Use the following information to answer the next question. Given the following data: P4(s) + 6Cl₂(g) → 4PCI3(g) 4PC15(g) → P4(s) + 10Cl₂(g) AH = -2439 kJ ΔΗ = +3438 kJ Using Hess's Law, the enthalpy of reaction for the following equation: PCI-(g) → PCl3(g) + Cl₂(g) is calculated to be Record your answer to two decimal places. Include sign; do not include units. kJ.

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Use the following information to answer the next question.
Given the following data:
P4(S) + 6Cl₂(g) → 4PC13(g)
A,H-2439 kJ
4PC15(g) → P4(s) + 10Cl₂(g) ΔΗ = +3438 kJ
Using Hess's Law, the enthalpy of reaction for the following equation: PCI5(g) → PCI3(g) + Cl₂(g) is calculated to be
Record your answer to two decimal places. Include sign; do not include units.
Use the following information to answer the next question.
Given the following data:
N₂H4(1) + CH4O(1)→ CH₂O(g) + N₂(g) + 3H₂(g) A-H = -37 kJ
N₂(g) + 3H₂(g) → 2NH3(g)
CH4O(1) CH₂O(g) + H₂(g)
ArH=-91.8 kJ
A,H = -65 kJ
Using Hess's Law, the enthalpy of reaction for the following equation: N₂H4(1) + H₂(g) → 2NH3(g) is calculated to be
Record your 2-digit answer. Include sign; do not include units.
◆
kJ.
kJ.
Transcribed Image Text:Use the following information to answer the next question. Given the following data: P4(S) + 6Cl₂(g) → 4PC13(g) A,H-2439 kJ 4PC15(g) → P4(s) + 10Cl₂(g) ΔΗ = +3438 kJ Using Hess's Law, the enthalpy of reaction for the following equation: PCI5(g) → PCI3(g) + Cl₂(g) is calculated to be Record your answer to two decimal places. Include sign; do not include units. Use the following information to answer the next question. Given the following data: N₂H4(1) + CH4O(1)→ CH₂O(g) + N₂(g) + 3H₂(g) A-H = -37 kJ N₂(g) + 3H₂(g) → 2NH3(g) CH4O(1) CH₂O(g) + H₂(g) ArH=-91.8 kJ A,H = -65 kJ Using Hess's Law, the enthalpy of reaction for the following equation: N₂H4(1) + H₂(g) → 2NH3(g) is calculated to be Record your 2-digit answer. Include sign; do not include units. ◆ kJ. kJ.
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