ba2+ + 2103 O 0.298 g 0.122 g 0.221 g O 0.926 g O 0.143 g

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