G, +S,e a) Starting from the basic phase definitions (see the Appendix) show that y = 1+e b) Using the expression above, determine the distribution of the total and effective vertical stress with depth for the soil profile shown. Plot these distributions for 0Sz<12m.Yw = 9.81 kN/m3 4.0 m Sand G = 2.65; e= 0.6 2.0 m W. T. Clay G = 2.8; e = 0,8 4.0 m 2.0 m Silt Y =18 kN / m² Appendix Vw ;e = Vs %3D M, = G,VsPwi Mw = wM, GSYW Ya 1+e (Gs – 1)Yw y' %3| 1+e (1+w)YwGs Ysat = 1+ wG5 Cc = 0.009(LL – 10) Cyt T, Har %| 2 For 0 60%, T, = 1.781 – 0.933 log(100 – U%) C,H C,H + o, + Ao' log 1+e, 1+e, – log
G, +S,e a) Starting from the basic phase definitions (see the Appendix) show that y = 1+e b) Using the expression above, determine the distribution of the total and effective vertical stress with depth for the soil profile shown. Plot these distributions for 0Sz<12m.Yw = 9.81 kN/m3 4.0 m Sand G = 2.65; e= 0.6 2.0 m W. T. Clay G = 2.8; e = 0,8 4.0 m 2.0 m Silt Y =18 kN / m² Appendix Vw ;e = Vs %3D M, = G,VsPwi Mw = wM, GSYW Ya 1+e (Gs – 1)Yw y' %3| 1+e (1+w)YwGs Ysat = 1+ wG5 Cc = 0.009(LL – 10) Cyt T, Har %| 2 For 0 60%, T, = 1.781 – 0.933 log(100 – U%) C,H C,H + o, + Ao' log 1+e, 1+e, – log
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
Transcribed Image Text:G,+S,e ,
a) Starting from the basic phase definitions (see the Appendix) show that y =
1+e
b) Using the expression above, determine the distribution of the total and effective vertical stress with
depth for the soil profile shown. Plot these distributions for 0<z<12m.Yw =
9.81 kN /m³
4.0 m
Sand
G¸ = 2.65; e= 0.6
2.0 m
W.T.
4.0 m
Clay
G = 2.8;
e = 0.8
2.0 m
Silt
Y sa =18 kN / m²
Appendix
Vw
S, =
-;e =
Vs
M, = G,V;Pwi Mw = wMs
G3YW
Ya =
1+e
(Gs – 1)Yw
y'
1+e
(1+ w)Y»G5
1 + wGs
Ysat =
Cc = 0.009(LL – 10)
%3D
Cyt
T,
Här
2
n (U%`
For 0 sUS 60%,T, = " ()
4 (100,
For U > 60%, T, :
1.781 – 0.933 log(100 – U%)
C,H
- log
1+e,
o, + Ao'
C,H
1+e,
S =
- log
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