Answered: ① H+ + HCO3─ + Pi →…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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① H⁺+ HCO₃^─ + P_i → Carboxyphosphate + H₂O ∆G⁰’ =+19.7 kJ mol^-1

② ATP + H₂O → ADP + P_i + H⁺ ∆G⁰’ = ─30.5 kJ mol^-1

③ Carboxyphosphate + pyruvate → oxaloacetate + P_i∆G⁰’ = ??? kJ mol^-1

④ Overall reaction:

ATP + HCO₃^─ + pyruvate → oxaloacetate + ADP + P_i ∆G⁰’ = ─2.1 kJ mol^-1

a) Use reactions ①, ② and overall reaction ④ to calculate the ∆G⁰’ for the formation of oxaloacetate from pyruvate and carboxyphosphate (reaction ③ above).

Use reactions ①, ② and overall reaction ④ to calculate the ∆G⁰’ for the formation of oxaloacetate from pyruvate and carboxyphosphate (reaction ③ above).

b) Now calculate ∆G⁰’ for the formation of oxaloacetate from pyruvate and bicarbonate in the absence of ATP.

c) Explain the difference in your answers to parts a and b.

Expert Solution

Step 1: Given data

The given reactions are:

$1. space H to the power of plus space plus space H C O subscript 3 superscript minus space plus space P subscript i rightwards arrow C a r b o x y p h o s p h a t e space plus space H subscript 2 O space colon space increment G degree subscript 1 equals plus 19.7 space k J divided by m o l 2. space A T P space plus space H subscript 2 O rightwards arrow A D P space plus space P subscript i space plus space H to the power of plus space space space colon space increment G degree subscript 2 equals negative 30.5 space k J divided by m o l 3. space C a r b o x y p h o s p h a t e space plus space p y r u v a t e space rightwards arrow o x a l o a c e t a t e space plus space P subscript i space space colon space increment G degree subscript 3 equals n o t space g i v e n 4. space A T P space plus space H C O subscript 3 superscript minus space plus space p y r u v a t e space rightwards arrow space o x a l o a c e t a t e space plus space A D P space plus space P subscript i space space colon space increment G degree subscript 4 equals negative 2.1 space k J divided by m o l$

The reaction 4 is the overall reaction. $Δ G^{\circ}$ represents the change in standard Gibbs energy for the process.

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