Exercise 4.4.9 (Lipschitz Functions). A function f: A → R is called Lipschitz if there exists a bound M > 0 such that f(x) f(y)\ ≤ M x-y for all x + y = A. Geometrically speaking, a function f is Lipschitz if there is a uniform bound on the magnitude of the slopes of lines drawn through any two points on the graph of f. (a) Show that if f: A → R is Lipschitz, then it is uniformly continuous on A. (b) Is the converse statement true? Are all uniformly continuous functions necessarily Lipschitz?
Exercise 4.4.9 (Lipschitz Functions). A function f: A → R is called Lipschitz if there exists a bound M > 0 such that f(x) f(y)\ ≤ M x-y for all x + y = A. Geometrically speaking, a function f is Lipschitz if there is a uniform bound on the magnitude of the slopes of lines drawn through any two points on the graph of f. (a) Show that if f: A → R is Lipschitz, then it is uniformly continuous on A. (b) Is the converse statement true? Are all uniformly continuous functions necessarily Lipschitz?
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.1: Inverse Functions
Problem 56E
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Transcribed Image Text:Exercise 4.4.9 (Lipschitz Functions). A function f: A → R is called
Lipschitz if there exists a bound M > 0 such that
f(x) f(y)\
≤ M
x-y
for all x + y = A. Geometrically speaking, a function f is Lipschitz if there is a
uniform bound on the magnitude of the slopes of lines drawn through any two
points on the graph of f.
(a) Show that if f: A → R is Lipschitz, then it is uniformly continuous on A.
(b) Is the converse statement true? Are all uniformly continuous functions
necessarily Lipschitz?
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