For a 208-V three-phase ideally balanced system shown below, Find: a) The magnitude of the line current I b) The magnitude of the load's line and phase voltages VLL and VDL c) The real, reactive, and the apparent powers consumed by the load; d) The power factor of the load. Von=1202-240° Vbn = 120-120° 2* an=12020° 0.06 Ω www 10.12 Ω 0.06 Ω 10.12 Ω ww 208 V น. น Z₁ = 12 +19 Zo 0.06 Ω 10.12 Ω www V, 208 √√3 = 120 V
For a 208-V three-phase ideally balanced system shown below, Find: a) The magnitude of the line current I b) The magnitude of the load's line and phase voltages VLL and VDL c) The real, reactive, and the apparent powers consumed by the load; d) The power factor of the load. Von=1202-240° Vbn = 120-120° 2* an=12020° 0.06 Ω www 10.12 Ω 0.06 Ω 10.12 Ω ww 208 V น. น Z₁ = 12 +19 Zo 0.06 Ω 10.12 Ω www V, 208 √√3 = 120 V
Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter2: Fundamentals
Section: Chapter Questions
Problem 2.42P: A balanced -connected impedance load with (12+j9) per phase is supplied by a balanced three-phase...
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
Transcribed Image Text:For a 208-V three-phase ideally balanced system shown below,
Find:
a) The magnitude of the line current I
b) The magnitude of the load's line and phase voltages VLL and VDL
c) The real, reactive, and the apparent powers consumed by the load;
d) The power factor of the load.
Von=1202-240°
Vbn = 120-120°
2*
an=12020°
0.06 Ω
www
10.12 Ω
0.06 Ω
10.12 Ω
ww
208 V
น.
น
Z₁ = 12 +19
Zo
0.06 Ω
10.12 Ω
www
V,
208
√√3
= 120 V
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