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for the The equilibrium constant (K) decomposition of gaseous H,O; 63. H,O = Hye) + 1 O2) is related to degree of dissociation (a) at a total pressure P, given by:- 3,1/2 a°p!/2 (1) Kp = (1+a) (2 + a) '/2 3,3/2 (2) Кр — %3D (1 – a) (2 + a) '/² 3/2. a2p? (1 – a) (2 + a) '/2 (3) Kp (4) Kp: a 3/2p1/2 (1- a) (2+ a) /2

for the The equilibrium constant (K) decomposition of gaseous H,O; 63. H,O = Hye) + 1 O2) is related to degree of dissociation (a) at a total pressure P, given by:- 3,1/2 a°p!/2 (1) Kp = (1+a) (2 + a) '/2 3,3/2 (2) Кр — %3D (1 – a) (2 + a) '/² 3/2. a2p? (1 – a) (2 + a) '/2 (3) Kp (4) Kp: a 3/2p1/2 (1- a) (2+ a) /2

Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter12: Gaseous Chemical Equilibrium
Section: Chapter Questions
Problem 36QAP: At a certain temperature, K=0.29 for the decomposition of two moles of iodine trichloride, ICl3(s),...
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The equilibrium constant (K) for decomposition of gaseous H,O; the 63. 1 H;Oe = Hu) + Oe is related to degree of 2 (), dissociation (a) at a total pressure P, given by:- a³p!/2 (1) Kp = (1 +a) (2 + a) '/² %3D 3/2 (2) Кр - (1 – a) (2 + a) '/2 3/2,2 (3) Kp= (1 – a) (2 + a) '/² (4) Kp = a?pl/2 3/2,1/2 (1 – a) (2 + a) '/2
Transcribed Image Text:The equilibrium constant (K) for decomposition of gaseous H,O; the 63. 1 H;Oe = Hu) + Oe is related to degree of 2 (), dissociation (a) at a total pressure P, given by:- a³p!/2 (1) Kp = (1 +a) (2 + a) '/² %3D 3/2 (2) Кр - (1 – a) (2 + a) '/2 3/2,2 (3) Kp= (1 – a) (2 + a) '/² (4) Kp = a?pl/2 3/2,1/2 (1 – a) (2 + a) '/2
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