### Transcription for Educational Website:#### Diagram Explanation:The image shows a simply supported beam with a non-uniform distributed load. The beam is labeled with two support points, A and B. - **Support A**: Situated on the left end of the beam.- **Support B**: Located 4 meters from support A along the beam.The total length of the beam is 6 meters from point A to point x on the right side.#### Load Distribution:The distributed load changes linearly along the beam:- At the left end (point A), the load starts at 2 kN/m.- At point x, 6 meters from A, the load increases to 5 kN/m.The distributed load is represented by several downward arrows, which illustrate the direction of the load acting on the beam.#### Problem Statement:The question accompanying the diagram asks:"What is the magnitude of the resultant force equivalent to the distributed load applied to this beam (kN)?"This requires calculating the total force resulting from integrating the varying load over the length of the beam.

Sol:- Since the load is given in the diagram is a combination of triangular load and…

Answered: What is the magnitude of the resultant…

Engineering

Mechanical Engineering

What is the magnitude of the resultant force equivalent the distributed load applied to this beam (kN)?

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Types of loading

In mechanical terminology, the term load indicates that external force/weight, either constant or variable, acts on a mechanical member/structure. The weight of an object of a specific material is also an external load, and the external force that works on a structure comes under the categories of loading. The external load generates its effects as stress and strain in the structure.

Question

### Transcription for Educational Website:

#### Diagram Explanation:

The image shows a simply supported beam with a non-uniform distributed load. The beam is labeled with two support points, A and B.

- **Support A**: Situated on the left end of the beam.
- **Support B**: Located 4 meters from support A along the beam.

The total length of the beam is 6 meters from point A to point x on the right side.

#### Load Distribution:

The distributed load changes linearly along the beam:

- At the left end (point A), the load starts at 2 kN/m.
- At point x, 6 meters from A, the load increases to 5 kN/m.

The distributed load is represented by several downward arrows, which illustrate the direction of the load acting on the beam.

#### Problem Statement:

The question accompanying the diagram asks:

"What is the magnitude of the resultant force equivalent to the distributed load applied to this beam (kN)?"

This requires calculating the total force resulting from integrating the varying load over the length of the beam.

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