Example 22 se For a normally consolidated clay (c' = 0) these are the results for a consolidated drained triaxial test Chamber pressure = 104 kN/m² Deviator stress at failure = 125 kN/m² a) Find the angle of friction, ' (Answer: 22) b) Determine the angle 8 that failure plane makes with the major principle plan (Answer: 56) TOI-OHOMAI Institute of Technology Example 3 The equation of effective stress failure envelope for normally consolidated clayey soil is Tf = o'tan 27 A drained triaxial test was conducted with the same soil at the chamber confining pressure of 100 kN/m². Calculate the deviator stress at failure (Answer: 166.3 kN/m²)

Example 22 se For a normally consolidated clay (c' = 0) these are the results for a consolidated drained triaxial test Chamber pressure = 104 kN/m² Deviator stress at failure = 125 kN/m² a) Find the angle of friction, ' (Answer: 22) b) Determine the angle 8 that failure plane makes with the major principle plan (Answer: 56) TOI-OHOMAI Institute of Technology Example 3 The equation of effective stress failure envelope for normally consolidated clayey soil is Tf = o'tan 27 A drained triaxial test was conducted with the same soil at the chamber confining pressure of 100 kN/m². Calculate the deviator stress at failure (Answer: 166.3 kN/m²)

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: A consolidation undrained (CU) triaxial compression test is conducted on a normally consolidated…

A: Asked: To determine the effective angle of friction () for the given CU test.Given:Consolidated…

Q: Problem 2. A CD triaxial test was conducted on a loose sand. The axial stress was held constant and…

Q: A consolidated-drained tri-axial test was conducted on a normally consolidated clay. The results are…

A: The result of the consolidated tri-axial test are:-Confining stress Deviator stress To determine:-i)…

Q: (A 30' 5 EQUAL SACES 35 BEauAL SICES Ga I- 30 8. GI ca 30 -I- O FLOOR FRAMING PLAN uestions: O Dran…

Q: Example 3 The equation of effective stress failure envelope for normally consolidated clayey soil is…

Q: 1- Following data are given for a direct shear test conducted on dry sand: Normal stress: 120 lb/ft²…

Q: The equation of the effective stress failure envelope for a slightly over-consolidated clay is 7, =…

A: Pole Method The Pole method is used in mohr's circle to find the stresses along the plane. The Pole…

Q: A sample of dry sand is subjected to a tri-axial test. The angle of internal friction is 35.2°. The…

Q: Situation: The results of a consolidated drained triaxial shear test conducted on a consolidated…

Q: The following are the results of four drained shear box tests on over-consolidated clay specimens…

A: Area of shear box = 1960 mm². The results of four drained shear box tests on over-consolidated…

Q: A sample of dry sand was placed in a direct shear testing apparatus and was tested until the sample…

A: Given that: Shear stress at failure, τf=70 kN/m2Normal stress at failure, σf=96 kN/m2

Q: The stresses on a failure plane in a drained triaxial test on sand are as Follows: Normal Stress nf…

Q: Q.4/ A normally consolidated (N.C) clay was found to have p-15°, q'= 30°. The soil specimen was…

Q: Q # 3. Following data are given for a direct shear test conducted on dry sand: Specimen dimensions:…

A: Given: Specimen dimension - 63mm×63mm×25mmσNormal stress - 105 kN/m2v Shear force at failur - 300…

Q: A consolidated-undrained test on a normall consolidate clay yield the following results: Confining…

A: Given:- Confining pressure = 160 kPa Deviator stress = 181 kPa Pore pressure = 77 kPa To find:- From…

Q: A consolidated-undrained triaxial test on a specimen of saturated clay was carried out under an…

A: Stress path for s-t plot is shown below. This plot is generally, called as Cambridge plot. The total…

Q: A uniform loading of 150kPa is applied at a 28 m Χ 28 m area. Please calculate the consolidation…

A: Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: Determine a. Angle of friction, o' b. Angle 0 that the failure plane makes with the major principal…

Q: A CD triaxial compression test conducted on a clay specimen revealed that c'=5 kPa and o'=22°. What…

Q: O A. Tresca failure criterion. O B. None of the filure criterion models. 2 C. Mohr-Coulomb failure…

A: Question 15- Option C Mohr failure criteria is used. In this test mohr circle is plotted at…

Q: The results of a consolidated undrained test, in which o3 = 392 kN/m², on a normally consolidated…

A: Given : Results of a consolidated undrained test on a normally consolidated clay σ3 =…

Q: SITUATION 5: A sand sample is subjected to direct shear testing at it's (in - situ) water content.…

A: For the first test : σ = 400 kPaτ = 300 kPaWe know that, τ = σtanϕ + c 300…

Q: sample of dry sand is tested in direct shear. The shear box holding the sample has a circular cross…

Q: In a tri-axial test for a normally consolidated soil, the deviator stress is equal to 700 kPa and…

Q: A soil sample is subjected to an initial equal-all-around hydrostatic state of stress of 50 kPa.…

Q: 2. Ten point load tests are carried out on cylindrical specimens of a sedimentary rock with 30 mm…

Concept explainers

Calculation of Settlement

The vertical displacement of the structural foundation due to the loading from the superstructure is known as settlement. It is due to the reduction of air voids present in the soil. The amount of vertical displacement depends on the bearing capacity of the soil on which the foundation is laid. The effect of the settlement depends on the magnitude of settlement, uniformity, and the structural design of the structure. The maximum allowable settlement for residential and office buildings should be less than 18 mm, for industrial buildings, it is 38 mm and for commercial buildings, it is 25 mm.

