Given a horizontal beam AB with two supports A and B is subjected to an external distributed load w=100N/m, and two bending moments M, 50N.m and M2-200N.m as shown in the following figure. M₁ A W 1 m 4 m 2 m a) The force due to distributed load wis b) The resultant force of the equivalent system is M2 B N located m measured from A. N downward located m measured from A.
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- 3) Find the forces developed in beams FE, CE, and CD. State whether they're in tension or compression. A 20 № 20cm f B 4444 20cm 20cm 20cm 100 N 3 9 5 20cm с E 20cm 55NA beam is subjected to some couple moments as shown in the figure and parameter table. With counter-clockwise as positive, what is the resultant couple moment? F₁ 1 parameter L₁ L2 L3 F₁ F2 0 1 value 3 2 0.75 175 125 70 The resultant moment is F₁ 1 units ft ft ft lb lb O Ө Ꮎ 080 BY NO SA 2021 Cathy Zupke CC F₂ F₂ lb-ftThe following diagram corresponds to questions 1 to 3. A beam rests on two sharp edges as shown on the image. The beam has a length of 7,50 m and a mass of 4,25 kg. Object 1 has a mass of 1,50 kg; object 2 has a mass of 2,35 kg. Point P is 0,50 m form the center of the beam. CG 1. How much is the torque done by object 1 around point P? A. 55,2 N*m B. 7,36 N*m C. 62,5 N*m D. Object 1 doesn't exert a torque. 2. How much is the torque done by the force of gravity of the beam around point P? A. 20,8 N*m N-m ך177 .B C. 156 N*m D. 313 N*m 3. If you needed to cancel the nomal forces of the two objects, where you should place object 2? The axis of rotation is point P. A. 3,30 m from point B. 9,18 m from point P C. 5,69 m from point P D. 3,62 m from point P
- A bent tube is attached to a wall with brackets as shown. . A force of F = 980 lb is applied to the end of the tube with direction indicated by the dimensions in the figure. a.) Determine the force vector F in Cartesian components. → → b.) Resolve the force vector F into vector components parallel and perpendicular to the position vector rDA. Express each of these vectors in Cartesian components. 2013 Michael Swanbom cc 10 BY NC SA g x B A א Z FK с кая b Values for dimensions on the figure are given in the table below. Note the figure may not be to scale. Be sure to align your cartesian unit vectors with the coordinate axes shown in the figure. Variable Value a 8 in 12 in с 15 in 36 in h 23 in g 28 in a. F = b. FDA = = ( + k) lb k) lb FIDA = 2 + k) lb3) A point mass is attached to one end of a beam levered against a spike which acts as the pivot. The point mass weighs 250N and the beam has a uniform mass of 10kg and is 8m long. Parts a and b Part c Fapplied 3 of 6mov 1m 8m Krist 0 = 60° Scale 250 N Scale a. If a scale placed beneath the point mass reads 250N, what is the magnitude and direction for the force at the pivot point? Direction: North, 90° from x-axis Magnitude to k* 250N = 2500 N b. For the same scenario, how far must the pivot point be located relative to the left edge of the beam? (Hint, both the boxes weight and the force from the scale act at the farthest right edge of the beam.) www.acta 0672nos onl c. The pivot is then moved to be 6m from the left edge of the beam which now makes a 60 angle with the floor. How much downward force would be needed at the left-most edge of the beam to reduce the reading on the scale to zero? (Hint: the beam is still in static eq. when the scale reads zero.)Two forces are acting on the vertical pole, as depicted in the figure and parameter list. Calculate the moment about O for each force. Determine which direction the forces will rotate the pole. 0 BY NO SA 2021 Cathy Zupke parameter L₁ L2 F₁ F₂ 0 e value units 4 ft 10 ft 70 lb 70 70 lb D The moment about O from F₁ The moment about O from F₂ = counterclockwise no moment F₁ L₁ lb-ft lb-ft Choose which direction the pole will tend to rotate: O clockwise O L₂ F₂ 41 5 3
- Q3: Three forces are acting on a steel plate with 4m length by 4m width shown in figure. These three forces are required to cause a horizontal resultant acting through point A. If F = 504N, 1) The value of horizontal resultant R is: E A D 853.814N + O 796.894N → O 711.512N - O 640.361N → O None of theseGW4 Given: Two forces are acting on a pipe as shown in the figure. The magnitude and the coordinate direction Find: angles of the resultant force. F2 = 81 lb Plan: 1) Find the forces along CA and F = 100 lb CB in the Cartesian vector form. 4 ft 2) Add the two forces to get thc yresultant force, FR. 3) Determine the magnitude and the coordinate angles of FR. B. 3 ft 7 ft 40 4 ftTwo couple forces F = 67N, F - 61N, act on the frame and given that d- 4m and 0- 28". The other length parameters are a = 4m, b- 8m, C- 12m, and e- 12m. Compute the moment by the following methods: -F, -F1 F1 a) Find the moment of each couple by using cross product and add them up. M: kị N m b) Sum up the moments of all forces component about point B resolve forces into a and y components N- m
- The crate weighing 400 lb is supported by three ropes concurrent at B.Find the forces in ropes AB and BC if P = 460 lb.please box out or highlight all the answersF1 F2 a C F3 F4 E Consider the following values: - F5 a = 1 m; b = 3 m; c = 7 m; d = 3 m; FI = 3 kN; F2 = 11 kN; F3 = 2 kN; F4 = 20 kN; F5 = 2 kN; a = 30°, e = 60° B= 30° 5] What is the moment of the force F2 about point E? a) 81.7 IN.m b) 78.1 KN.m c) 64.6 KN.m d) 73.1 KN.m e) 54.6 kN.m f) 61.3 KN.m