Example 6: Nodal Analysis In the following circuit: If 11=20cos(5t)[A], 12=10cos(5t)[A] R1=4, R2=2, C1=C2=0.2, L1=L2=0.2| Find the node voltages V1 & V2? Solution: LI m C2 V1 ++ V2 IIRI C1 12 L2 22 R2 12 Draw the equivalent circuit in frequency domain: | Apply KCL at V1: Apply KCL at V2: V₁(t)= V2(t)=

Example 6: Nodal Analysis In the following circuit: If 11=20cos(5t)[A], 12=10cos(5t)[A] R1=4, R2=2, C1=C2=0.2, L1=L2=0.2| Find the node voltages V1 & V2? Solution: LI m C2 V1 ++ V2 IIRI C1 12 L2 22 R2 12 Draw the equivalent circuit in frequency domain: | Apply KCL at V1: Apply KCL at V2: V₁(t)= V2(t)=

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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An RTD forms one arm of a Wheatstone bridge, as shown in the figure below and the RTD is used to measure a constant temperature with the bridge operated in deflection mode. The bridge is balanced when the RTD temperature is at 0°C and the resistance R1 is set to 20 N. The RTD has a resistance of 20 2 at 0°C with an a = 0.0045°C-1. If the RTD is subjected to a temperature of 120°C and the output voltage from the bridge is 1.2 Volts, what is the input voltage? R₂ R₁ E₁ Hilllo R3 RTD RRTD
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A component requires 6.3-V across it with a current of 0.3 V. A second component requires 12.6-V at 0.15A. The two components are connected in series. What is the value of resistor that must be connected across the 12.6-V component to allow it to operate properly when in series with the 6.3-V component?
Problem Solving: Simplify and determine the equivalent circuit resistance below: R₁=20 E= 460 V R5= 10000 R₂ = 100 R3 = 100 R4 = 100 www R6=1500 Rg = 600 R7 = 200 R12=200 R8 = 400 R10 = 400 R₁1= 2000 R13 = 2000 R₁4 = 400 R15 = 1000 www R16 = 2000 R17 = 6000 R18 1040 R19 = 104 Hi guys! Here is something you can practice with. Simplify the circuit above. The final answer for this is 153/3 ohms. Good luck!