Calculate M, M, and the polydispersity index for a hypothetical polymer sample that contains equimo- lar amounts of polymer having molecular weights of 30,000, 60,000, and 90,000.
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- If 9 grams of polymer A with molecular weight of 30,000 Dalton is mixed with 5 grams of polymer B with molecular weight of 50,000 Dalton, calculate the number average molecular weight, weight average molecular weight and polydispersity index of the polymer mixture.2-pentanone has a retention index of 987 on a poly(ethylene glycol) column (also called Carbowax). (a) Between which two straight-chain hydrocarbons is 2-pentanone eluted? (b) An unretained solute is eluted from a certain column in 1.80 min. Decane (C10H22) is eluted in 15.63 min and undecane (C11H24) is eluted in 17.22 min. What is the retention time of a compound whose retention index is 1 050?Explaining the following polymer size fractions in a polymer sample: Fraction Molecular Weight Number of Chains 1 3,250 400 5,000 500 3 500,000 4 а. Calculate the number-average molecular weight of the polymer. b. Calculate the weight-average molecular weight of the polymer. c. Which average molecular weight did the 4 chains of molecular weight of 500,000 most significantly affect? why ? d. Calculate the polydispersity index (PI = (Mw/Mn) of the polymer.
- Give typed solutionClassify the descriptions based on whether they apply to ion‑exchange, size‑exclusion, or both types of chromatography columns. - Proteins move through the column at rates determined by their net charge. - The gel bed will contain polymer beads with charged functional groups. - Proteins move through the column at rates determined by their size. - The gel bed will contain porous polymer beads. - The properties of the proteins affect the rate at which they migrate. - Proteins are separated based on differences in their amino acid sequences.Aliquots of a 0.5 mg/mL standard of BSA were used to construct a standard curve for the Bradford protein assay. The tubes contained the following amounts of the BSA solution: 0, 20, 40, 60, 80, 100 μL. Each sample then had water added to make the final volume 100 μL. The corresponding absorbencies after adding Bradford reagent were the following: 0, 0.05, 0.09, 0.14, 0.19, and 0.22. If you took 20 μL of an unknown and added 80 μL of water, mixed, took 10 μL of the mixture and 90 μL of water and added the Bradford reagent and saw an absorbance of 0.08, what was the protein concentration of the undiluted unknown to one decimal place?
- 4mL of diluted protein solution was prepared by mixing 200uL of the protein solution with 3.8mL of distilled water. 100uL of this diluted was then mixed with 900uL of Lysozyme solution. Lysozyme activity was measured at 450nm and gave a reading of -0.080 (Abs/min). Calculate the concentration of lysozyme activity in units of abs/min/mL.- A 50 g sample of poly(hexamethylene adipamide) is found to contain 5.10 x10-3 mol of carboxyl groups by both titration with base and infrared spectroscopy. Calculate the number average molecular weight of the polymer.About a decade ago, it was more common to use peptide mass mapping to identify a protein cut from a gel. Peptide mass mapping involves digesting the protein with trypsin and then measuring the peptide masses using MALDI-TOF mass spectrometry. The more superior method of identifying a protein from a gel is to digest the protein with trypsin and then use liquid chromatography to separate the peptides. The separated peptides are then electrosprayed into a tandem mass spectrometer. The MS-MS data is uploaded into a database such as MASCOT for protein identification. Explain why the LC-MS-MS method is superior to the peptide mass mapping method.
- 6.) An unknown polymer sample is fractionated, and the following molar fractions are obtained. Calculate Mn and Mw and the dispersity. Fill out the table to show your work. Fraction # 1 2 3 4 5 6 n₁ (mol) 0.004 0.011 0.009 0.003 0.017 0.008 M; (g/mol) 10,400 12,080 13,950 16,700 18,150 20,000 n¡Mi n;M;²How would you make 2.0 L of electrotransfer buffer for transferring the proteins from a gel onto nitrocellulose? Its composition is the following in water: 25 mM Tris (this is a solid; MW = 121) 192 mM Glycine (this is a solid; MW = 75.07) 20.0 % Methanol (you have 100% from the stockroom)Dr. Alghe has just performed a restriction digest on DNA she extracted from her samples. She must now run her DNA out on a gel to separate the fragments based on size. To do this she must prepare a 1.2% agarose gel, where the percentage is determined as mass/vol. How many grams of agarose must she add to 200 mL of buffer in order to arrive at the correct percentage?