Given the following thermochemical equations → 4PCI3(g) P4(s) + 6CI2(g) 4PCI5(g) → P4(s) + 10CI 2(g) AH = -2439 kJ/mol AH = 3438 kJ/mol %3D find the AH for the reaction below, PCI5(g) → PC|3(g) + Cl2(g)

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Given the following thermochemical equations
P4(s) + 6C12(g)
4PCI3(g)
AH = -2439 kJ/mol
4PCI5(g) → P4(s) + 10CI 2(g)
AH = 3438 kJ/mol
find the AH for the reaction below,
PCI5(g) → PC|3(g) + Cl2(g)
O A) +249.8 kJ/mol
O B) +999 kJ/mol
O C) -999 kJ/mol
O D) -249.8 kJ/mol
Transcribed Image Text:Given the following thermochemical equations P4(s) + 6C12(g) 4PCI3(g) AH = -2439 kJ/mol 4PCI5(g) → P4(s) + 10CI 2(g) AH = 3438 kJ/mol find the AH for the reaction below, PCI5(g) → PC|3(g) + Cl2(g) O A) +249.8 kJ/mol O B) +999 kJ/mol O C) -999 kJ/mol O D) -249.8 kJ/mol
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