Please help me with the question below. A detailed explanation to aid in understanding is welcome. Calculate M, M, and the polydispersity index for a hypothetical polymer sample that contains equimo-lar amounts of polymer having molecular weights of 30,000, 60,000, and 90,000.

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Answered: Calculate M, M, and the polydispersity…

Macroscale and Microscale Organic Experiments

7th Edition

ISBN:9781305577190

Author:Kenneth L. Williamson, Katherine M. Masters

Publisher:Kenneth L. Williamson, Katherine M. Masters

Chapter4: Recrystallization

Section: Chapter Questions

Problem 1Q

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Calculate Mn, Mw and the polydispersity index for a hypothetical polymer sample that contains equimolar amounts of polymer having molecular weights of 30,000, 60,000, and 90,000.
If 9 grams of polymer A with molecular weight of 30,000 Dalton is mixed with 5 grams of polymer B with molecular weight of 50,000 Dalton, calculate the number average molecular weight, weight average molecular weight and polydispersity index of the polymer mixture.
Explaining the following polymer size fractions in a polymer sample: Fraction Molecular Weight Number of Chains 1 3,250 400 2 5,000 500 3 500,000 4 a. Calculate the number-average molecular weight of the polymer. b. Calculate the weight-average molecular weight of the polymer. c. Which average molecular weight did the 4 chains of molecular weight of 500,000 most significantly affect? why ? d. Calculate the polydispersity index (PI = (Mw/Mn) of the polymer.
2-pentanone has a retention index of 987 on a poly(ethylene glycol) column (also called Carbowax). (a) Between which two straight-chain hydrocarbons is 2-pentanone eluted? (b) An unretained solute is eluted from a certain column in 1.80 min. Decane (C10H22) is eluted in 15.63 min and undecane (C11H24) is eluted in 17.22 min. What is the retention time of a compound whose retention index is 1 050?
Explaining the following polymer size fractions in a polymer sample: Fraction Molecular Weight Number of Chains 1 3,250 400 5,000 500 3 500,000 4 а. Calculate the number-average molecular weight of the polymer. b. Calculate the weight-average molecular weight of the polymer. c. Which average molecular weight did the 4 chains of molecular weight of 500,000 most significantly affect? why ? d. Calculate the polydispersity index (PI = (Mw/Mn) of the polymer.
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Why does a solid form at the interface of the two solutions? PROCEDURESynthesis of NylonIn a small beaker dissolve ~ 0.5 mL of sebacoyl chloride in 12 mL of ether. In a smalltest tube get ~ 6 mL (~1/4 of a 6 “ test tube) of 1,6-diaminohexane solution in water.In order to form the good polymer fibers, it is best to not mix the solutions. Youshould try to layer one solution on top of the other. First pour the 1,6-diaminohexanesolution into a 100 mL beaker. Then slowly pour the sebacoyl chloride down the sideof the tilted beaker with minimal mixing. At this point you should see two distinctlayers with a white film at the interface. Hook the nylon which forms at the interfacewith a straightened paper clip and pull slowly straight up as high as possible. Thenwrap it around your large beaker and then continue to wind the polymer around tillthe reaction is complete. Rinse your polymer in DI water to remove any salts or acidthat may be present.Weigh your product and characterize it by…
22-30. (a) The mean free path is the average distance a molecule travels before colliding with another molecule. The mean free path, A, is given by A = kT/(V20P), where k is Boltzmann’s constant, T is temperature (K), P is pressure (Pa), and o is the collision cross section. For a molecule with a diameter d, the col- lision cross section is nd. The collision cross section is the area swept out by the molecule within which it will strike any other molecule it encounters. The magnetic sector mass spectrometer is maintained at a pressure of ~103 Pa so that ions do not collide with (and deflect) one another as they travel through the mass analyzer. What is the mean free path of a molecule with a diam- eter of 1 nm at 300 K in the mass analyzer?
Classify the descriptions based on whether they apply to ion‑exchange, size‑exclusion, or both types of chromatography columns. - Proteins move through the column at rates determined by their net charge. - The gel bed will contain polymer beads with charged functional groups. - Proteins move through the column at rates determined by their size. - The gel bed will contain porous polymer beads. - The properties of the proteins affect the rate at which they migrate. - Proteins are separated based on differences in their amino acid sequences.
Aliquots of a 0.5 mg/mL standard of BSA were used to construct a standard curve for the Bradford protein assay. The tubes contained the following amounts of the BSA solution: 0, 20, 40, 60, 80, 100 μL. Each sample then had water added to make the final volume 100 μL. The corresponding absorbencies after adding Bradford reagent were the following: 0, 0.05, 0.09, 0.14, 0.19, and 0.22. If you took 20 μL of an unknown and added 80 μL of water, mixed, took 10 μL of the mixture and 90 μL of water and added the Bradford reagent and saw an absorbance of 0.08, what was the protein concentration of the undiluted unknown to one decimal place?
4mL of diluted protein solution was prepared by mixing 200uL of the protein solution with 3.8mL of distilled water. 100uL of this diluted was then mixed with 900uL of Lysozyme solution. Lysozyme activity was measured at 450nm and gave a reading of -0.080 (Abs/min). Calculate the concentration of lysozyme activity in units of abs/min/mL.
- A 50 g sample of poly(hexamethylene adipamide) is found to contain 5.10 x10-3 mol of carboxyl groups by both titration with base and infrared spectroscopy. Calculate the number average molecular weight of the polymer.

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Calculate M, M, and the polydispersity index for a hypothetical polymer sample that contains equimo- lar amounts of polymer having molecular weights of 30,000, 60,000, and 90,000.