The correct answer is: 3 39 9 10 5 10 10 7 000 10 P = 01300 1 1 00 10 10 S 90 181 63 181 126 905 14 905 Proportion of games won by Doug = 91/181

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter11: Rational And Irrational Numbers
Section11.6: The Pythagorean Theorem
Problem 10ST
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Bob and Doug play a lot of Ping-Pong, but Doug is a much better player, and wins 60% of their games.

To make up for this, if Doug wins a game he will spot Bob five points in their next game. If Doug wins again he will spot Bob ten points the next game, and if he still wins the next game he will spot him fifteen points, and continue to spot him fifteen points as long as he keeps winning. Whenever Bob wins a game he goes back to playing the next game with no advantage.

It turns out that with a five-point advantage Bob wins 60% of the time; he wins 70% of the time with a ten-point advantage and 90% of the time with a fifteen-point advantage.

Model this situation as a Markov chain using the number of consecutive games won by Doug as the states. There should be four states representing zero, one, two, and three or more consecutive games won by Doug. Find the transition matrix of this system, the steady-state vector for the system, and determine the proportion of games that Doug will win in the long run under these conditions.

(here's a sample of what the answer would look like)

The correct answer is:
3 39 9
10 5 10 10
7
000
10
P =
01300
1 1
00
10 10
S
90
181
63
181
126
905
14
905
Proportion of games won by Doug = 91/181
Transcribed Image Text:The correct answer is: 3 39 9 10 5 10 10 7 000 10 P = 01300 1 1 00 10 10 S 90 181 63 181 126 905 14 905 Proportion of games won by Doug = 91/181
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