Two gases X and Y are found in the atmosphere in only trace amounts because they decompose quickly. When exposed to ultraviolet light the half-life of X is 1.25 h, while that of Y is 15. min. Suppose an atmospheric scientist studying these decompositions fills a transparent 20.0 L flask with X and Y and exposes the flask to UV light. Initially, the partial pressure of X is 4.0 times greater than the partial pressure of Y. As both gases decompose, will the partial pressure of X ever fall below the partial pressure of Y? If you said yes, calculate the time it takes the partial pressure of X to fall below the partial pressure of Y. Round your answer to 2 significant digits. yes 号 no X ☐ min

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Two gases X and Y are found in the atmosphere in only trace amounts because they decompose quickly. When exposed to ultraviolet light the half-life of X is
1.25 h, while that of Y is 15. min. Suppose an atmospheric scientist studying these decompositions fills a transparent 20.0 L flask with X and Y and exposes
the flask to UV light. Initially, the partial pressure of X is 4.0 times greater than the partial pressure of Y.
As both gases decompose, will the partial pressure of X ever fall
below the partial pressure of Y?
If you said yes, calculate the time it takes the partial pressure of X
to fall below the partial pressure of Y. Round your answer to 2
significant digits.
yes
号
no
X
☐ min
Transcribed Image Text:Two gases X and Y are found in the atmosphere in only trace amounts because they decompose quickly. When exposed to ultraviolet light the half-life of X is 1.25 h, while that of Y is 15. min. Suppose an atmospheric scientist studying these decompositions fills a transparent 20.0 L flask with X and Y and exposes the flask to UV light. Initially, the partial pressure of X is 4.0 times greater than the partial pressure of Y. As both gases decompose, will the partial pressure of X ever fall below the partial pressure of Y? If you said yes, calculate the time it takes the partial pressure of X to fall below the partial pressure of Y. Round your answer to 2 significant digits. yes 号 no X ☐ min
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