2. The shear strength of a normally consolidated clay can be given by the equation t = ơ' tan 28°. A consolidated-undrained test was conducted on the clay. Following are the results of the test. Chamber confining pressure = 105 KN/m? Deviator stress at failure 97 KN/m² a. Compute the pore water pressure developed in the clay specimen at failure. b. Compute the consolidated-undrained friction angle 4. What would have been the deviator stress at failure if a drained test had been conducted with the same chamber confining pressure that is o3= 105 KN/m? C.
2. The shear strength of a normally consolidated clay can be given by the equation t = ơ' tan 28°. A consolidated-undrained test was conducted on the clay. Following are the results of the test. Chamber confining pressure = 105 KN/m? Deviator stress at failure 97 KN/m² a. Compute the pore water pressure developed in the clay specimen at failure. b. Compute the consolidated-undrained friction angle 4. What would have been the deviator stress at failure if a drained test had been conducted with the same chamber confining pressure that is o3= 105 KN/m? C.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:2. The shear strength of a normally consolidated clay can be given by the equation t = ơ' tan 28°. A
consolidated-undrained test was conducted on the clay. Following are the results of the test.
Chamber confining pressure = 105 KN/m?
Deviator stress at failure = 97 KN/m²
a. Compute the pore water pressure developed in the clay specimen at failure.
b. Compute the consolidated-undrained friction angle 4.
What would have been the deviator stress at failure if a drained test had been conducted
with the same chamber confining pressure that is o3= 105 KN/m?
C.
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