Example 6.23 from book: The life, in thousands of miles, of a certain type of electronic control for locomotives has an approximately lognormal distribution with μ = 5.149 and σ = 0.737. Find the 5th percentile of the life of such an electronic control. From Table A.3, we know that P(Z < -1.645) = 0.05. Denote by X the life of such an electronic control. Since ln(X) has a normal distribution with mean 5.149 and σ = 0.737, the 5th percentile of X can be calculated as u = |ln(x) = µ+Zo ln(x) = 5.149 + (0.737) (-1.645) = 3.937. In(x) = log(x) x = ex = e =3.937 ≈51.261 9/10

College Algebra
1st Edition
ISBN:9781938168383
Author:Jay Abramson
Publisher:Jay Abramson
Chapter6: Exponential And Logarithmic Functions
Section6.8: Fitting Exponential Models To Data
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Example 6.23 from book:
The life, in thousands of miles, of a certain type of electronic control for locomotives
has an approximately lognormal distribution with μ = 5.149 and σ = 0.737. Find
the 5th percentile of the life of such an electronic control.
From Table A.3, we know that P(Z < -1.645) = 0.05. Denote by X the life
of such an electronic control. Since ln(X) has a normal distribution with mean
5.149 and σ = 0.737, the 5th percentile of X can be calculated as
u =
|ln(x) = µ+Zo ln(x) = 5.149 + (0.737) (-1.645) = 3.937.
In(x) = log(x)
x = ex = e
=3.937
≈51.261
9/10
Transcribed Image Text:Example 6.23 from book: The life, in thousands of miles, of a certain type of electronic control for locomotives has an approximately lognormal distribution with μ = 5.149 and σ = 0.737. Find the 5th percentile of the life of such an electronic control. From Table A.3, we know that P(Z < -1.645) = 0.05. Denote by X the life of such an electronic control. Since ln(X) has a normal distribution with mean 5.149 and σ = 0.737, the 5th percentile of X can be calculated as u = |ln(x) = µ+Zo ln(x) = 5.149 + (0.737) (-1.645) = 3.937. In(x) = log(x) x = ex = e =3.937 ≈51.261 9/10
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