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b) Construct an enthalpy cycle and calculate the enthalpy of combustion in each case using the above data. i) Ethane 2 C₂H6 (g) + 7 O2(g) → 4 CO2 (g) + 6 H₂O(1) H₂O = -285.5 CO₂=-393 C₂H6 = -83.6 ii) Ethene C₂H4 (g) + 302 (g) → 2CO2 (g) + 2H₂O (1) C₂H4 = +52.0 CO₂ = -393 H₂O = -285.5 iii) Hydrogen 2H₂(g) + O2(g) → 2H₂O (1) H₂O = -285.5

b) Construct an enthalpy cycle and calculate the enthalpy of combustion in each case using the above data. i) Ethane 2 C₂H6 (g) + 7 O2(g) → 4 CO2 (g) + 6 H₂O(1) H₂O = -285.5 CO₂=-393 C₂H6 = -83.6 ii) Ethene C₂H4 (g) + 302 (g) → 2CO2 (g) + 2H₂O (1) C₂H4 = +52.0 CO₂ = -393 H₂O = -285.5 iii) Hydrogen 2H₂(g) + O2(g) → 2H₂O (1) H₂O = -285.5

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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H2O = -285.5

CO2 = -393

C2H6 = -83.6

 

enthalpy cycle and enthalpy of combustion

b) Construct an enthalpy cycle and calculate the enthalpy of combustion in each case using the above data. i) Ethane 2 C₂H6 (g) + 7 O2(g) → 4 CO2 (g) + 6 H₂O(1) H₂O = -285.5 CO₂=-393 C₂H6 = -83.6 ii) Ethene C₂H4 (g) + 302 (g) → 2CO₂ (g) + 2H₂O (1) C₂H4 = +52.0 CO₂ = -393 H₂O = -285.5 iii) Hydrogen 2H₂ (g) + O2(g) → 2H₂O (1) H₂O = -285.5
Transcribed Image Text:b) Construct an enthalpy cycle and calculate the enthalpy of combustion in each case using the above data. i) Ethane 2 C₂H6 (g) + 7 O2(g) → 4 CO2 (g) + 6 H₂O(1) H₂O = -285.5 CO₂=-393 C₂H6 = -83.6 ii) Ethene C₂H4 (g) + 302 (g) → 2CO₂ (g) + 2H₂O (1) C₂H4 = +52.0 CO₂ = -393 H₂O = -285.5 iii) Hydrogen 2H₂ (g) + O2(g) → 2H₂O (1) H₂O = -285.5
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