H10m6mSATURATED CLAYYo=19 kN/m2.5mSANDA175 kN/mCalculate the max. depth of cut H, thata)can be made in the clay.Calculate the effective stress of A.b)c)Calculate the effective stress at B.Scanned with CamScanner

Answered: H 10m 6m SATURATED CLAY Yo=19 kN/m A…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Q1 The lower sand layer in the soil profile shown below is in an artesian condition. Calculate: 2 a) The effective stress () at the top and base of the clay layer. 2b) The height of water in the piezometer for 5 = 0 at the base of the clay layer. > c) The maximum depth (Z) of the proposed excavation (Figure Q1 (b)). (Assume Z>2 m). 4.0 m 2.0m Yary 16.6 kN/in³ Sand Ground water table Z Y.. W.T. Sand 2.0 m Sand Ysa 20.6 kN/m³ 4.0 m Year 20.6 kN/m³ Clay R Sand Ysar=20.5 kN/m³ Figure Q1 (b) Clay Sand Figure Q1 (a)
You have been assigned to check the stability of a pond constructed in stiff saturated clay underlain by a layer of sand. The necessary information are given in the following figure. (i) Find effective stress at and determine the stability of cut under given condition. (ii) What should be water level into the pond to ensure factor of safety = 1. (Given that yw = 9.81 kN/m³) H = 5 m 7m KE T 3 m 2 m ↓ Saturated clay Sand Ysat 18 kN/m³ 6.5 m Ysat = 15 kN/m³
Translation results Translation result how much should the groundwater level rise for the 9m soil profile composed of clay (4m) and sand (5m) from the first case when it was 4m so that the change in effective stress at the bottom of the clay layer is 15kN
A vane shear test was conducted in a saturated clay. The height and diameter of the rectangular vane were 4 in. and 2 in., respectively. During the test, the maximum torque applied was 230 lb-in. The clay soil has a undrained shear strength of 7.844 psi. It has a liquid limi of 58 and a plasic limi o 29. What would be the corrected undrained shear strength of the clay for design purposes? Using Bjerum's relationship for λ. λ = 1.7 - 0.54 log[PI(%)]
Compute geostatic stress at point A y= 15.0 kN/m³ V Y= 16.8 kN/m³ Y= 17.2 kN/m³ 2.0 m 2.5 m 3.6 m 10.9 m SC 1.6 m B SM Silty sand CL Clay
A point load Q = 250 kN is applied to the ground surface. What is the minimum depth Zi in m below the point load such as the increase in vertical total stress does not exceed 10 kPa. Do not consider any eccentricity for this question. (Acceptable tolerance = 2%).
the profile of on 2 m from the load. 5-11 A uniform surface load of 220 kPa is applied over the area shown below. Estimate the stress increase in soil due to the surface load at a depth of 15 m below point A. 10 m 20 m IT 10 m A
O The lower sand layer in the soil profile shown below is in an artesian condition. Calculate: a) The effective stress (6) at the top and base of the clay layer. b) The height of water in the piezometer for = 0 at the base of the clay layer. c) The maximum depth (Z) of the proposed excavation (Figure Q1 (b)). (Assume Z>2 m). Lawr 4.0 m [2m 2.0 m dry -16.6 kN/m² Sand Ground water table Z Y.. W.T. 2.0 m Sand Sand 720.6 kN/m² TOP 4.0 m You 20.6 kN/m² Clay base Test 20.5 kN/m² Sand Ban Clay Send ħ 24
Fground surface Y-15.6 kN/m Year-16.6 KN/m 4 m waler table Clay 5 m Y=17,8 kN/m Compute the effective stress at the bottom of the clay. a) 120.53 kPa b) 102.35 kPa e) 112.65 kPa d) 121.56 kPa If the water table rises to the level of the soll surface, what is the effective stress at the bottom of the clay? a) 66.55 kPa b) 78.11 kPa c) 67.11 kPa d) 48.19 kPa
Find h ?if the effective stress at bottom=200.85 kN/m². clay Y=18 kN/m³ @=12% 3m 3m 4m Silt G-2.71 S= 70% e = 0.6 Silt Capilary layer.zone Sand RF 72% n = 33% G= 2.68 max = 0.75 e
A concentrated load of 2500 kN is applied to the ground surface. Using Businessq equation. Compute the vertical stress increment in kPa due to this load at a depth of 6 m directly below the load. Compute the vertical stress increment in kPa due to this load at a depth of 6m below the ground surface and at a horizontal distance of 4.8m from the line of the concentrated load
G,+S,e , a) Starting from the basic phase definitions (see the Appendix) show that y = 1+e b) Using the expression above, determine the distribution of the total and effective vertical stress with depth for the soil profile shown. Plot these distributions for 0 60%, T, : 1.781 – 0.933 log(100 – U%) C,H - log 1+e, o, + Ao' C,H 1+e, S = - log

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H 10m 6m SATURATED CLAY Yo=19 kN/m A 2.5m SAND A175 kN/m Calculate the max. depth of cut H, that a) can be made in the clay. Calculate the effective stress of A. b) c) Calculate the effective stress at B. Scanned with CamScanner