1. Draw all 4 positional isomers of ethylmethyl cyclohexane and its all possible stereoisomers, include R or S 2. Draw any stereoisomer (trans) of that conformer in a chair conformer, draw its flipped too
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1. Draw all 4 positional isomers of ethylmethyl cyclohexane and its all possible stereoisomers, include R or S
2. Draw any stereoisomer (trans) of that conformer in a chair conformer, draw its flipped too
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- Consider the Newman projection below. a. Draw a full Lewis structure of this molecule with R1=Me,R2=Et , and R3=iPr . b. Given the sizes of these R groups (R3R2R1) , does the Newman projection above show thelowest potential energy conformation of this bond? If not, draw a Newman projectionshowing the lowest P.E. conformation (sighting down this same bond). c. To draw a Newman projection in the lowest P.E. conformation, the following rule of thumbusually applies: Place the largest group on the front carbon anti to the largest group on theback carbon. Is your answer to the previous question consistent with this rule of thumb?Fill in the blanks: cis-1,3-Dimethylcyclohexane has two different chair conformations: one withboth methyl groups in __________ positions and one with both methyl groups in ____________ positions.Following is a planar hexagon representation for one isomer of 1,2,4-trimethylcyclohexane. Draw the alternative chair conformations of this compound and state which of the two is more stable.
- Following is a chair conformation of cyclohexane with the carbon atoms numbered 1 through 6. (a) Draw hydrogen atoms that are above the plane of the ring on carbons 1 and 2 and below the plane of the ring on carbon 4. (b) Which of these hydrogens are equatorial? Which are axial? (c) Draw the alternative chair conformation. Which hydrogens are equatorial? Which are axial? Which are above the plane of the ring? Which are below it?Q2. a) Draw the Newman projection of the most stable staggered conformation of 2-methylpentane, looking down the 3,4 bond. H3C c-CH2-CH2CH3 H3C´H b) The structure of cis-1-tert-butyl-3-methylcyclohexane is shown below. Draw both chair forms of this molecule, and circle the one you think is less stable. Me 't-BuF) Circle the letter corresponding to the relationship of each pair of structures: Identical (I), Conformers (C), Enantiomers (E) (enantiomers can have different conformations). FIRST... determine the absolute configuration of chiral centers. H | F OH C H OH E
- Solve this problemSee attached question.3. Draw both chair conformations of the six membered rings below and circle the lowest energy conformation. If they are equal in energy circle both structures. Draw out all of the H atoms on your chair structure and clearly indicate the directionality for all of the H and non-H substituents. a) b) c) d) Bri Ph,,, OH
- Monosubstituted cyclohexanes occur in two equilibrium conformations. In one conformation, the substituent is in an axial position. In the other conformation, the substituent is in the equatorial position. Complete the drawing of each chair conformation below and circle the more stable conformation.a. b. For the following two pairs of molecules, (1) Draw out the chair conformation for each molecule, flip the ring if it is possible. (2) Compare both molecules to circle out which one is more stable. (3) Identify their relationship as: constitutional isomer, conformational isomer, stereoisomer or identical. (4) Find all the chiral center on each molecule and label them. Br and ZX- and VS. H H H Br H H ∞, draw its and then in the 2. For (1R, 2S, 4R)-4-tert-buyl-1-ethyl-2-methylcyclohexane: draw its correct skeletal structure most stable conformer first showing the Hydrogens that are directly attached to the ring last stusture omit the hydrogens that are directly connected to the ring and draw the correct positions of the three alkyl groups in skeletal representation. Draw all bonds with the same length! 5. draw the correct skeletal structure here showing stereochemistry on this chair draw the most stable conformer including the H's directly attached to the ring on this chair draw only the alkyl groups, all bonds same lenght