Athot 45.3°C -70.3°C = -25.0°C Atcold 45.3°C-21.5°C = 23.8°C Part A Calculate the heat capacity of the calorimeter good = (45.03 g)x (4-184 g +²2) * (23-8²2) = 4484.1 9 hot = (49.9191g) x (4.184, +2) × (-25.0%) = -5221.5 q cal = -ghot - gcold 19 cal = 5221.5-4484.1 q cal = 737.4J 1737.4 = 30.983 -> 31.057/°27 HC-310 Jọc 23.8°C 3377 : 73741J +4=184J7 gx²C x 94.95g=438.255/2x of the calorimeter 23.8°C
Athot 45.3°C -70.3°C = -25.0°C Atcold 45.3°C-21.5°C = 23.8°C Part A Calculate the heat capacity of the calorimeter good = (45.03 g)x (4-184 g +²2) * (23-8²2) = 4484.1 9 hot = (49.9191g) x (4.184, +2) × (-25.0%) = -5221.5 q cal = -ghot - gcold 19 cal = 5221.5-4484.1 q cal = 737.4J 1737.4 = 30.983 -> 31.057/°27 HC-310 Jọc 23.8°C 3377 : 73741J +4=184J7 gx²C x 94.95g=438.255/2x of the calorimeter 23.8°C
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Could someone check this for me, please? I am unsure which part, if any, is being done correctly. The water weights are as they are on the page (first # in qcold and first # in qhot).

Transcribed Image Text:Athot 45.3°C -70.3°C = -25.0°C
Atcold 45.3°C-21.5°C = 23.8°C
Part A Calculate the heat capacity of the calorimeter
qedd = (45.03g)x (4.184 79 +²2) * (23.8²2) = 4484.1
9 hot = (49.9191g) x (4.184 + 2) × (-25.0%) = -5221.5
a cal =-ghot - gcold
q
cal = 5221.5-4484.1
qcal = 737.4J
737.4 = 30.983 > 31.057°27
HC=31.0
3377
HC: 757141J + 4.184 J/g x°C x 94.95@=438.255/€
g
of the
Calorimeter 23.8°C
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