Select the reaction for which Kp = Kc. O 2CO,(g) + 2CF,(g) =4 COF,(g) O NH,NO,(s) = N,O(g) + 2 H,O(g) O 2H,S(g) + SO,(g) = 3 S(s) + 2 H,O(g) O 2 Na,O,(8) + 2CO,(g) =2 Na, CO, (s) +0,(g)

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Chapter1: Chemical Foundations
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### Select the reaction for which \( K_p = K_c \).

1. \( 2 \text{CO}_2 (g) + 2 \text{CF}_4 (g) \rightleftharpoons 4 \text{COF}_2 (g) \)

2. \( \text{NH}_4\text{NO}_3 (s) \rightleftharpoons \text{N}_2\text{O} (g) + 2 \text{H}_2\text{O} (g) \)

3. \( 2 \text{H}_2\text{S} (g) + \text{SO}_2 (g) \rightleftharpoons 3 \text{S} (s) + 2 \text{H}_2\text{O} (g) \)

4. \( 2 \text{Na}_2\text{O}_2 (s) + 2 \text{CO}_2 (g) \rightleftharpoons 2 \text{Na}_2\text{CO}_3 (s) + \text{O}_2 (g) \)

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For this type of problem, when asked to determine if \( K_p = K_c \), it typically means finding the reaction for which the change in the number of moles of gas (\( \Delta n \)) is zero, as:

\[ K_p = K_c (RT)^{\Delta n} \]

If \( \Delta n = 0 \), then:

\[ K_p = K_c \]

### Explanation:

- Calculate \( \Delta n \) by subtracting the moles of gaseous reactants from the moles of gaseous products.

1. ***Reaction 1:*** 
   - \( \Delta n = 4 - (2 + 2) = 0 \)

2. ***Reaction 2:*** 
   - \( \Delta n = (1 + 2) - 0 = 3 \)

3. ***Reaction 3:***
   - \( \Delta n = 2 - (2 + 1) = -1 \)

4. ***Reaction 4:***
   - \( \Delta n = 1 - 2 = -1 \)

Based on these calculations, Reaction 1 is the reaction for which \( K_p = K_c \),
Transcribed Image Text:### Select the reaction for which \( K_p = K_c \). 1. \( 2 \text{CO}_2 (g) + 2 \text{CF}_4 (g) \rightleftharpoons 4 \text{COF}_2 (g) \) 2. \( \text{NH}_4\text{NO}_3 (s) \rightleftharpoons \text{N}_2\text{O} (g) + 2 \text{H}_2\text{O} (g) \) 3. \( 2 \text{H}_2\text{S} (g) + \text{SO}_2 (g) \rightleftharpoons 3 \text{S} (s) + 2 \text{H}_2\text{O} (g) \) 4. \( 2 \text{Na}_2\text{O}_2 (s) + 2 \text{CO}_2 (g) \rightleftharpoons 2 \text{Na}_2\text{CO}_3 (s) + \text{O}_2 (g) \) --- For this type of problem, when asked to determine if \( K_p = K_c \), it typically means finding the reaction for which the change in the number of moles of gas (\( \Delta n \)) is zero, as: \[ K_p = K_c (RT)^{\Delta n} \] If \( \Delta n = 0 \), then: \[ K_p = K_c \] ### Explanation: - Calculate \( \Delta n \) by subtracting the moles of gaseous reactants from the moles of gaseous products. 1. ***Reaction 1:*** - \( \Delta n = 4 - (2 + 2) = 0 \) 2. ***Reaction 2:*** - \( \Delta n = (1 + 2) - 0 = 3 \) 3. ***Reaction 3:*** - \( \Delta n = 2 - (2 + 1) = -1 \) 4. ***Reaction 4:*** - \( \Delta n = 1 - 2 = -1 \) Based on these calculations, Reaction 1 is the reaction for which \( K_p = K_c \),
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