Give correct detailed Solution with explanation needed. Don't give Handwritten answer. don't use Ai for answering this Choose which structure is the general structure for a triacylglycerol.H₂C-OHHC O CH2(CH2) 13 CH3H2C O CH2(CH2) 15CH3H₂C-OHHC O CH2(CH2) 11 CH3H₂C-OHH₂C-OHHC-OHH₂C OH

A triacylglycerol, also known as a triglyceride, is a type of fat found in the blood and a major…

Answered: Choose which structure is the general…

Choose which structure is the general structure for a triacylglycerol. H₂C-OH HC O CH2(CH2) 13 CH3 H2C O CH2(CH2) 15CH3 H₂C-OH HC O CH2(CH2) 11 CH3 H₂C-OH H₂C-OH HC-OH H₂C OH

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Give correct detailed Solution with explanation needed. Don't give Handwritten answer. don't use Ai for answering this

Choose which structure is the general structure for a triacylglycerol.
H₂C-OH
HC O CH2(CH2) 13 CH3
H2C O CH2(CH2) 15CH3
H₂C-OH
HC O CH2(CH2) 11 CH3
H₂C-OH
H₂C-OH
HC-OH
H₂C OH

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0.1890 grams of an unknown organic acid containing 2 carboxylic groups was dissolved in about 50 mL of water in a 250 mL Erlenmeyer flask and titrated against 0.1000 M NaOH solution using bromothymol blue indicator. 34.62 mL of titrant was used to achieve end point. Calculate the molar mass of the unknown. Write answer with two decimal places only. No units please.
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Unknown Acid Acid name Acetic acid Group #5 Group #6 Group #7 Mean Standard Deviation % Error STATISTICAL ANALYSIS: Calculate mean values for molar mass, pKa, and Ka. Calculate % error and standard deviation: Unknown acid # 1 Molar Mass of unknown acid (calculated), g/mol Group #1 Group #2 Group #3 Group #4 Reaction Initial conc. / M: Change in conc. at equilibrium / M: Equilibrium conc. / M: Acetic acid | Molar Mass, g/mol: 60.05 | pka = 4.76 Accepted Values Molar mass, g/mol 60.05 Ka = Part II 1. Using initial molarity of acid and measured pH of the acid before titration, build a RICE table and calculate the Ka of the acid. You can use examples 1, 2 (pp. 3-4) from the Manual (posted on Canvas) Initial Molarity of [HA], M 0.219 Initial pH of Acid pka = HA(aq) + H₂O(1) [HA] -X 58.8 57.4 60.4 61.0 58.4 59.2 59.7 59.3 1.13 0.01 [HA] + X 台 pH: H3O+ (aq) = 0 +X 2. Use the Henderson-Hasselbauch equation to perform the same calculation. +X pka 4.76 Ka = pka 4.78 5.00 4.64 4.89 4.62 4.68 4.82…
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Give detailed Solution..show work..don't give Handwritten answer..don't use Ai for answering this
if an acidic functional group is added with a basic functional group, the resulting structure will always be a neutrally-charged molecule provide factual evidence that the statement is true