Given the values of AHn, ASxn, and T below, determineASuniv.Part AAHn = - 85 kJ , AS = - 153 J/K,T = 291 KExpress your answer using two significant figures.ASuniv =J/KSubmitPrevious Answers Request AnswerX Incorrect; Try Again; 4 attempts remainingPart BAHan = - 85 kJ , ASrxn = – 153 J/K,T = 751 KExpress your answer using one significant figure.?ASuniv =J/KSubmitRequest Answer Exercise 18.42Given the values of AHn, ASn, and T below, determineASuniv.Part CAHn =+85 kJ , ASrn =- 153 J/K,T = 291 KExpress your answer using two significant figures.ASuniv =J/KSubmitRequest AnswerPart DAHm = – 85 kJ , ASrxn =+ 153 J/K.T = 390 KExpress your answer using two significant figures.ASuniv =J/KSubmitRequest AnswerPart Etho roaction in nart A will be spontaneous, (Assume that all reactar

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Given the values of AHn, ASixn, and T below, determine ASuniv- Part A AHn =- 85 kJ , ASxn =- 153 J/K,T = 291 K Express your answer using two significant figures. ? ASuniv = J/K Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Part B AHn = – 85 kJ , ASrxn = – 153 J/K,T = 751 K Express your answer using one significant figure. ? ASuniv = J/K Submit Request Answer

Given the values of AHn, ASixn, and T below, determine ASuniv- Part A AHn =- 85 kJ , ASxn =- 153 J/K,T = 291 K Express your answer using two significant figures. ? ASuniv = J/K Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Part B AHn = – 85 kJ , ASrxn = – 153 J/K,T = 751 K Express your answer using one significant figure. ? ASuniv = J/K Submit Request Answer

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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2Na(s) + 2H2O(l)2NaOH(aq) + H2(g)H° = -369 kJ and S° = -15.3 J/KG° would be less than zero at temperatures (above, below) fill in the blank 1 K.Enter above or below in the first box and enter the temperature in the second box. Assume that H° and S° are constant.
2Fe2O3(s) 4Fe(s) + 302(g). Use the following data: So Fe(s) = 27.31 J/K, S° O2(g) = 205.15 J/K, S° Fe2O3(s) = 89.96 J/K. Express your answer in joules per kelvin to two decimal places. - ΑΣΦ AS°= = 468.4 © = ? J/K
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Directions: Solve for the following. 1. HESS' LAW Given thermochemical equations: N2(9) + O2(9) 2NO(9) AH = -180.5kJ %3D N29) + 3H20) 2NH3(9) + 3H2(g) → 2NH3(9) AH = -91.8k) AH = -483.6kJ 2H2(9) + 02(g) - 2H20g) %3D Calculate the enthalpy change: 4NH3(9) + 502o) → 4NO) + 6H20) AH =? 2. ENTHALPY OF FORMATION Calculate the AHf of the reaction: 2c0 + 020)→ 2C02)
in text form with proper workings and explanation for each and every part and steps with concept and introduction no AI no copy paste remember answer must be in proper format with all working!!!!!!!
3. (4.0 points) Without any detailed calculation consider the following equations and predict the sign of AS. a. N2(g) + 3H2 (g) → 2NH3 (g) b. 2H2(g) + O2(g) → 2H₂O (1) C. CH4 (g) +202 (g) → CO2 (g) + 2H₂O (1) d. 2N2 (g) +502 (g) → 2N20s (g)