-&nhohčních_8_nuoho-3 CH₂ NHCH R¹ H :O: & NIGH- HOME I H₂C 0: R' H₂ 1. BrCN 2. H₂O :Ö-H H nichonich_8_om CH₂ CH₂-OH CH₂-S-CH3 Proteins can be cleaved specifically at the amide bond on the carboxyl side of methionine residues by reaction with cyanogen bromide (above). Cleavage proceeds by a four-stage mechanism. The third stage is an hydrolysis reaction that cleaves the peptide chain. At the end of this stage, the carboxyl group of the former methionine becomes part of a lactone (cyclic ester) ring. Draw curved arrows for the first step of this stage. Arrow-pushing Instructions NA →XT R H₂NCC
-&nhohčních_8_nuoho-3 CH₂ NHCH R¹ H :O: & NIGH- HOME I H₂C 0: R' H₂ 1. BrCN 2. H₂O :Ö-H H nichonich_8_om CH₂ CH₂-OH CH₂-S-CH3 Proteins can be cleaved specifically at the amide bond on the carboxyl side of methionine residues by reaction with cyanogen bromide (above). Cleavage proceeds by a four-stage mechanism. The third stage is an hydrolysis reaction that cleaves the peptide chain. At the end of this stage, the carboxyl group of the former methionine becomes part of a lactone (cyclic ester) ring. Draw curved arrows for the first step of this stage. Arrow-pushing Instructions NA →XT R H₂NCC
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:-NHCHÖNHCH
ਸਾਲ
R
&
C-NHCHC-
R'
CH₂
T
CH₂-S-CH3
Arrow-pushing Instructions
AOC XT
H :O:
1. BrCN
2. H₂O
NHCH-C
NHCH-C-NCHC-
H₂C 0: R'
H₂
NHCHCNI
R
:0-H
I
H
0=0
Proteins can be cleaved specifically at the amide bond on the carboxyl side of methionine residues by reaction with cyanogen bromide (above). Cleavage proceeds by a four-stage mechanism. The third stage is an hydrolysis reaction that cleaves the peptide
chain. At the end of this stage, the carboxyl group of the former methionine becomes part of a lactone (cyclic ester) ring. Draw curved arrows for the first step of this stage.
-NHCHÖNHCH-C-OH
CH₂
CH₂-OH
+
{}
H₂NCC-
R'
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