4. Use the information below to calculate Sº 3 PbBr2(s) Pb²+ (aq) + 2 Br(aq) Substance AHºf (kJ/mol) so (J/K) Pb2+ (aq) -1.7 10.5 Br (aq) -121.5 82.4 PbBr2(s) -282.4 ??? Report your answer in J/K with one decimal place, but do not write the units. Include a for BaF2(s). Ksp = 1.3 x 10-6 if applicable.

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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To solve for PbBr 2 not BaF2(s)
(3) H2(g) + O2(g)
H₂O2(1)
AGO = ???
Report your answer in kJ with one decimal place, but do not write the units. Include a -
Selected Answer: [None Given]
4. Use the information below to calculate
So
for BaF2(s).
x
PbBr2(s)
Pb²+ (aq) +
2 Br (aq)
=
Ksp = 1.3 x 10-6
Substance
AHºf (kJ/mol)
so (J/K)
Pb²+ (aq)
-1.7
10.5
Br (aq)
-121.5
82.4
PbBr2(s)
-282.4
???
-
Report your answer in J/K with one decimal place, but do not write the units. Include a
Selected Answer: 275.3
Response Feedback: Very tedious algebra. Be very careful.
Question 4
Question 5
if applicable.
if applicable.
Transcribed Image Text:(3) H2(g) + O2(g) H₂O2(1) AGO = ??? Report your answer in kJ with one decimal place, but do not write the units. Include a - Selected Answer: [None Given] 4. Use the information below to calculate So for BaF2(s). x PbBr2(s) Pb²+ (aq) + 2 Br (aq) = Ksp = 1.3 x 10-6 Substance AHºf (kJ/mol) so (J/K) Pb²+ (aq) -1.7 10.5 Br (aq) -121.5 82.4 PbBr2(s) -282.4 ??? - Report your answer in J/K with one decimal place, but do not write the units. Include a Selected Answer: 275.3 Response Feedback: Very tedious algebra. Be very careful. Question 4 Question 5 if applicable. if applicable.
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