Which of the following processes have a S > 0? CH3OH(I) → CH3OH(s) N₂(g) + 3 H₂(g) → 2 NH3(g) CH4(g) + H₂O (g) → CO(g) + 3 H₂(g) Na2CO3(s) + H₂O(g) + CO₂(g) → 2 NaHCO3(s) All of these processes have a DS > 0.
Which of the following processes have a S > 0? CH3OH(I) → CH3OH(s) N₂(g) + 3 H₂(g) → 2 NH3(g) CH4(g) + H₂O (g) → CO(g) + 3 H₂(g) Na2CO3(s) + H₂O(g) + CO₂(g) → 2 NaHCO3(s) All of these processes have a DS > 0.
Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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![**Which of the following processes have a ΔS > 0?**
- ⃝ CH₃OH(l) → CH₃OH(s)
- ⃝ N₂(g) + 3 H₂(g) → 2 NH₃(g)
- ⃝ CH₄(g) + H₂O(g) → CO(g) + 3 H₂(g)
- ⃝ Na₂CO₃(s) + H₂O(g) + CO₂(g) → 2 NaHCO₃(s)
- ⃝ All of these processes have a ΔS > 0.
**Explanation:**
This is a multiple-choice question asking which processes result in an increase in entropy (ΔS > 0).
1. **CH₃OH(l) → CH₃OH(s):**
- This process involves the phase change from liquid to solid, generally associated with a decrease in entropy, ΔS < 0.
2. **N₂(g) + 3 H₂(g) → 2 NH₃(g):**
- This reaction involves fewer gas molecules (4 to 2), typically associated with a decrease in entropy.
3. **CH₄(g) + H₂O(g) → CO(g) + 3 H₂(g):**
- The number of gas molecules increases (2 to 4), typically associated with an increase in entropy.
4. **Na₂CO₃(s) + H₂O(g) + CO₂(g) → 2 NaHCO₃(s):**
- The reaction results in fewer gas molecules and more solid product, likely associated with a decrease in entropy.
5. **All of these processes have a ΔS > 0:** This option suggests that all reactions result in an increase in entropy, which is not correct based on the individual analysis above.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb5cb748f-b247-416f-8df5-751d92c52687%2F47cbb4a2-aa58-4791-8443-8f6f4a8cd738%2Fifv15dt_processed.png&w=3840&q=75)
Transcribed Image Text:**Which of the following processes have a ΔS > 0?**
- ⃝ CH₃OH(l) → CH₃OH(s)
- ⃝ N₂(g) + 3 H₂(g) → 2 NH₃(g)
- ⃝ CH₄(g) + H₂O(g) → CO(g) + 3 H₂(g)
- ⃝ Na₂CO₃(s) + H₂O(g) + CO₂(g) → 2 NaHCO₃(s)
- ⃝ All of these processes have a ΔS > 0.
**Explanation:**
This is a multiple-choice question asking which processes result in an increase in entropy (ΔS > 0).
1. **CH₃OH(l) → CH₃OH(s):**
- This process involves the phase change from liquid to solid, generally associated with a decrease in entropy, ΔS < 0.
2. **N₂(g) + 3 H₂(g) → 2 NH₃(g):**
- This reaction involves fewer gas molecules (4 to 2), typically associated with a decrease in entropy.
3. **CH₄(g) + H₂O(g) → CO(g) + 3 H₂(g):**
- The number of gas molecules increases (2 to 4), typically associated with an increase in entropy.
4. **Na₂CO₃(s) + H₂O(g) + CO₂(g) → 2 NaHCO₃(s):**
- The reaction results in fewer gas molecules and more solid product, likely associated with a decrease in entropy.
5. **All of these processes have a ΔS > 0:** This option suggests that all reactions result in an increase in entropy, which is not correct based on the individual analysis above.
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