**Question:**How many grams (g) of solute are present in 75 mL of a 0.50 M glucose (C₆H₁₂O₆) solution of glucose?**Given Data:**- Molar mass of glucose = 180.15 g/mol**Options:**- A. 68 g- B. 7.0 g- C. 0.038 g- D. 37.5 g- E. 6.8 g**Explanation:**To find the grams of glucose in the solution, use the following steps:1. Convert the volume from mL to L: - 75 mL = 0.075 L2. Use the formula for moles of solute: - Moles of solute = Molarity (M) × Volume (L) - Moles of glucose = 0.50 M × 0.075 L = 0.0375 moles3. Convert moles to grams: - Grams = Moles × Molar mass - Grams of glucose = 0.0375 moles × 180.15 g/mol = 6.8 g**Correct Answer:**- E. 6.8 g

Biomolecules are organic molecules present in living organisms. Carbohydrates, nucleic acids,…

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Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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How many grams (g) of solute are present in 75 mL of a 0.50 M glucose (C6H1206) solution of glucose? Molar mass of glucose = 180.15 g/mol %3D A. 68 g B. 7.0 g C. 0.038 g D. 37.5 g E. 6.8 g