Draw the per-unit impedance diagram of the network shown in Fig. 1, calculated to a common base of 100 MVA. Determine: (i) (ii) The rms fault current (in kA) and the fault level (in MVA) for a three-phase symmetrical sh circuit fault at bus no. 6. The rms fault current (in kA) and the fault level (in MVA) for a three-phase symmetrical sh circuit fault at bus no. 2. T₁ 132kV/33kV 80 MVA X-0.12 pu bus 2 Load 30 km X-0.4 02/km bus 4 T₁ 33kV/11kV 12 MVA X-0.08 pu bus 5 Load bus 1 1800 MVA Fault Level T₂ 132kV/33kV 80 MVA X-0.12 pu Load Load 12 km X-0.24 0/km T₁ 132kV/11kV 60 MVA X-0.1 pu bus 3 20 km X-0.24 02/km Load bus 6
Draw the per-unit impedance diagram of the network shown in Fig. 1, calculated to a common base of 100 MVA. Determine: (i) (ii) The rms fault current (in kA) and the fault level (in MVA) for a three-phase symmetrical sh circuit fault at bus no. 6. The rms fault current (in kA) and the fault level (in MVA) for a three-phase symmetrical sh circuit fault at bus no. 2. T₁ 132kV/33kV 80 MVA X-0.12 pu bus 2 Load 30 km X-0.4 02/km bus 4 T₁ 33kV/11kV 12 MVA X-0.08 pu bus 5 Load bus 1 1800 MVA Fault Level T₂ 132kV/33kV 80 MVA X-0.12 pu Load Load 12 km X-0.24 0/km T₁ 132kV/11kV 60 MVA X-0.1 pu bus 3 20 km X-0.24 02/km Load bus 6
Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Question
![Draw the per-unit impedance diagram of the network shown in Fig. 1, calculated to a common base of
100 MVA.
Determine:
(i)
(ii)
The rms fault current (in kA) and the fault level (in MVA) for a three-phase symmetrical short-
circuit fault at bus no. 6.
The rms fault current (in kA) and the fault level (in MVA) for a three-phase symmetrical short-
circuit fault at bus no. 2.
T₁
132kV/33kV
80 MVA
X-0.12 pu
bus 2
Load
30 km
X+0,4 82/km
bus 4
T₁
33kV/11kV
12 MVA
X-0.08 pu
bus 5
Load V
bus 1
1800 MVA Fault Level
T₂
132kV/33kV
80 MVA
X-0.12 pu
Load
Load
12 km
X 0.24 52/km
Figure 1
T₁
132kV/11kV
60 MVA
X-0.1 pu
bus 3
20 km
X-0.24 02/km
Load
bus 6](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3c1026a2-02ce-4304-90fa-ce2f48f45210%2F2875df54-82eb-4dfb-a770-48318ff2f961%2Fpfoi8q_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Draw the per-unit impedance diagram of the network shown in Fig. 1, calculated to a common base of
100 MVA.
Determine:
(i)
(ii)
The rms fault current (in kA) and the fault level (in MVA) for a three-phase symmetrical short-
circuit fault at bus no. 6.
The rms fault current (in kA) and the fault level (in MVA) for a three-phase symmetrical short-
circuit fault at bus no. 2.
T₁
132kV/33kV
80 MVA
X-0.12 pu
bus 2
Load
30 km
X+0,4 82/km
bus 4
T₁
33kV/11kV
12 MVA
X-0.08 pu
bus 5
Load V
bus 1
1800 MVA Fault Level
T₂
132kV/33kV
80 MVA
X-0.12 pu
Load
Load
12 km
X 0.24 52/km
Figure 1
T₁
132kV/11kV
60 MVA
X-0.1 pu
bus 3
20 km
X-0.24 02/km
Load
bus 6
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