Ezetimibe (C24H21 F2 NO3) is a drug used to treat high blood cholesterol. Which of the following statements is correct? a b с B d OH -N Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. A OH F Proton A is more acidic because when proton A is lost resonance is possible but this is not true when proton B dissociates. This creates a higher charge density that increases the entropy of water. X Your answer Proton A is more acidic because when proton A is lost resonance is possible but this is not true when proton B dissociates. This delocalization of charge creates a lower charge density that does not reduce the entropy of water as much Proton B is more acidic because when proton Bis lost resonance is possible but this is not true when proton A dissociates. This delocalization of charge creates a lower charge density that does not reduce the entropy of water as much Proton B is more acidic because when proton B is lost resonance is possible but this is not true when proton A dissociates. This creates a higher charge density that increases the entropy of water.

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Ezetimibe (C_{24}H_{21}F_2NO_3) is a drug used to treat high blood cholesterol. Which of the following statements is correct?

**Ezetimibe (C₂₄H₂₁F₂NO₃) Overview**

Ezetimibe is a medication used to treat high blood cholesterol. The molecular structure is provided, with key points highlighted for a deeper understanding.

**Molecular Diagram Explanation**

- The structure shown in the diagram includes two hydroxyl (OH) groups, labeled as A and B.
- The molecule consists of aromatic rings and various functional groups, with fluorine atoms on two separate rings.

**Quiz Question**

The question asks which statement is correct regarding the acidity of protons A or B on the ezetimibe molecule.

**Choices:**

a. Proton A is more acidic because when proton A is lost, resonance is possible, but this is not true when proton B dissociates. This creates a higher charge density that increases the entropy of water.
   
b. Proton A is more acidic because when proton A is lost, resonance is possible, but this is not true when proton B dissociates. This delocalization of charge creates a lower charge density that does not reduce the entropy of water as much.

c. Proton B is more acidic because when proton B is lost, resonance is possible, but this is not true when proton A dissociates. This delocalization of charge creates a lower charge density that does not reduce the entropy of water as much.

d. Proton B is more acidic because when proton B is lost, resonance is possible, but this is not true when proton A dissociates. This creates a higher charge density that increases the entropy of water.

**Selected Answer:**

- Option (a) was selected, but it was marked incorrect.

This question focuses on the concept of resonance stability and charge density, both of which influence acidity. Understanding these principles is vital for analyzing the chemical behavior of molecules like ezetimibe.
Transcribed Image Text:**Ezetimibe (C₂₄H₂₁F₂NO₃) Overview** Ezetimibe is a medication used to treat high blood cholesterol. The molecular structure is provided, with key points highlighted for a deeper understanding. **Molecular Diagram Explanation** - The structure shown in the diagram includes two hydroxyl (OH) groups, labeled as A and B. - The molecule consists of aromatic rings and various functional groups, with fluorine atoms on two separate rings. **Quiz Question** The question asks which statement is correct regarding the acidity of protons A or B on the ezetimibe molecule. **Choices:** a. Proton A is more acidic because when proton A is lost, resonance is possible, but this is not true when proton B dissociates. This creates a higher charge density that increases the entropy of water. b. Proton A is more acidic because when proton A is lost, resonance is possible, but this is not true when proton B dissociates. This delocalization of charge creates a lower charge density that does not reduce the entropy of water as much. c. Proton B is more acidic because when proton B is lost, resonance is possible, but this is not true when proton A dissociates. This delocalization of charge creates a lower charge density that does not reduce the entropy of water as much. d. Proton B is more acidic because when proton B is lost, resonance is possible, but this is not true when proton A dissociates. This creates a higher charge density that increases the entropy of water. **Selected Answer:** - Option (a) was selected, but it was marked incorrect. This question focuses on the concept of resonance stability and charge density, both of which influence acidity. Understanding these principles is vital for analyzing the chemical behavior of molecules like ezetimibe.
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