Q-2: Following are the results of four drained direct shear tests on an over consolidated clay:Diameter of specimen = 50 mmHeight of specimen = 25 mmTest no.1234Normal force (N)150250350550Shear force at failure (N)157.5199.9257.6363.4Determine shear strength parameters by plotting graph

Diameter = 50 mm Height = 25 mm

Q-2: Following are the results of four drained direct shear tests on an over consolidated clay: Diameter of specimen = 50 mm ● Height of specimen = 25 mm Test no. 1 2 234 4 Normal force (N) 150 250 350 550 Shear force at failure (N) 157.5 199.9 257.6 363.4 Determine shear strength parameters by plotting graph

Q-2: Following are the results of four drained direct shear tests on an over consolidated clay: Diameter of specimen = 50 mm ● Height of specimen = 25 mm Test no. 1 2 234 4 Normal force (N) 150 250 350 550 Shear force at failure (N) 157.5 199.9 257.6 363.4 Determine shear strength parameters by plotting graph

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Test for Determination of Shear Strength

The term shear strength is often associated with the soil. Shear strength is defined as the resistance to the deformation of soil particles due to the continuous action of shear stress. In short, shear strength is the maximum shear stress that a soil can sustain.

Question

Q-2: Following are the results of four drained direct shear tests on an over consolidated clay:
Diameter of specimen = 50 mm
Height of specimen = 25 mm
Test no.
1
2
3
4
Normal force (N)
150
250
350
550
Shear force at failure (N)
157.5
199.9
257.6
363.4
Determine shear strength parameters by plotting graph

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