His388Glu357His388Glu357Ring openingProtonHOHOabstractionHOно-G6PHeNH-NHHis388His388His388 Glu357Glu357Glu357HOноHOно-ноOHcis-enediolF6PRing closureintermediateOHDescribe the mechanism shown above for phosphoglucose isomerase.Describe the chemistry of each step• How the enzyme appears or might facilitate the chemistryHow the enzyme increases the reaction rate.

Phosphoglucose isomerase is EC 5.3. 1.9. It catalyzes the second step of glycolysis causing the…

Answered: His388 Glu357 His388 Glu357 Ring…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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KINETIC CONSTANT No Na2HPO4 25mM Na2HPO4 50mM Na2HPO4 Vmax nmol p-NP. Min- 20.3252 14.30615 17.30104 Km mM -0.819106 -0.46495 -0.352941 1. What does this suggest about the structure of the active side of the enzyme?
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Predict the effect of each of the following amino acid substitutions on the KM and kcat of the enzyme-catalyzed reactions
Select the incorrect statement. With regards to free energy ΔG of the reaction below E+S ⇌ ES Negative ΔG mean the reaction toward is facourable More negative value of ΔG indicates stronger binding to S to E It is possible to compute disassociation constant from the ΔG value alone It is possible to calculate the term ( ΔH – T ΔS) from the value of ΔGalone ΔG = 0 indicates (ES)/(E)(S) =1 None of the above
4
=display&toolld3calendar-mybb, Gmail YouTube Maps calendar-tool Home Courses C A Question Completion Status: 20 3D 70 100| 11凸|12D|| 130 14 150 16 170 QUESTION 14 A newly isolated bacterial isocitrate dehydrogenase is found to have a molecular mass of 180KDA and SDS-PAGE shows it to be a homodimer. 1mg of enzyme produces 0.05 mmoles of product per minute per mL. What is the turnover number of this enzyme in µmol product produced per pmol of enzyme subunit per mL? O a. 4.5 Ob.4500 O c. 9000 O d.9 QUESTION 15 The absorption spectrum of NAD" and its reduced form NADH are shown below: Absorption 2,4 2,0 1,6 Click Save and Submit to save and submit. Click Save All Answers to save all answers. Save All Ar 8 11 JAN 9. tv W ... LO
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protease mechanism: you isolate a new protease which cleaves the peptide bond 2 aa residues before a F residue. You might expect to fınd... O An I residue in the S2'pocket AL residue in the S2 pocket O aV residue in the oxyanion hole An Lresidue in the catalytic triad in Michaelis-Menton kinetics, cutting the enzyme concentration in half will O will double the reaction rate O will not change Vo and Vmax will change Vo but not turnover number decrease Km by half
Puting a metabolic pathway map together which includes glycolysis, gluconeogenesis, glycogen synthesis & glycogenolysis, and the two types of fermentation, and pyruvate oxidation (to acetyl-CoA). The map should have/illustrate/show all of the indicated 6 pathways stated previously on the same page, to emphasize how these processes are related to each other. map should include: a) Clear labels for all the pathways b) All the pathways shown on the same page and correctly integrated with each other, i.e., it should be clear which reactions are shared by different pathways c) The names of all metabolites (common abbreviations may be used) d) The names of all enzymes e) All relevant cofactors/co-substrates discussed in class, clearly showing, where ATP is used and produced f) Double or single arrows representing reversible or irreversible reactions, respectively g) All "high-energy" intermediates clearly labeled with an asterisk (*) h) Labels for cellular locations of…
(d) of glucose oxidation in diabetic human patients treated with Metformin (●) and in (nondiabetic) control human patients (0). At –150 min both groups of subjects were started on an intravenous feed of 3-(®H)-glucose, and at t = 0 min they were started on an oral glucose tolerance test whereby a measured amount of glucose in water (a syrupy mixture) was swallowed followed by measure- ment of blood glucose levels at 30 min intervals. The flux of glucose oxidation was measured by the appear- ance of 3H2O in the blood stream. While the information The diagram to the right compares the rate 8000 ORAL GLUCOSE 6000- 4000- 2000- -120 -60 60 120 180 240 300 Minutes cannot be directly extracted from the reaction mecha- nism diagrams in the textbook, the glycolytic step in which the tritium is first released into water is that catalyzed by TPI, as illustrated at the beginning of Question #3. Explain why this step is suitable for measuring the flux of glycolysis through the release of °H…

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