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Q: */Create all the possible origin/destinations from the airport codes provided. Load the…
A: */Create all the possible origin/destinations from the airport codes provided. Load the…
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Q: Please help me debug this code, expected output is attached below
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Q: // FILE: DPQueue.h // CLASS PROVIDED: p_queue (priority queue ADT) // // TYPEDEFS and MEMBER…
A: The detail code is given below:
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Max Function
Statistical function is of many categories. One of them is a MAX function. The MAX function returns the largest value from the list of arguments passed to it. MAX function always ignores the empty cells when performing the calculation.
Power Function
A power function is a type of single-term function. Its definition states that it is a variable containing a base value raised to a constant value acting as an exponent. This variable may also have a coefficient. For instance, the area of a circle can be given as:
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- What happens when a programmer attempts to access a node's data fields when the node variable refers to None? How do you guard against it? *PYTHONAssume a Node class has been defned using the Node class implenentation in your textbook, except that the data members have been declared public instead of private. This means that the code shown below has direct access to thse data rembers def ned inside the Node class. Type the EXACT output of the following code segnent You rmay assune that the code cormpiles and executes withcut errors. Node *pttl/ Node; ptrl->item R", pErl->nextE nullptr: Lop ptrl, ptr2 nevị Node: ptr2->item o) PEr2-2next = ptr1; top = ptr2; ptrl prr1->ite m new Nade; pEr1-next = top: vnile ipts1 1=nullptr)- cout ite XO perl = ptrt->hext cout#include<iostream>#include<string>#include <cstdlib>#include <ctime>#include<time.h>#include <iomanip>using namespace std; void merge(string a[], string b[], int left, int mid, int right) {int nL = mid - left + 1;int nR = right - mid;string leftA[nL], rightA[nR], leftB[nL], rightB[nR];for(int i = 0; i < nL; i++) {leftA[i] = a[nL+i];leftB[i] = b[nL+i];}for(int i = 0; i < nR; i++) {rightA[i] = a[mid+i+1];rightB[i] = b[mid+i+1];}int i = 0, j = 0, k = left;while(i < nL && j < nR) {if(leftA[i] <= rightA[j]) {a[k] = leftA[i];b[k] = leftB[i];i++;}else {a[k] = rightA[j];b[k] = rightB[j];j++;k++;}}while(i < nL) {a[k] = leftA[i];b[k] = leftB[i];i++;k++;}while(j < nR) {a[k] = rightA[j];b[k] = rightB[j];j++;k++;}} void mergeSort(string a[], string b[], int left, int right) {int mid;if(left < right) {mid = left + (right-1)/2;mergeSort(a,b,left,mid);mergeSort(a,b,mid+1,right);merge(a,b,left,mid,right);}} int menu() {int…#include <iostream>#include <list>#include <string>#include <cstdlib>using namespace std;int main(){int myints[] = {};list<int> l, l1 (myints, myints + sizeof(myints) / sizeof(int));list<int>::iterator it;int choice, item;while (1){cout<<"\n---------------------"<<endl;cout<<"***List Implementation***"<<endl;cout<<"\n---------------------"<<endl;cout<<"1.Insert Element at the Front"<<endl;cout<<"2.Insert Element at the End"<<endl;cout<<"3.Front Element of List"<<endl;cout<<"4.Last Element of the List"<<endl;cout<<"5.Size of the List"<<endl;cout<<"6.Display Forward List"<<endl;cout<<"7.Exit"<<endl;cout<<"Enter your Choice: ";cin>>choice;switch(choice){case 1:cout<<"Enter value to be inserted at the front: ";cin>>item;l.push_front(item);break;case 2:cout<<"Enter value to be inserted at the end:…C++ Data Structure:Create an AVL Tree C++ class that works similarly to std::map, but does NOT use std::map. In the PRIVATE section, any members or methods may be modified in any way. Standard pointers or unique pointers may be used.** MUST use given Template below: #ifndef avltree_h#define avltree_h #include <memory> template <typename Key, typename Value=Key> class AVL_Tree { public: classNode { private: Key k; Value v; int bf; //balace factor std::unique_ptr<Node> left_, right_; Node(const Key& key) : k(key), bf(0) {} Node(const Key& key, const Value& value) : k(key), v(value), bf(0) {} public: Node *left() { return left_.get(); } Node *right() { return right_.get(); } const Key& key() const { return k; } const Value& value() const { return v; } const int balance_factor() const {…C++ ProgrammingTopic: stacks queues and dequesBelow is the initial program of the main file, only modify the main file, sllstack file also provided for the reference of the main. See attached photo for instructions. main.cpp #include <iostream> #include <cstring> #include "sllstack.h" using namespace std; int main(int argc, char** argv) { SLLStack* stack = new SLLStack(); int test; string str; cin >> test; switch (test) { case 0: getline(cin, str); // PERFORM SOLUTION TO BRACKETS PROBLEM HERE // FYI: Place your variable declarations, if