A specimen of saturated sand was consolidated under an all-around pressure of 105kN/m2.The axial stress was then increased and drainage was prevented.The specimen failed when the axial deviator stress reached 70 KN/m2.The pore water pressure at failure was 50 KN/m2.Determine: i. Consolidated-undrained angle of shearing resistance, ɸ ii. Drained friction angle, ɸ′ iii. Sketch Mohr’s circles and Failure Envelops in terms of total and effective stress. iv. Assuming soil specimen to be homogenous, sketch a network of failure planes.

Q: Problem 2. A CD triaxial test was conducted on a loose sand. The axial stress was held constant and…

A:

Q: A consolidated-drained tri-axial test was conducted on a normally consolidated clay. The results are…

A: The result of the consolidated tri-axial test are:-Confining stress Deviator stress To determine:-i)…

Q: Q2: A sample of clean sand was retrieved from 7m below the surface, vertical load of 150 kN/m, a…

A:

Q: (c) The shear strength of soil collected 4m below ground surface and tested under consolidated…

A: Comparing the given equation of Shear stress with standard equation:

Q: In a triaxial test for the normally consolidated clay, chamber confining pressure 200 %3D kN/m2 and…

A: Confining pressure and deviator pressure of triaxial test have been given and it has been asked to…

Q: The equation of the effective stress failure envelope for a slightly over-consolidated clay is 7, =…

A: Pole Method The Pole method is used in mohr's circle to find the stresses along the plane. The Pole…

Q: Example 22 se For a normally consolidated clay (c' = 0) these are the results for a consolidated…

A: Deviator stress = sigma1 - Sigma3 Chamber pressure = Sigma3

Q: 2.22 A consolidated-undrained normally consolidated test results: triaxial test was conducted on a…

A: Consolidated saturated clay test results σ3 = 90 kN/m²σ1 = 220 kN/m²  u = 38 kN/m²

Q: The stresses on a failure plane in a drained triaxial test on sand are as Follows: Normal Stress nf…

A:

Q: 1. Given the figure below plot the pore pressure, total stress and effective tress at the top,…

A: Finding out the total stress diagram,pore water pressure diagram and effective stress diagram.

Q: The results of a consolidated undrained test, in which o3 = 392 kN/m², on a normally consolidated…

A: Given : Results of a consolidated undrained test on a normally consolidated clay                σ3 =…

Q: It is known that the angle of internal friction for the soil comprising a granular deposit is 37°.…

A: Answer  We are given Angle of internal friction ϕ = 37o  Minor principal stress σ3 = 45 Kpa Let us…

Q: 2 7.3 A normally consolidated clay specimen (d=31°) was consolidated under a chamber-confining…

A: For pore water pressure we have the concept of effective stress

Q: A certain soil has c ′ = 12 kPa and ∅ ′ = 32° . The major and minor total principal stresses at a…

A: Given: c' = 12KPa, ∅ ′ = 32°, major principal stress= 348KPa minor total principal stress = 160 KPa

Q: Pre-consolidation stress at sample depth (kPa) = | |.... No decimals needed Based on the o'z0 value…

A: The soil at a depth experiences stress due to presence of overburden or other loads. These stress…

Q: For normally consolidated clay specimens, drained direct shear tests were conducted and the…

A: INTRODUCTION; Direct shear test is performed over the soil to calculate the shear strength of soil…

Q: A sand layer lay over a clay stratum is 5 m in depth, as shown below. The water is 2.5 m below…

A: Given data : γSat=18 KN/m3γdry=12 KN/m3γw=10 KN/m3

Calculation of Settlement

The vertical displacement of the structural foundation due to the loading from the superstructure is known as settlement. It is due to the reduction of air voids present in the soil. The amount of vertical displacement depends on the bearing capacity of the soil on which the foundation is laid. The effect of the settlement depends on the magnitude of settlement, uniformity, and the structural design of the structure. The maximum allowable settlement for residential and office buildings should be less than 18 mm, for industrial buildings, it is 38 mm and for commercial buildings, it is 25 mm.