Given a horizontal beam AB with two supports A and B is subjected to an external distributed load w=100N/m, and two bending moments M, 50N.m and M2-200N.m as shown in the following figure. M₁ A W 1 m 4 m 2 m a) The force due to distributed load wis b) The resultant force of the equivalent system is M2 B N located m measured from A. N downward located m measured from A.

Given a horizontal beam AB with two supports A and B is subjected to an external distributed load w=100N/m, and two bending moments M, 50N.m and M2-200N.m as shown in the following figure. M₁ A W 1 m 4 m 2 m a) The force due to distributed load wis b) The resultant force of the equivalent system is M2 B N located m measured from A. N downward located m measured from A.

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter1: Introduction To Statics

Section: Chapter Questions

Problem 1.12P: A differential equation encountered in the vibration of beams is d4ydx4=2D where x = distance...

See similar textbooks

Similar questions

For the force system shown in figure below, the resultant of the force systemis _ N. 6ON Y 20" 175 N 35 x 18 B0 N 200 N
The unstretched length of springs AB and AC are 0.8485 m and 3 m, respectively. The weight of the box is 84 N. The system is in equilibrium and the springs are stretched, find the following and show full solutions and fbda) Force in spring AB and force in spring ACb) Resultant force of the systemc) Direction of resultant from the horizontal
The unstretched length of springs AB and AC are 0.8485 m and 3 m, respectively. The weight of the box is 84 N. The system is in equilibrium and the springs are stretched, find the following with complete fbda) Force in spring AB and force in spring ACb) Resultant force of the systemc) Direction of resultant from the horizontal
A pole OA is subjected to two forces FAB and FAC. The force in cable AB is 3.5 KN. Given FAC -0.948)-2.844k (KN) 5m B 2m 4m 6 m The force FAB (KN) as a vector is represented as The projection of FAC along AB in KN is The angle between AB and AC is 1.098i+ 0.274j-1.648k 0.842i+ 0.561j-2.064k| 0.8421-0.561j-2.064k 1.9211+0.48j-2.884k 2.473 2.017 1.434 1.856 44.87 34.46 51.04 37.65 27
3) Find the forces developed in beams FE, CE, and CD. State whether they're in tension or compression. A 20 № 20cm f B 4444 20cm 20cm 20cm 100 N 3 9 5 20cm с E 20cm 55N
3m 2m Q32] 60 YA 300 N Find the resultant R of the force System Shown in figure. Show it's position with-respect- to point C. Also Show Where it cuts the mem ber "CD". 1m 2m 3 m 250N D. 400 N-m Ane R= 991 N 60 O = 63. d = 2-354 m تېد المحصل عن نقطت¢ %3D 500N a= 2.642 m A [Q337
3 of on Given the horizontal beam AB with two supports Pin A and Roller B. The system is subjected to external loads as shown in the following figure. 4 KN.m A 2 m 2 m $OK b) The resultant force of the equivalent system is c) The vertical support reactions at pin A is 3 KN/m a) The force due to distributed load w is B 77777 KN located located m measured from B. Im measured from A. KN. KN and at roller B is
Given a horizontal beam AB with two supports A and B is subjected to an external distributed load w-50N/m, and an external force F-100N as shown in the following figure. F A 77777 XX 1 m 1m a) The force due to distributed load wis 3 m b) The resultant force of the equivalent system is W B 77777 N located m measured from A. N downward located m measured from A. Time lef
Vibration Engineering Mechanical Engineering
A:0. docs.google.com/forms/d/e/1FAlpQLSeE : مطلوب Untitled Se F1 =5 kN F2 = 13 kN 45 B = 60 F3 = 4 kN 4 m 8 m D F4 = 22 kN a = 30° FS = 4 kN Vhat is the resultant moment of the five forces acting on the rod about point B? 0.5 kN.m b) 49.5 kN.m c) 39.1 kN.m d) 18.5 kN.m e) 9.1 kN.m f) 21.1 Vhat is the resultant moment of the five forces acting on the rod about point E? 22.8 kN.m b) - 2.8 kN.m c) – 18.9 kN.m d) - 8.1 kN.m - 12.7 kN.m f) -7 Vhat is the moment of the force F1 about point D? 27.8 kN.m b) - 12.8 kN.m c) - 38.9 kN.m d) - 19.1 kN.m e) - 32.7 kN.m f) - 29 Vhat is the moment of the force F2 about point E? .5 kN.m b) 55.5 kN.m el 14.2 kN.m d1 32.5 kN.m el 7.1 kN.m. A 84.1
The following diagram corresponds to questions 1 to 3. A beam rests on two sharp edges as shown on the image. The beam has a length of 7,50 m and a mass of 4,25 kg. Object 1 has a mass of 1,50 kg; object 2 has a mass of 2,35 kg. Point P is 0,50 m form the center of the beam. d 2 Pl CG 1. How much is the torque done by object 1 around point P? A. 55,2 N*m B. 7,36 N*m С. 62,5 N*m D. Object 1 doesn't exert a torque.
5 kN/m 2 kN/m A 4 m- 2 m What is the magnitude of the resultant force equivalent the distributed load applied to this beam (kN)?