Question

Example 22 a
For a normally consolidated clay (c' = 0) these are the
results for a consolidated drained triaxial test
Chamber pressure = 104 kN/m²
Deviator stress at failure = 125 kN/m²
a) Find the angle of friction, ' (Answer: 22)
b) Determine the angle 9 that failure plane makes with the
major principle plan (Answer: 56)
TOI-OHOMAI
Institute of Technology
Example 3
The equation of effective stress failure envelope for
normally consolidated clayey soil is
Tf = o'tan 27
A drained triaxial test was conducted with the same soil at
the chamber confining pressure of 100 kN/m². Calculate
the deviator stress at failure (Answer: 166.3 kN/m²)

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Step by step

Solved in 3 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

A dilatometer test (DMT) was conducted in a clay deposit. The water table was located at a depth of 3 mbelow theground surface. At 8 m depth the contact pressure (p1) was 280 kPa and the expansion stress (p2) was 350 kPa.Assume σo = 95 kPa at the 8 m depth and μ = 0.35. Determine (a) Coefficient of at-rest earth pressure Ko,(b) Overconsolidation ratio OCR and (c) Modulus of elasticity Es.
Problem 2: The following data were obtained in a direct shear test. ... 20 kPa Normal pressure .... Tangential Pressure Cohesion of soil 15 kPa 8 kPa Determine the following: a) Angle of internal friction, ø b) Compute the angle that the failure plane makes with the horizontal, 0. c) Compute the minimum principal stress. d) Compute the max. principal stress
the angle of internal frictional of a cohesive soil which was tested using tria-axial shear apparatus is equal to 26.57. failure occurred when the shearing stress is 250 kPa and the normal stress is 480 kPa. a. determine the maximum principal stress at failure, in kPa. round off to two decimal b. deternmine the cohesion of the soil in kPa. round off to two decimal c. determine the deviator stress at failure in kPa.round off to two decimal
A consolidated-drained tri-axial test was conducted on a normally consolidated clay. The results are as follows: O3 = 150 kN/m? (Aoa)f= 130 kN/m? Determine a. Angle of friction, o' b. Angle 0 that the failure plane makes with the major principal plane c. Find the normal stress o' and the shear stress tf on the failure plane d. Determine the effective normal stress on the plane of maximum shear stress
A normally consolidated soil was subjected to tri-axial test with the following data: cell pressure= 320 kPa; The specimen failed when the deviator stress is 460 kPa. Compute the normal stress in kPa on the plane of max shear stress a.550 b.141.42 c.208.9 d.119.03
A CD triaxial test was conducted on a loose sand. The axial stress was held constant and the radial stress was increased until failure occurred. At critical state, the radial stress was greater than the axial stress. Show that, using Mohr’s circle and geometry, the slip plane is inclined at (π/2)/2-fcs¢/2 to the horizontal plane.
Soil Mechanism
Problem 3: A vane shear test was conducted on a soft clay. The vane was 112 mm in height and 70 mm in diameter. It was pressed and fully penetrated into the clay with an applied torque, T. The test gave a result of corrected undrained shear strength of 34.65 kPa with a liquid limit of the soil equal to 60 and a plastic limit of 25. Determine the following: a) the torque T applied b) the unconfined compressive strength of clay c) the unconfined compression strength of clay in the remolded state if the soil sample has a sensitivity of 3.5.
Please correct solution
Note:- • Do not provide handwritten solution. Maintain accuracy and quality in your answer. Take care of plagiarism. • Answer completely. • You will get up vote for sure.
Q: A consolidated-drained tri-axial test was conducted on a normally consolidated clay. The results are as following: confining stress, G3 = 150 kN/m² and deviator stress, (Aod)t = 150 kN/m². i) Determine angle of friction, q; ii) Determine angle 0 that the failure plane makes with the major principal plane; iii) Find the normal stress and the shear stress ty on the failure plane; and iv) Determine the effective normal stress on the plane of maximum shear stress. Express your results in two decimal places.
1. Given the figure below plot the pore pressure, total stress and effective stress at the top, bottom and midpoint of each soil layer, provide a plot with all umerical values of depth and stress in tabular form and on a depth v stress plot. Oft Sand Vmoist = 122 pcf Ysat = 151 pcf I 12ft 30ft Clay Ysat = 144 pcf %3D 70ft Sand Ysat = 128 pcf 120ft