any, before switch. break; case 1: stack->push('a'); stack->push('b'); stack->push('c'); cout << stack->pop() << endl; cout << stack->pop() << endl; cout << stack->pop() << endl; cout << stack->isEmpty()…In this code: #include <iostream> #include <string> using namespace std;// Node struct to store data for each song in the playliststruct Node { string data; Node * next;};// Function to create a new node and return its addressNode * getNewNode(string song) { Node * newNode = new Node(); newNode -> data = song; newNode -> next = NULL; return newNode;}// Function to insert a new node at the head of the linked listvoid insertAtHead(Node ** head, string song) { Node * newNode = getNewNode(song); if ( * head == NULL) { * head = newNode; return;} newNode -> next = * head; * head = newNode;}// Function to insert a new node at the tail of the linked listvoid insertAtTail(Node ** head, string song) { Node * newNode = getNewNode(song); if ( * head == NULL) { * head = newNode; return; } Node * temp = * head; while (temp -> next != NULL) { temp = temp -> next; } temp -> next = newNode;}// Function to remove a node from the linked listvoid removeNode(Node ** head,…//Can you explain how this code work or the meaning of this code?#include <iostream>using namespace std;struct Node {int data;struct Node *next;};struct Node* head = NULL;struct Node* rhead = NULL;int count1;//insert at front for reverselistvoid insertfront(int data){Node* new_node = (Node*) malloc(sizeof(Node)); new_node->data = data; new_node->next = rhead; rhead=new_node;}//insert at endvoid insert(int new_data){Node* ptr;ptr = head;Node* new_node = (Node*) malloc(sizeof(Node)); new_node->data = new_data; new_node->next = NULL;if (head == NULL) { head = new_node; } else{while (ptr->next!= NULL) { ptr = ptr->next;}ptr->next=new_node;}count1++;}//display listvoid display() {struct Node* ptr;ptr = head;if(head==NULL){cout<<"Sorry the list is empty";return;}while (ptr != NULL) {cout<< ptr->data <<" ";ptr = ptr->next;}cout<<endl;}//delete datavoid deletedata(int data){Node* ptr,*ptrpre;ptr = head;if (head == NULL) {…#ifndef NODES_LLOLL_H#define NODES_LLOLL_H #include <iostream> // for ostream namespace CS3358_SP2023_A5P2{ // child node struct CNode { int data; CNode* link; }; // parent node struct PNode { CNode* data; PNode* link; }; // toolkit functions for LLoLL based on above node definitions void Destroy_cList(CNode*& cListHead); void Destroy_pList(PNode*& pListHead); void ShowAll_DF(PNode* pListHead, std::ostream& outs); void ShowAll_BF(PNode* pListHead, std::ostream& outs);} #endif #include "nodes_LLoLL.h"#include "cnPtrQueue.h"#include <iostream>using namespace std; namespace CS3358_SP2023_A5P2{ // do breadth-first (level) traversal and print data void ShowAll_BF(PNode* pListHead, ostream& outs) { cnPtrQueue queue; CNode* currentNode; queue.push(lloLLPtr->getHead()); while (!queue.empty()) { currentNode = queue.front(); queue.pop(); if…#include <stdlib.h>#include <string.h>#include <stdio.h>#include "stack.h" /* Checks whether the parenthesis in str are balanced using the stack. Returns 1, if balanced 0, if unbalanced An expression has balanced parenthesis if it satisfies the following conditions: 1. The first observed parenthesis cannot be a closing parenthesis 2. All opening parentheses should have matching closing parenthesis 3. The parentheses cannot be intertwined but can be nested*/int parenthesis_balance_check(LINKED_STACK stack, char* str); int main() { return 0;} PLEASE ONLY USE "C" LANGUAGE, DONT USE "C#" AND "C++"Write a function that takes two queue structures as _parameters: original queue and modified queue. The function finds the numbers greater than or equal to 5 in the original queue and places 1 to the same position in the modified queue. For the numbers less than 5, modified queue element has 0. Assume that two input queues have the same number of elements at a time. Example Original Queue: 35 16 28 Example Modified Queue: O1101 void modifyqueue (struct queue *org, struct queue *mod){ Note that you need printqueue function to display the queue contents in order to verify your solutions.//main.cpp #include<iostream>#include<cmath>#include<string>#include<cstring>#include<algorithm>#include<list>using namespace std; #include "Dog.h" void popDogs(list<Dog>&); /** Change NOTHING above this line **/ //TODO, overload << operator//here's a startostream& operator<<(ostream& os, Dog& d){ //Insert code here so that when a Dog is output, it is done as: //dogName weighs weight pounds. //Like: //Spot weighs 28 pounds. //Don't forget the period at the end. Do NOT include an endl at the end of the line. os<< d.dogName<< " weighs " << d.weight << " pounds."; return os; } int main(){ //TODO, instantiate list of Dog variable called kennel. list<Dog> kennel; //TODO, call the popDogs function passing the kennel variable declared above popDogs(kennel); //This code will sort the list of Dog using the less-than operator kennel.sort();…SEE MORE QUESTIONS