Example 6: Nodal Analysis In the following circuit: If 11=20cos(5t)[A], 12=10cos(5t)[A] R1=4, R2=2, C1=C2=0.2, L1=L2=0.2| Find the node voltages V1 & V2? Solution: LI m C2 V1 ++ V2 IIRI C1 12 L2 22 R2 12 Draw the equivalent circuit in frequency domain: | Apply KCL at V1: Apply KCL at V2: V₁(t)= V2(t)=

Example 6: Nodal Analysis In the following circuit: If 11=20cos(5t)[A], 12=10cos(5t)[A] R1=4, R2=2, C1=C2=0.2, L1=L2=0.2| Find the node voltages V1 & V2? Solution: LI m C2 V1 ++ V2 IIRI C1 12 L2 22 R2 12 Draw the equivalent circuit in frequency domain: | Apply KCL at V1: Apply KCL at V2: V₁(t)= V2(t)=

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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An RTD forms one arm of a Wheatstone bridge, as shown in the figure below and the RTD is used to measure a constant temperature with the bridge operated in deflection mode. The bridge is balanced when the RTD temperature is at 0°C and the resistance R1 is set to 20 N. The RTD has a resistance of 20 2 at 0°C with an a = 0.0045°C-1. If the RTD is subjected to a temperature of 120°C and the output voltage from the bridge is 1.2 Volts, what is the input voltage? R₂ R₁ E₁ Hilllo R3 RTD RRTD
Vc R3 R1 C2 С1 Vin R4 R6 /9441 C3 Vout 01 R2 T2 g160100555 - 987047944 R5 /9447 g160100555- 987047944 R73 C4 VEE Resistance and source g160100555 0100559 g160100555 - 987047944/ •A. ICI =? •b. IC2 =? g160100555- 9870479447 •C. are given below. VCEI =? VCE2 =? 87047944/ For transistors if hFE : •D. g16010055 70/9447 g160100555 R = 87047944 g16010055 87047944/ 100k R3 = 40k R4 = 5k R5 = 20k R6 = 5k R7 = 3k VCC = 15V VEE = -15V 79447 87047944 7944 g160100565 87047944 9441 87047944 9870479447
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