hi, expert please help me with this problem.. i need it before 5 pm thank you As part of a lab exercise, your group was assigned an unknown compound X for which you had to determine its partition coefficient between an organic solvent and water. You dissolve and shake 4 grams of X in a mixture of 130 mL benzene and 100 mL of water. At the end, your group discovered that the benzene layer contained 0.5 g of X. Use the information provided to calculate for the partition coefficient. What can you say about the chemical nature of compound X? I HAVE 2 ANSWERS (i don't know if it is correct hehehe) 1st Answer: partition coefficient (Kd)=conc. at 1st phase (C1) / conc. at 2nd phase (C2) Kd = C1/C2 = CH2O / CBenzene Kd = (4g-0.5g) / 100 mL / 0.5G/130 mL Kd = 0.035/0.003846154 Kd = 9.099 or 9.1 (my 1st answer) My 2nd Answer is on the picture please CHECK IF CORRECT. IF NOT PLEASE SEND THE CORRECT ANSWER THANK YOU.
hi, expert please help me with this problem.. i need it before 5 pm thank you As part of a lab exercise, your group was assigned an unknown compound X for which you had to determine its partition coefficient between an organic solvent and water. You dissolve and shake 4 grams of X in a mixture of 130 mL benzene and 100 mL of water. At the end, your group discovered that the benzene layer contained 0.5 g of X. Use the information provided to calculate for the partition coefficient. What can you say about the chemical nature of compound X? I HAVE 2 ANSWERS (i don't know if it is correct hehehe) 1st Answer: partition coefficient (Kd)=conc. at 1st phase (C1) / conc. at 2nd phase (C2) Kd = C1/C2 = CH2O / CBenzene Kd = (4g-0.5g) / 100 mL / 0.5G/130 mL Kd = 0.035/0.003846154 Kd = 9.099 or 9.1 (my 1st answer) My 2nd Answer is on the picture please CHECK IF CORRECT. IF NOT PLEASE SEND THE CORRECT ANSWER THANK YOU.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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hi, expert please help me with this problem.. i need it before 5 pm thank you
As part of a lab exercise, your group was assigned an unknown compound X for which you had to determine its partition coefficient between an organic solvent and water. You dissolve and shake 4 grams of X in a mixture of 130 mL benzene and 100 mL of water. At the end, your group discovered that the benzene layer contained 0.5 g of X. Use the information provided to calculate for the partition coefficient. What can you say about the chemical nature of compound X?
I HAVE 2 ANSWERS (i don't know if it is correct hehehe)
1st Answer:
partition coefficient (Kd)=conc. at 1st phase (C1) / conc. at 2nd phase (C2)
Kd = C1/C2 = CH2O / CBenzene
Kd = (4g-0.5g) / 100 mL / 0.5G/130 mL
Kd = 0.035/0.003846154
Kd = 9.099 or 9.1 (my 1st answer)
My 2nd Answer is on the picture please CHECK IF CORRECT. IF NOT PLEASE SEND THE CORRECT ANSWER THANK YOU.
![Civen:
4gof were dissolved in 130 ml berzene
and loomL water
0-5
of. * in the benzene layer
were identified
What ic asked : partition coefficient
%3D
k
Solution
X organic
[XI Aqueous
Concentration of X in berzene
XS organic
TXJ organic
amount of A (mass)
Volume
130 mL
[xJ opganic
0.00 98 glml.
Concentration of
[x] aqueous
xJ aquenus
* in water
9 of A
vol. (m)
4
100 mL
X-
[A aqueous
> 0-04 g/ml
ErJorgante
Ex Aquesus
0.0038-glmb
0-04 의mL
K - 0.095](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb61958a3-badf-4ed4-b0f1-f2e04b3f701f%2Fbd2177db-af1a-45eb-8616-7fec9c8d1fad%2Fkt9t5an_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Civen:
4gof were dissolved in 130 ml berzene
and loomL water
0-5
of. * in the benzene layer
were identified
What ic asked : partition coefficient
%3D
k
Solution
X organic
[XI Aqueous
Concentration of X in berzene
XS organic
TXJ organic
amount of A (mass)
Volume
130 mL
[xJ opganic
0.00 98 glml.
Concentration of
[x] aqueous
xJ aquenus
* in water
9 of A
vol. (m)
4
100 mL
X-
[A aqueous
> 0-04 g/ml
ErJorgante
Ex Aquesus
0.0038-glmb
0-04 의mL
K - 0.095
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