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Q2) The single-line diagram of a three-phase power system is shown in the figure below. The inductor connected to Generator 3 neutral has a reactance of 0.05 per unit using generator 3 ratings as base. Use a 1000-MVA, 765-kV base in the zone of line 1-2. Equipment ratings are given as follows: Synchronous generators: G1 1000 MVA 15 kV G2 1000 MVA 15 kV G3 500 MVA G4 750 MVA Transformers: 13.8 kV 13.8 kV T1 1000 MVA T2 1000 MVA T3 500 MVA T4 750 MVA Transmission lines: 1-2 765 kV 1-3 765 kV 2-3 765 kV 15 kV A/765 kV Y 15 kV A/765 kV Y 15 kV Y/765 kV Y 15 kV Y/765 kV Y X=X₂ = 0.18, Xo = 0.07 per unit X=X₂=0.20, Xo = 0.10 per unit X = X₂ = 0.15, Xo = 0.05 per unit X=0.30, X₂ = 0.40, Xo = 0.10 per unit X₁ = 50 2, Xo = 150 2 X₁ = 40 2, Xo = 100 2 X = 40 Ω, Χ = 100 Ω X = 0.10 per unit X = 0.10 per unit X = 0.12 per unit X = 0.11 per unit

Q2) The single-line diagram of a three-phase power system is shown in the figure below. The inductor connected to Generator 3 neutral has a reactance of 0.05 per unit using generator 3 ratings as base. Use a 1000-MVA, 765-kV base in the zone of line 1-2. Equipment ratings are given as follows: Synchronous generators: G1 1000 MVA 15 kV G2 1000 MVA 15 kV G3 500 MVA G4 750 MVA Transformers: 13.8 kV 13.8 kV T1 1000 MVA T2 1000 MVA T3 500 MVA T4 750 MVA Transmission lines: 1-2 765 kV 1-3 765 kV 2-3 765 kV 15 kV A/765 kV Y 15 kV A/765 kV Y 15 kV Y/765 kV Y 15 kV Y/765 kV Y X=X₂ = 0.18, Xo = 0.07 per unit X=X₂=0.20, Xo = 0.10 per unit X = X₂ = 0.15, Xo = 0.05 per unit X=0.30, X₂ = 0.40, Xo = 0.10 per unit X₁ = 50 2, Xo = 150 2 X₁ = 40 2, Xo = 100 2 X = 40 Ω, Χ = 100 Ω X = 0.10 per unit X = 0.10 per unit X = 0.12 per unit X = 0.11 per unit

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Q2) The single-line diagram of a three-phase power system is shown in the figure below. The inductor connected to Generator 3 neutral has a reactance of 0.05 per unit using generator 3 ratings as base. Use a 1000-MVA, 765-kV base in the zone of line 1-2. Equipment ratings are given as follows: Synchronous generators: G1 1000 MVA 15 kV G2 1000 MVA 15 kV G3 500 MVA 13.8 kV G4 750 MVA 13.8 kV Transformers: T1 1000 MVA T2 1000 MVA T3 500 MVA T4 750 MVA Transmission lines: 1-2 765 kV 1-3 765 kV 2-3 765 kV 15 kV A/765 kV Y 15 kV A/765 kV Y 15 kV Y/765 kV Y 15 kV Y/765 kV Y X = X₂ = 0.18, Xo = 0.07 per unit X=X₂=0.20, Xo = 0.10 per unit X=X₂ = 0.15, Xo = 0.05 per unit X=0.30, X₂ = 0.40, Xo = 0.10 per unit X₁ = 50 2, Xo = 150 2 X₁ = 40 2, Xo = 100 2 X₁ = 40 2, Xo = 100 2 at Line 1-3 Line 1-2 2 X = 0.10 per unit X = 0.10 per unit X = 0.12 per unit X = 0.11 per unit Line 2-3 3 youtly
Transcribed Image Text:Q2) The single-line diagram of a three-phase power system is shown in the figure below. The inductor connected to Generator 3 neutral has a reactance of 0.05 per unit using generator 3 ratings as base. Use a 1000-MVA, 765-kV base in the zone of line 1-2. Equipment ratings are given as follows: Synchronous generators: G1 1000 MVA 15 kV G2 1000 MVA 15 kV G3 500 MVA 13.8 kV G4 750 MVA 13.8 kV Transformers: T1 1000 MVA T2 1000 MVA T3 500 MVA T4 750 MVA Transmission lines: 1-2 765 kV 1-3 765 kV 2-3 765 kV 15 kV A/765 kV Y 15 kV A/765 kV Y 15 kV Y/765 kV Y 15 kV Y/765 kV Y X = X₂ = 0.18, Xo = 0.07 per unit X=X₂=0.20, Xo = 0.10 per unit X=X₂ = 0.15, Xo = 0.05 per unit X=0.30, X₂ = 0.40, Xo = 0.10 per unit X₁ = 50 2, Xo = 150 2 X₁ = 40 2, Xo = 100 2 X₁ = 40 2, Xo = 100 2 at Line 1-3 Line 1-2 2 X = 0.10 per unit X = 0.10 per unit X = 0.12 per unit X = 0.11 per unit Line 2-3 3 youtly
a) Draw the zero, positive, and negative sequence reactance diagrams. b) For a fault at bus 3, determine the thevenin equivalent of each sequence network as viewed from the fault bus. Prefault voltage is 1 per unit. (use the wye-delta transformation) A с B ZAB= ZBC ZCA = ZCA ZAZB+ Z₂Zc+ ZcZA Zc ZAZB+ ZBZc+ ZcZA ZA ZAZB+ ZBZc+ZCZA ZB B Z₁ = Z₁ = Zc = ZABZCA ZAB + ZBC + ZCA ZABZBC ZAB + ZBC + ZCA ZCAZBC ZAB + ZBC + ZCA c) Determine the subtransient fault current in per unit and in kA, as well as the per unit line-to-ground voltages at the fault bus for a bolted single line-to- ground fault at bus 3.
Transcribed Image Text:a) Draw the zero, positive, and negative sequence reactance diagrams. b) For a fault at bus 3, determine the thevenin equivalent of each sequence network as viewed from the fault bus. Prefault voltage is 1 per unit. (use the wye-delta transformation) A с B ZAB= ZBC ZCA = ZCA ZAZB+ Z₂Zc+ ZcZA Zc ZAZB+ ZBZc+ ZcZA ZA ZAZB+ ZBZc+ZCZA ZB B Z₁ = Z₁ = Zc = ZABZCA ZAB + ZBC + ZCA ZABZBC ZAB + ZBC + ZCA ZCAZBC ZAB + ZBC + ZCA c) Determine the subtransient fault current in per unit and in kA, as well as the per unit line-to-ground voltages at the fault bus for a bolted single line-to- ground fault at bus 3.
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