Exercise C. Charles's Law Using Charles's Law, Volume (V) = Constant Temperature (T) calculate the parameter that is missing in each row of the following table. Enter the appropriate form of Charles's law in the first column as shown in the table. Be sure to enter the appropriate units for each result and use the appropriate units when calculating the result. (23 pts, 2 per line, 5 for each word problem.) Equation T1 V1 T2 V2 V2 x T1 = 300. K 1.00 liter 600. K 2.00 liter T2 V1 300. K 2.00 liters 450. mL 50. C 2.00 liters 300. C 140. C 500. mL 2.00L 500. C 300. mL 773 K

Principles of Instrumental Analysis
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Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
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Exercise C. Charles's Law
Using Charles's Law, Volume (V)
= Constant
Temperature (T)
calculate the parameter that is missing in each row of the following table. Enter the
appropriate form of Charles's law in the first column as shown in the table. Be sure to
enter the appropriate units for each result and use the appropriate units when
calculating the result. (23 pts, 2 per line, 5 for each word problem.)
Equation
T1
V1
T2
V2
V2 x T1 =
300. K
1.00 liter
600. K
2.00 liter
T2
V1
300. K
2.00 liters
450. mL
50. C
2.00 liters
300. C
140. C
500. mL
2.00L
500. C
300. mL
773 K
Transcribed Image Text:Exercise C. Charles's Law Using Charles's Law, Volume (V) = Constant Temperature (T) calculate the parameter that is missing in each row of the following table. Enter the appropriate form of Charles's law in the first column as shown in the table. Be sure to enter the appropriate units for each result and use the appropriate units when calculating the result. (23 pts, 2 per line, 5 for each word problem.) Equation T1 V1 T2 V2 V2 x T1 = 300. K 1.00 liter 600. K 2.00 liter T2 V1 300. K 2.00 liters 450. mL 50. C 2.00 liters 300. C 140. C 500. mL 2.00L 500. C 300. mL 773 K
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