Five uL of a 10 to 1 dilution of a sample were added to 5 mL of Bradford reagent. The absorbance at 595 nm was 0.78 and, according to a standard curve, corresponds to 0.015 mg of protein on the x axis. What is the protein concentration of the original solution? Why?
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Five uL of a 10 to 1 dilution of a sample were added to 5 mL of Bradford reagent. The absorbance at 595 nm was 0.78 and, according to a standard curve, corresponds to 0.015 mg of protein on the x axis. What is the protein concentration of the original solution? Why?
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- The following data are obtained from three standard soltions using UV-Vis spectroscopy: What is the colar concentration (M) of an unknown solution with an absorbance of 0.180 at 255 nm? The unknown solution contains the same analyte as the standard solution does. The molar mass of the analyte is 188.65 g/mol a) 4.82x10-5b)1.9x10-3c)3.60x10-4d)1.9x10-5e)1.8x 10-4Blue Blue dye stock solution Absorbance at 630 nm Calibration curve Part 1: 0.1944 M 0.00697 y = 0.0682x A purple solution is prepared by mixing 5.00 mL of the blue dye solution with 6.75 mL of red dye solution. The calibration curve for each color is provided. Part 2 out of 3 (a) Determine the theoretical molar concentration of each dye in the mixture. [Blueltheoretical = 8.27 x 10-2 [Red] theoretical = 1.16 [Bluelexperimental [Redlexperimental " *10-1 M M x 10 (b) Using the absorbance and calibration curve for each dye, calculate the experimental molar concentration of each dye in the mixture. x 10 Red Red dye stock solution Absorbance at 500 nm Calibration curve 0.2015 M 0.00193 y = 0.0170x M M4. The total absorbance of a solution is the sum of the absorbances of all different materials present. AT = Aa + Ap + Ac .. etc. At 427 nm, the molar absorbtivity of Yellow #5 is 2.73×10°M-1-cm1. At 427 nm the molar absorptivity of Red 40 is 7.49x103 M-1.cm-1. Calculate the total absorbance of a solution in which the concentration of Yellow #5 = 2.00x10-5 M and the concentration of Red 40 = 4.80x10-5 M, when measured at 427 nm in a 1.00 cm cell.
- A student is analyzing a tap water sample for Mg by atomic absorption spectroscopy and has the following table of standards data: Conc. (ppm) Absorbance 0.20 0.40 0.70 1.0 0.131 0.255 0.498 0.641 She prepared 3 dilutions of her tap water (see below). Which dilution is the best to use? Tap water dilution factor Absorbance 1:4 1:20 1:50 1.196 0.390 0.119 the 1:4 dilution is best the the 1:50 dilution is best any value could be used with equal precision the 1:20 dilution is best"[FeSCN2+]eq is calculated using the formula: [FeSCN2+]eq = Aeq/Astd x [FeSCN2+]std where Aeq and Astd are the absorbance values for the equilibrium and standard sample respectively." I am confused about what Aeq and Astd mean. We did an experiment where we measured the absorption of this chemical formation and I got around 0.18. Is that one of the values?An unknown amount of a compound with a molecular mass of 270.57 g/mol is dissolved in a 10 mL volumetric flask. A 1.00 mL aliquot of this solution is transferred to a 25 mL volumetric flask, and enough water is added to dilute to the mark. The absorbance of this diluted solution at 355 nm is 0.495 in a 1.000 cm cuvette. The molar absorptivity for this compound at 355 nm is €355 = 6149 M-¹cm-¹. What is the concentration of the compound in the cuvette? concentration: What is the concentration of the compound in the 10 ml flask? concentration: How many milligrams of compound were used to make the 10 mL solution? mass: M M mg
- You are measuring the concentration of an unknown protein sample, and the absorbance at 595 nm (or A595) of your unknown is greater than that of the highest-concentration standard solution. It is not advisable to simply extrapolate the line of the standard curve to calculate the concentration of the unknown In this scenario, what would be the best strategy to measure the concentration of your unknown (instead of extrapolating from the standard curve)?A student weighed out 0.150 g of protein powder and dissolved it in 100 mL of water (Solution 1). The student then diluted this solution by transferring 1 mL into a 25 mL flask and diluting with water (Solution 2). Finally, 1 mL of that solution was transferred to a test tube and combined with 4 mL Bradford reagent. The absorbance of the solution in the test tube was 0.11. Assuming that the best fit linear line of the standard curve was y = 0.04144 x + 0.01521 (μ g mL), calculate the percent protein by mass in the original protein powder.Give a clear handwritten answer with explanation
- A standard 3 mL cuvette is two-thirds filled with a 1 in 5 dilution of 70 mM oxyhaemoglobin. The absorbance is measured at 580nm. A few drops of a live yeast suspension is added to the cuvette (without significantly changing the volume). The absorbance is remeasured at the same wavelength as above and is found to be 0.40, a decrease of 0.2 on the first measurement. What is the molar absorbance coefficient of the oxyhaemoglobin at 580 nm? (do not enter the units in the answer, 2 decimal places)(2) Adenine has a molar absorbance of 4 13.1 M-1cm-1 for 263 nm nucleic acid. What is the molar concentration of an acid solution that shows a permeability of 75% when 2 ml of it is placed in an absorption cell with a thickness of 1 cm?Suppose that a solution has an absorbance of 0.226 at a wavelength of 450 nm. If the concentration of the solution is 24 μM, what is the value of the molar absorptivity? The data were taken with a standard 1-cm cuvette.
